overloading

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed last year . Is Method Overloading considered part of polymorphism? 回答1: "Polymorphism" is just a word and doesn't have a globally agreed-upon, precise definition. You will not be enlightened by either a "yes" or a "no" answer to your question because the difference will be in the chosen

问题 This question already has answers here : Should you declare methods using overloads or optional parameters in C# 4.0? (13 answers) Closed 6 years ago . which one is better? at a glance optional parameter seems better (less code, less XML documentation, etc), but why do most MSDN library classes use overloading instead of optional parameters? Is there any special thing you have to take note when you choose to use optional parameter (or overloading)? 回答1: One good use case for 'Optional

问题 Am I able to overload the print function and call the normal function from within? What I want to do is after a specific line I want print to call my print which will call the normal print and write a copy to file. Also I don't know how to overload print . I don't know how to do variable length arguments. I'll look it up soon but overload print python just told me I can't overload print in 2.x which is what I am using. 回答1: For those reviewing the previously dated answers, as of version

问题 This question already has answers here : Function with same name but different signature in derived class (2 answers) Closed 5 years ago . Given the following example, why do I have to explicitly use the statement b->A::DoSomething() rather than just b->DoSomething() ? Shouldn't the compiler's overload resolution figure out which method I'm talking about? I'm using Microsoft VS 2005. (Note: using virtual doesn't help in this case.) class A { public: int DoSomething() {return 0;}; }; class B :

问题 Section 6.3 of the TypeScript language spec talks about function overloading and gives concrete examples on how to implement this. However if I try something like this: export class LayerFactory { constructor (public styleFactory: Symbology.StyleFactory) { } createFeatureLayer (userContext : Model.UserContext, mapWrapperObj : MapWrapperBase) : any { throw "not implemented"; } createFeatureLayer(layerName : string, style : any) : any { throw "not implemented"; } } I get a compiler error

问题 In PHP, what do you mean by function overloading and function overriding. and what is the difference between both of them? couldn't figure out what is the difference between them. 回答1: Overloading is defining functions that have similar signatures, yet have different parameters. Overriding is only pertinent to derived classes, where the parent class has defined a method and the derived class wishes to override that method. In PHP, you can only overload methods using the magic method __call.

问题 From How to override python builtins with an import statement I obtained the following code: from __future__ import print_function def print(*args, **kwargs): . . some intervening logic . return __builtins__.print(*args, **kwargs) This code works fine, but has module scope. That is, if there are print statements within this file they work as expected, going through the print() function as defined. However, importing it (from foo import *) has no effect within the module that imported it. If I

问题 I'm doing my Java class exercises. I have this code which contains an overloaded method: class A { // Overloaded method public void f(int n, float x) { System.out.println("f(int n, float x) n = " + n + " x = " + x); } private void f(long q, double y) { System.out.println("f(long q, double y) q = " + q + " y = " + y); } public void f(double y1, double y2) { System.out.println("f(double y1, double y2) y1 = " + y1 + " y2 = " + y2); } public void g() { int n = 1; long q = 12; float x = 1.5f;

问题 I have a long standing doubt. Could someone please tell me whether method overloading is a form of polymorphism or is it something completely different? 回答1: Method overloading is just a syntax sugar allowing you to have methods with same name but different arguments. It has nothing to do with polymorphism. Method overloading is typically used to define two methods accepting different arguments, e.g.: public void println(boolean x) //... public void println(char x) //... or to skip certain

问题 Suppose I define some function f with the following 3 signatures in C++: void f(int x) {} void f(int& x) {} void f(const int& x) {} These functions can coexist since they differ in the types of the arguments. Now I run the following code: int main { int i = 3; const int ci = 4; f(3); f(i); f(ci); } How does C++ know which overloaded function to call in this specific case ? What are rules in general ( best practice ? ) for writing overloaded functions in C++ as to avoid ambiguity. Does the