order-of-execution

When does a java object become non-null during construction?

由 本秂侑毒 提交于 2019-12-03 01:50:35
Say you are creating a java object like so: SomeClass someObject = null; someObject = new SomeClass(); At what point does the someObject become non-null? Is it before the SomeClass() constructor runs or after? To clarify a little, say if another thread was to check if someObject was null while the SomeClass() constructor was halfway through completion, would it be null or non-null? Also, what would be the difference if someObject was created like so: SomeClass someObject = new SomeClass(); Would someObject ever be null? If another thread were to check the someObject variable "during"

Why do these snippets of JavaScript behave differently even though they both encounter an error?

由 拥有回忆 提交于 2019-12-02 16:27:04
var a = {} var b = {} try{ a.x.y = b.e = 1 // Uncaught TypeError: Cannot set property 'y' of undefined } catch(err) { console.error(err); } console.log(b.e) // 1 var a = {} var b = {} try { a.x.y.z = b.e = 1 // Uncaught TypeError: Cannot read property 'y' of undefined } catch(err) { console.error(err); } console.log(b.e) // undefined Actually, if you read the error message properly, case 1 and case 2 throw different errors. Case a.x.y : Cannot set property 'y' of undefined Case a.x.y.z : Cannot read property 'y' of undefined I guess it's best to describe it by step-by-step execution in easy

Virtual base classes order of creation

由 狂风中的少年 提交于 2019-12-01 05:18:42
问题 I have the following problem: struct A1 { A1() { std::cout << "A1, "; } }; struct A2 { A2() { std::cout << "A2, "; } }; struct AA1 : virtual A1, A2 { AA1() { std::cout << "AA1, "; } }; struct AA2 : A1, virtual A2 { AA2(){ std::cout << "AA2, "; } }; struct B : AA1, virtual AA2 { B() { std::cout << "B "; } }; int main() { B b; } When you run this code, the answer is: A1 A2 A1 AA2 A2 AA1 B I want to understand where is the first A1 created. I know the rule that the virtual classes are called

Do external stylesheets get loaded before the HTML?

由 不想你离开。 提交于 2019-12-01 02:27:49
If I have external stylesheets being included in the <head></head> section of my HTML page, will they be loaded before the HTML and immediately applied upon rendering? Let me present my specific use case. External styles.css file: form label { display: none; } Page containing form: <head> <link rel="stylesheet" href="styles.css" type="text/css" /> </head> <form action="process.php" method="post"> <label for="name">Name</label> <input type="text" id="name" name="name" /> </form> Can I be confident that the labels will be invisible upon page load (no flickering due to CSS downloading)? Otherwise

When exactly is an initializer temporary destroyed?

由 会有一股神秘感。 提交于 2019-11-30 13:44:04
问题 I constructed this experiment today, after answering some question struct A { bool &b; A(bool &b):b(b) { } ~A() { std::cout << b; } bool yield() { return true; } }; bool b = A(b).yield(); int main() { } b has value false (resulting from zero initialization) before setting it to true by the dynamic initialization. If the temporary is destroyed before initialization of b finished, we will print false , otherwise true . The spec says that the temporary is destroyed at the end of the full

Order property of ActionFilter, from lowest to greatest or vice versa?

由 不想你离开。 提交于 2019-11-30 06:54:00
I defined two ActionFilters: [DefaultResources(Order = 2)] [RenderTemplate(Order = 1)] And to my surprise DefaultResources is executed BEFORE RenderTemplate. But according to MSDN documentation it should work vice versa: [Filter1(Order = 2)] [Filter2(Order = 3)] [Filter3(Order = 1)] public void Index() { View("Index"); } In this example, action filters would execute in the following order: Filter3, Filter1, and then Filter2. I'm using .NET 4. And comparing by method OnActionExecuted. Am I missing something? This is the answer I was looking for. Order of OnActionExecuted is reversed order of

jQuery: Enforce order of execution of document.ready() calls

由 别说谁变了你拦得住时间么 提交于 2019-11-28 11:52:55
I'm working on a codebase with multiple blocks of code setting some behavior on document.ready() (jQuery). Is there a way to enforce that one specific block is called before any of the others? Background: I need to detect JS errors in an automated testing environment, so I need the code that starts logging JS errors to execute before any other JS code executes. document.ready() callbacks are called in the order they were registered. If you register your testing callback first, it will be called first. Also if your testing code does not actually need to manipulate the DOM, then you may be able

Reading files in a particular order in python

由 假如想象 提交于 2019-11-27 19:42:07
Lets say I have three files in a folder: file9.txt, file10.txt and file11.txt and i want to read them in this particular order. Can anyone help me with this? Right now I am using the code import glob, os for infile in glob.glob(os.path.join( '*.txt')): print "Current File Being Processed is: " + infile and it reads first file10.txt then file11.txt and then file9.txt. Can someone help me how to get the right order? Files on the filesystem are not sorted. You can sort the resulting filenames yourself using the sorted() function : for infile in sorted(glob.glob('*.txt')): print "Current File

Java Printing a Binary Tree using Level-Order in a Specific Format

由 给你一囗甜甜゛ 提交于 2019-11-27 18:24:32
Okay, I have read through all the other related questions and cannot find one that helps with java. I get the general idea from deciphering what i can in other languages; but i am yet to figure it out. Problem: I would like to level sort (which i have working using recursion) and print it out in the general shape of a tree. So say i have this: 1 / \ 2 3 / / \ 4 5 6 My code prints out the level order like this: 1 2 3 4 5 6 I want to print it out like this: 1 2 3 4 5 6 Now before you give me a moral speech about doing my work... I have already finished my AP Comp Sci project and got curious

jQuery: Enforce order of execution of document.ready() calls

由 末鹿安然 提交于 2019-11-27 06:34:01
问题 I'm working on a codebase with multiple blocks of code setting some behavior on document.ready() (jQuery). Is there a way to enforce that one specific block is called before any of the others? Background: I need to detect JS errors in an automated testing environment, so I need the code that starts logging JS errors to execute before any other JS code executes. 回答1: document.ready() callbacks are called in the order they were registered. If you register your testing callback first, it will be
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