or-operator

问题 I am having trouble with this line of code right here...why am I being prompted with this error? I am getting an error saying "Operator '|' cannot be applied to operands of type 'bool' and 'string' How do check if my residency variable is not equal to these 2 strings I have listed in the if statement? catch (ArgumentException) { if (age > 16 | age > 80) { Console.WriteLine("You can only enter states of OH or MI ad the driver's age must be between 16 and 80."); } if (residency != "OH" | "MI")

问题 I am having trouble with this line of code right here...why am I being prompted with this error? I am getting an error saying "Operator '|' cannot be applied to operands of type 'bool' and 'string' How do check if my residency variable is not equal to these 2 strings I have listed in the if statement? catch (ArgumentException) { if (age > 16 | age > 80) { Console.WriteLine("You can only enter states of OH or MI ad the driver's age must be between 16 and 80."); } if (residency != "OH" | "MI")

问题 This is just fine: def foo a or b end This is also fine: def foo return a || b end This returns void value expression : def foo return a or b end Why? It doesn't even get executed; it fails the syntax check. What does void value expression mean? 回答1: return a or b is interpreted as (return a) or b , and so the value of return a is necessary to calculate the value of (return a) or b , but since return never leaves a value in place (because it escapes from that position), it is not designed to

问题 This is just fine: def foo a or b end This is also fine: def foo return a || b end This returns void value expression : def foo return a or b end Why? It doesn't even get executed; it fails the syntax check. What does void value expression mean? 回答1: return a or b is interpreted as (return a) or b , and so the value of return a is necessary to calculate the value of (return a) or b , but since return never leaves a value in place (because it escapes from that position), it is not designed to

问题 This is just fine: def foo a or b end This is also fine: def foo return a || b end This returns void value expression : def foo return a or b end Why? It doesn't even get executed; it fails the syntax check. What does void value expression mean? 回答1: return a or b is interpreted as (return a) or b , and so the value of return a is necessary to calculate the value of (return a) or b , but since return never leaves a value in place (because it escapes from that position), it is not designed to

问题 This is just fine: def foo a or b end This is also fine: def foo return a || b end This returns void value expression : def foo return a or b end Why? It doesn't even get executed; it fails the syntax check. What does void value expression mean? 回答1: return a or b is interpreted as (return a) or b , and so the value of return a is necessary to calculate the value of (return a) or b , but since return never leaves a value in place (because it escapes from that position), it is not designed to

问题 I have a long set of comparisons to do in Java, and I'd like to know if one or more of them come out as true. The string of comparisons was long and difficult to read, so I broke it up for readability, and automatically went to use a shortcut operator |= rather than negativeValue = negativeValue || boolean . boolean negativeValue = false; negativeValue |= (defaultStock < 0); negativeValue |= (defaultWholesale < 0); negativeValue |= (defaultRetail < 0); negativeValue |= (defaultDelivery < 0);

问题 I have a long set of comparisons to do in Java, and I'd like to know if one or more of them come out as true. The string of comparisons was long and difficult to read, so I broke it up for readability, and automatically went to use a shortcut operator |= rather than negativeValue = negativeValue || boolean . boolean negativeValue = false; negativeValue |= (defaultStock < 0); negativeValue |= (defaultWholesale < 0); negativeValue |= (defaultRetail < 0); negativeValue |= (defaultDelivery < 0);

问题 I have a long set of comparisons to do in Java, and I'd like to know if one or more of them come out as true. The string of comparisons was long and difficult to read, so I broke it up for readability, and automatically went to use a shortcut operator |= rather than negativeValue = negativeValue || boolean . boolean negativeValue = false; negativeValue |= (defaultStock < 0); negativeValue |= (defaultWholesale < 0); negativeValue |= (defaultRetail < 0); negativeValue |= (defaultDelivery < 0);

问题 I am new to C and need help. My code is the following. #include<stdio.h> #include<conio.h> void main() { int suite=2; switch(suite) { case 1||2: printf("hi"); case 3: printf("byee"); default: printf("hello"); } printf("I thought somebody"); getche(); } I am working in Turbo C and the output is helloI thought somebody . There's no error message. Please, let me know how this is working. 回答1: case 1||2: Becomes true . so it becomes case 1: but the passed value is 2. so default case executed.