notation

问题 If i have a function defined inside some object as in : var myobject={ myfunction:function(){//mycode here} } usually you can access the function using: myobject.myfunction() but what if i want to use myobject["myfunction"] trying so , actually the function did not get called , how can i call the function using brackets notation ? 回答1: Use it like. You were very close myobject["myfunction"](); You can also do this var myfuncname="myfunction"; myobject[myfuncname](); 回答2: The two forms

问题 #define LOGI(...) ((void)__android_log_print(ANDROID_LOG_INFO, "native-activity", __VA_ARGS__)) #define LOGW(...) ((void)__android_log_print(ANDROID_LOG_WARN, "native-activity", __VA_ARGS__)) This is definition for these 2 macros; later in the code LOGI and LOGW are used this way LOGI("accelerometer: x=%f y=%f z=%f", event.acceleration.x, event.acceleration.y, event.acceleration.z); and this way LOGW("Unable to eglMakeCurrent"); Since I try to avoid complex macros and #define in general, I

问题 #define LOGI(...) ((void)__android_log_print(ANDROID_LOG_INFO, "native-activity", __VA_ARGS__)) #define LOGW(...) ((void)__android_log_print(ANDROID_LOG_WARN, "native-activity", __VA_ARGS__)) This is definition for these 2 macros; later in the code LOGI and LOGW are used this way LOGI("accelerometer: x=%f y=%f z=%f", event.acceleration.x, event.acceleration.y, event.acceleration.z); and this way LOGW("Unable to eglMakeCurrent"); Since I try to avoid complex macros and #define in general, I

问题 I would like to have the closest number below 1.0 as a floating point. By reading wikipedia's article on IEEE-754 I have managed to find out that the binary representation for 1.0 is 3FF0000000000000 , so the closest double value is actually 0x3FEFFFFFFFFFFFFF . The only way I know of to initialize a double with this binary data is this: double a; *((unsigned*)(&a) + 1) = 0x3FEFFFFF; *((unsigned*)(&a) + 0) = 0xFFFFFFFF; Which is rather cumbersome to use. Is there any better way to define this

问题 I would like to have the closest number below 1.0 as a floating point. By reading wikipedia's article on IEEE-754 I have managed to find out that the binary representation for 1.0 is 3FF0000000000000 , so the closest double value is actually 0x3FEFFFFFFFFFFFFF . The only way I know of to initialize a double with this binary data is this: double a; *((unsigned*)(&a) + 1) = 0x3FEFFFFF; *((unsigned*)(&a) + 0) = 0xFFFFFFFF; Which is rather cumbersome to use. Is there any better way to define this

问题 I am in a Data Structures and Algorithms class. I am trying to indicate if f(n) is Big Theta of g(n). I will also have to indicate Big O, small o, etc... but I am lost about the way to approach this particular pair. f(n) = log* (log n) g(n) = log( log* n ) From what I have currently learned, if this pair completes this statement Θ(g(n))={f(n):there exists c_1, c_2 > 0 and n_0 <br> such that 0 ≤ c_1 g(n) ≤ f(n) ≤ c_2 g(n) for all n ≥ n_0}. My problem is that I have no idea what log * is and

问题 I figured out how to read/convert the symbolic rwx parts to 421 octal parts, which was pretty straight forward. But I am extremely confused when there's the special characters involved. We know that -r-xr---wx converts to 0543, but what does -r-sr---wt or -r-xr---wt convert to? I believe for under user execute permission there's x, s, S. For group execute permission there's also x, s, S. Then all other user execute permission there's x, t, T. What do all these mean and how are they converted

问题 Right off the bat - no, this is NOT homework. I would like to write a prefix notation parser in python (for sums presently)... for example if given: + 2 2 it would return: 4 ideas? 回答1: def prefix(input): op, num1, num2 = input.split(" ") num1 = int(num1) num2 = int(num2) if op == "+": return num1 + num2 elif op == "*": return num1 * num2 else: # handle invalid op return 0 print prefix("+ 2 2") prints 4, also included a multiplication operator just to show how to expand it. 回答2: Prefix

问题 I know that this question has been asked before, but I tried all the possible solutions and none of them worked for me. So, I have a log-log plot in matplotlib, and I would like to avoid scientific notation on the x-axis. This is my code: from numpy import array, log, pi import matplotlib.pyplot as plt from scipy.optimize import curve_fit import matplotlib.ticker as mticker plt.rc('axes.formatter', useoffset=False) tc = array([7499680.0, 12508380.0, 23858280.0, 34877020.0, 53970660.0,

问题 I suddenly stuck here: $source = (object) array( 'field_phone' => array( 'und' => array( '0' => array( 'value' => '000-555-55-55', ), ), ), ); dsm($source); $source_field = "field_phone['und'][0]['value']"; dsm($source->{$source_field}); //This notation doesn't work dsm($source->field_phone['und'][0]['value']); //This does dsm() is Drupal developer function for debug printing variables, objects and arrays. Why $source object doesn't understand $obj->{$variable} notation? Notice: Undefined