nodes

问题 I\'ve been trying to figure this out but I haven\'t gotten anywhere.Hopefully someone can come to my rescue. My problem is I\'m using adjacency list data model to produce my hierarchy data in mysql.I can retrieve the table (see below) into a multidimension array with associative array for each item. What I want to do is once I get this array , I want to get another array with all the nodes (child, grandchild etc) under a parent id (including the parent item).I just can\'t workout how to code

问题 I have a problem with this struct contructor when I try to compile this code: typedef struct Node { Node( int data ) // { this->data = data; previous = NULL; // Compiler indicates here next = NULL; } int data; Node* previous; Node* next; } NODE; when I come this error occurs: \\linkedlist\\linkedlist.h||In constructor `Node::Node(int)\':| \\linkedlist\\linkedlist.h|9|error: `NULL\' was not declared in this scope| ||=== Build finished: 1 errors, 0 warnings ===| Last problem was the struct, but

问题 I have a graph (organigram) how this: digraph G { nodesep=0.3; ranksep=0.2; margin=0.1; node [shape=rectangle]; edge [arrowsize=0.8]; 1 -> 2; 1 -> 3; 1 -> 4; 1 -> 5; 1 -> 6; 1 -> 7; 1 -> 8; 1 -> 9; 1 -> 10; } I have organigrams with 70 people and it\'s impossible to print in A4. How would I put nodes in 2 or 3 lines? 回答1: Here are two possibilities (see also this question): 1. Use the unflatten utility Graphviz provides a tool called unflatten. If you pre-process your graph using this command

问题 To simplify the problem, I have a graph that contains nodes and edges which are on a 2D plane. What I want to be able to do is click a button and it make the automatically layout the graph to look clean. By that I mean minimal crossing of edges, nice space between nodes, maybe even represent the graph scale (weighted edges). I know this is completely subjective of what is a clean looking graph, but does anyone know of an algorithm to start with, rather than reinventing the wheel? Thanks. 回答1:

问题 I feel as if I am not actually deleting the node and freeing up memory. I think I am just moving pointers around so when I print the linked list the list doesn\'t print the element I deleted. So my question is am I actually deleting the node or am I just simply rearranging the pointers so it looks like I am deleting the nodes(Essentially just breaking the links but not deleting the node)? Thank you for any help. void SLL::deleteNode(int target){ Node *current = new Node; Node *previous = new

问题 What is the library? Is there a full implementation? How is the library used? Where is its website? 回答1: libxml2 has a number of advantages: Compliance to the spec Active development and a community participation Speed. This is really a python wrapper around a C implementation. Ubiquity. The libxml2 library is pervasive and thus well tested. Downsides include: Compliance to the spec. It's strict. Things like default namespace handling are easier in other libraries. Use of native code. This