nodes

<div id="div-01">Here is div-01</div> <div id="div-02">Here is div-02</div> Aren't they the same thing ? Both returning the immediately followed node. I read a lot of articles but seems to me like the same thing, but can't figure where to use one versus other ? nextElementSibling always returns an element. nextSibling can return any kind of node. They are the same for your example, but different in other cases, e.g.: <p><span id="span-01">Here is span-01</span> Some text at the top level <span id="span-02">Here is span-02</span></p> In this case, document.getElementById('span-01')

I have a problem with this struct contructor when I try to compile this code: typedef struct Node { Node( int data ) // { this->data = data; previous = NULL; // Compiler indicates here next = NULL; } int data; Node* previous; Node* next; } NODE; when I come this error occurs: \linkedlist\linkedlist.h||In constructor `Node::Node(int)':| \linkedlist\linkedlist.h|9|error: `NULL' was not declared in this scope| ||=== Build finished: 1 errors, 0 warnings ===| Last problem was the struct, but it worked fine when it was in my main.cpp, this time it's in a header file and is giving me this problem. I

I have a graph (organigram) how this: digraph G { nodesep=0.3; ranksep=0.2; margin=0.1; node [shape=rectangle]; edge [arrowsize=0.8]; 1 -> 2; 1 -> 3; 1 -> 4; 1 -> 5; 1 -> 6; 1 -> 7; 1 -> 8; 1 -> 9; 1 -> 10; } I have organigrams with 70 people and it's impossible to print in A4. How would I put nodes in 2 or 3 lines? marapet Here are two possibilities (see also this question ): 1. Use the unflatten utility Graphviz provides a tool called unflatten . If you pre-process your graph using this command line: unflatten -l 3 wide.gv | dot -Tpng -o wide.png the output image will be similar to the below

I feel as if I am not actually deleting the node and freeing up memory. I think I am just moving pointers around so when I print the linked list the list doesn't print the element I deleted. So my question is am I actually deleting the node or am I just simply rearranging the pointers so it looks like I am deleting the nodes(Essentially just breaking the links but not deleting the node)? Thank you for any help. void SLL::deleteNode(int target){ Node *current = new Node; Node *previous = new Node; for (current = front->next, previous = front; current != NULL; current = current->next, previous