mysql

sql return only max date for each id

由 。_饼干妹妹 提交于 2021-02-10 04:53:34
问题 I have a database with one table that looks like this Books(id, title, author_id, date) I am using type DATE for the date field. What the query is looking to do is return only the most recent book from each author, so even for the books that have the same author_id, only return the book that has the most recent date field for that author. So for all books find the most recent book from each author, returning title, author_id, and date. I believe I will need to use the MAX function with a

sql return only max date for each id

由 谁都会走 提交于 2021-02-10 04:53:10
问题 I have a database with one table that looks like this Books(id, title, author_id, date) I am using type DATE for the date field. What the query is looking to do is return only the most recent book from each author, so even for the books that have the same author_id, only return the book that has the most recent date field for that author. So for all books find the most recent book from each author, returning title, author_id, and date. I believe I will need to use the MAX function with a

禅道Bug管理工具环境搭建

由 独自空忆成欢 提交于 2021-02-10 04:30:57
下载地址： http://sourceforge.net/projects/zentao/files/8.2/ZenTaoPMS.8.2.stable.exe/download 1、解压ZenTaoPMS.8.1.3到根目录，比如“C:\ xampp”、“D:\ xampp 2、进入xampp，以管理员身份点击“启动禅道” 3、禅道集成运行环境1.2.6，点击启动 4、系统会自动启动禅道所需要的apache和mysql服务 5、点击“访问禅道”，即可打开禅道环境的首页，5秒钟之后，页面会自动调到禅道的页面，并点击“开源版” 6、禅道项目管理软件的登录账号：admin、密码：123456 7、配置禅道：修改mysql数据库的密码，输入数据库的访问网http://127.0.0.1/phpmyadmin，点击进入“用户”，勾选“root”用户，接着，点击编辑权限 8、在“修改密码”中，输入密码：12345，点击“执行” 9、修改“root”账号的数据库密码，需要在xampp/zentao/config/my.php 里面的数据库密码 10、继续在D:\xampp\phpmyadmin\config.inc.php修改数据库密码 11、在服务器apache：D:\xampp\apache\conf\httpd.conf 更改端口号：80 改为端口号：8088 12、查看数据库mysql:

Mysql grant privileges get error ERROR 1133 (42000): Can't find any matching row in the user table

由 冷暖自知 提交于 2021-02-10 04:19:33
问题 I am trying to grant priv to my django user, but I got error says can't find any matching row in the user table. It is the user table. mysql> select user,grant_priv from user; +---------------+------------+ | user | grant_priv | +---------------+------------+ | root | Y | | mysql.session | N | | mysql.sys | N | | django | N | +---------------+------------+ Here is databases. mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | django | |

MySQL substring match using regular expression; substring contain 'man' not 'woman'

由 北慕城南 提交于 2021-02-10 04:19:05
问题 I have an issue while I fetch data from database using regular expression. While I search for 'man' in tags it returns tags contains 'woman' too; because its substring. SELECT '#hellowomanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 correct, it contains 'woman' SELECT '#helloowmanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 incorrect, it can contain anything other than 'woman' SELECT '#stylemanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 1 correct How can I update the regular

MySQL substring match using regular expression; substring contain 'man' not 'woman'

由 |▌冷眼眸甩不掉的悲伤 提交于 2021-02-10 04:14:21
问题 I have an issue while I fetch data from database using regular expression. While I search for 'man' in tags it returns tags contains 'woman' too; because its substring. SELECT '#hellowomanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 correct, it contains 'woman' SELECT '#helloowmanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 incorrect, it can contain anything other than 'woman' SELECT '#stylemanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 1 correct How can I update the regular

MySQL substring match using regular expression; substring contain 'man' not 'woman'

由 萝らか妹 提交于 2021-02-10 04:14:17
问题 I have an issue while I fetch data from database using regular expression. While I search for 'man' in tags it returns tags contains 'woman' too; because its substring. SELECT '#hellowomanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 correct, it contains 'woman' SELECT '#helloowmanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 incorrect, it can contain anything other than 'woman' SELECT '#stylemanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 1 correct How can I update the regular

MySQL substring match using regular expression; substring contain 'man' not 'woman'

由 会有一股神秘感。 提交于 2021-02-10 04:14:12
问题 I have an issue while I fetch data from database using regular expression. While I search for 'man' in tags it returns tags contains 'woman' too; because its substring. SELECT '#hellowomanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 correct, it contains 'woman' SELECT '#helloowmanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 0 incorrect, it can contain anything other than 'woman' SELECT '#stylemanclothing' REGEXP '^(.)*[^wo]man(.)*$'; # returns 1 correct How can I update the regular

Mysql grant privileges get error ERROR 1133 (42000): Can't find any matching row in the user table

由 限于喜欢 提交于 2021-02-10 04:14:09
问题 I am trying to grant priv to my django user, but I got error says can't find any matching row in the user table. It is the user table. mysql> select user,grant_priv from user; +---------------+------------+ | user | grant_priv | +---------------+------------+ | root | Y | | mysql.session | N | | mysql.sys | N | | django | N | +---------------+------------+ Here is databases. mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | django | |

Error while sending QUERY packet. PID=9565

由 巧了我就是萌 提交于 2021-02-10 03:28:14
问题 I have two different environments develop and live almost both are same But the above (in title) warning is occurred in develop mode only. Before this warning I am also getting error message as "Allowed memory size of 268435456 bytes exhausted". This happened only in develop mode. Using PHP version 5.6 with mysql (not mysqli). 回答1: thanks every one . Problem was solved the issue is one of my developer making wrong recursive function that's why more memory allocated 来源： https://stackoverflow
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