multiple-inheritance

Why can't I create a default, ordered dict by inheriting OrderedDict and defaultdict?

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-04 01:28:09
My first attempt to combine the features of two dictionaries in the collections module was to create a class that inherits them: from collections import OrderedDict, defaultdict class DefaultOrderedDict(defaultdict, OrderedDict): def __init__(self, default_factory=None, *a, **kw): super().__init__(default_factory, *a, **kw) However, I cannot assign an item to this dictionary: d = DefaultOrderedDict(lambda: 0) d['a'] = 1 Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib64/python3.3/collections/__init__.py", line 64, in __setitem__ self.__map[key] = link =

Why does C# allow multiple inheritance though interface extension methods but not classes? [closed]

邮差的信 提交于 2019-12-04 00:38:54
Closed. This question is off-topic. It is not currently accepting answers. Learn more . Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 7 years ago . I've checked through other questions and surprisingly this question doesn't seem to have been asked. With Extension methods, interfaces provide limited but true implementation multiple inheritance. This brings with it the Diamond problem, the same as with class based multiple inheritance. Why is this better or more acceptable than class based multiple inheritance that so many people seem to find so

Why is the diamond case with its common ancestor used to explain Java multiple inheritance issue, instead of two unrelated parent classes?

北慕城南 提交于 2019-12-03 23:34:11
This question might sound weird to Java people but if you try to explain this, it would be great. In these days I am clearing some of Java's very basic concept. So I come to Inheritance and Interface topic of Java. While reading this I found that Java does not support Multiple Inheritance and also understood that, what I am not able to understand that why everywhere Diamond figure issue(At least 4 class to create diamond) is discussed to explain this behavior, Can't we understand this issue using 3 classes only. Say, I have class A and class B, these two classes are different (they are not

Any way to inherit from same generic interface twice (with separate types) in Kotlin?

本小妞迷上赌 提交于 2019-12-03 20:35:03
问题 I have a scenario in my code where I would like a class to implement an interface for two separate types, like this example: interface Speaker<T> { fun talk(value: T) } class Multilinguist : Speaker<String>, Speaker<Float> { override fun talk(value: String) { println("greetings") } override fun talk(value: Float) { // Do something fun like transmit it along a serial port } } Kotlin is not pleased with this, citing: Type parameter T of 'Speaker' has inconsistent values: kotlin.String, kotlin

Why do I have to specify my own class when using super(), and is there a way to get around it?

耗尽温柔 提交于 2019-12-03 19:50:12
问题 When using Python's super() to do method chaining, you have to explicitly specify your own class, for example: class MyDecorator(Decorator): def decorate(self): super(MyDecorator, self).decorate() I have to specify the name of my class MyDecorator as an argument to super() . This is not DRY. When I rename my class now I will have to rename it twice. Why is this implemented this way? And is there a way to weasel out of having to write the name of the class twice(or more)? 回答1: The BDFL agrees.

bad weak pointer when base and derived class both inherit from boost::enable_shared_from_this

↘锁芯ラ 提交于 2019-12-03 19:40:35
问题 I have a base class which derives from boost::enable_shared_from_this, and then another class which derives from both the base class and boost::enable_shared_from_this: #include <boost/enable_shared_from_this.hpp> #include <boost/shared_ptr.hpp> using namespace boost; class A : public enable_shared_from_this<A> { }; class B : public A , public enable_shared_from_this<B> { public: using enable_shared_from_this<B>::shared_from_this; }; int main() { shared_ptr<B> b = shared_ptr<B>(new B());

Why doesn't OrderedDict use super?

淺唱寂寞╮ 提交于 2019-12-03 16:46:05
We can create an OrderedCounter trivially by using multiple inheritance: >>> from collections import Counter, OrderedDict >>> class OrderedCounter(Counter, OrderedDict): ... pass ... >>> OrderedCounter('Mississippi').items() [('M', 1), ('i', 4), ('s', 4), ('p', 2)] Correct me if I'm wrong, but this crucially relies on the fact that Counter uses super : class Counter(dict): def __init__(*args, **kwds): ... super(Counter, self).__init__() ... That is, the magic trick works because >>> OrderedCounter.__mro__ (__main__.OrderedCounter, collections.Counter, collections.OrderedDict, dict, object) The

C# Multiple Inheritance

柔情痞子 提交于 2019-12-03 16:36:40
问题 Currently im studying the C# with ASP.NET MVC 4 with Code First Approach . Im Visual Basic Developer, and Now i want to Start C#. And, now i came accross the situation where i've to manage Multiple Inheritance. But, it is not possible with Class i thought. So, how should i manage these classes i have : //I have the Following Person Class which Hold Common Properties //and a Type of Person e.g : Student, Faculty, Administrative public class Person { public int Id { get; set; } public string

Inherit from multiple partial implementations of an abstract base class?

半腔热情 提交于 2019-12-03 16:23:25
问题 Is it possible to have a number of partial implementations of an abstract interface, and then collect these partial implementations into a single concrete class by using multiple inheritence? I have the following example code: #include <iostream> struct Base { virtual void F1() = 0; virtual void F2() = 0; }; struct D1 : Base { void F1() override { std::cout << __func__ << std::endl; } }; struct D2 : Base { void F2() override { std::cout << __func__ << std::endl; } }; // collection of the two

How to implement virtual functions with the same name in multiple inheritance [duplicate]

半城伤御伤魂 提交于 2019-12-03 16:13:34
This question already has an answer here: Inherit interfaces which share a method name 5 answers Have code as below // A has a virtual function F(). class A { public: virtual void F() {}; }; // The same for B. class B { public: virtual void F() {}; }; // C inherits A and B. class C : public A, public B { public: // How to implement the 2 virtual functions with the same name but from // different base classes. virtual F() {...} }; Note that there is a default implementation of F() in the base classes. Thanks to Jan Herrmann and Spook. Is the below a simpler solution if we have to use some extra