multiple-columns

问题 I'm trying to create a table in Latex but without success. I tried different solutions but no one solves my problem. I would like create a table like the picture below: Can anyone show how to do this in latex please? 回答1: One first sketch may be the following: \documentclass{article} \usepackage{multirow} \begin{document} \begin{tabular}{|c|c|c|c|c|c|} \hline \multirow{3}{*}{A} & \multicolumn{2}{c|}{User B} & % \multicolumn{2}{c|}{User C} & \multirow{3}{*}{D}\\ \cline{2-5} & \multicolumn{2}{c

问题 I have been looking for an answer for a few hours about my problem. My current table: StudentName Course Correct Wrong Blank Score ------------------------------------------------- Student1 Math 38 2 0 95 Student1 English 45 5 0 90 ... Student2 Math 38 2 0 95 Student2 English 45 5 0 90 What I want is: Math English StudentName Correct Wrong Blank Score Correct Wrong Blank Score Student1 38 2 0 95 45 5 0 90 Student2 38 2 0 95 45 5 0 90` ... SELECT dbo.tbl_Students.StudentName, dbo.tbl

问题 This question already has answers here : Fastest way to replace NAs in a large data.table (9 answers) Closed 4 years ago . Let DT be a data.table: DT<-data.table(V1=sample(10), V2=sample(10), ... V9=sample(10),) Is there a better/simpler method to do multicolumn recode/sub-assign like this: DT[V1==1 | V1==7,V1:=NA] DT[V2==1 | V2==7,V2:=NA] DT[V3==1 | V3==7,V3:=NA] DT[V4==1 | V4==7,V4:=NA] DT[V5==1 | V5==7,V5:=NA] DT[V6==1 | V6==7,V6:=NA] DT[V7==1 | V7==7,V7:=NA] DT[V8==1 | V8==7,V8:=NA] DT[V9

问题 This question already has answers here : Fastest way to replace NAs in a large data.table (9 answers) Closed 4 years ago . Let DT be a data.table: DT<-data.table(V1=sample(10), V2=sample(10), ... V9=sample(10),) Is there a better/simpler method to do multicolumn recode/sub-assign like this: DT[V1==1 | V1==7,V1:=NA] DT[V2==1 | V2==7,V2:=NA] DT[V3==1 | V3==7,V3:=NA] DT[V4==1 | V4==7,V4:=NA] DT[V5==1 | V5==7,V5:=NA] DT[V6==1 | V6==7,V6:=NA] DT[V7==1 | V7==7,V7:=NA] DT[V8==1 | V8==7,V8:=NA] DT[V9

问题 I have a function which I want to apply to certain columns of a pandas dataframe. So rather than explicitly stating the columns, I want to dynamically select the columns I want and then call the function e.g. How to implement something like: for column in dataframe: if column.name != 'manager': apply function(): 回答1: I think you can first find all columns by list comprehension and then apply func : import pandas as pd df = pd.DataFrame({'A':[1,2,3], 'B':[4,5,6], 'C':[7,8,9], 'D':[1,3,5], 'E':

问题 Say I have this array: A, B 1, G 2, X 3, F 4, Z 5, I If column B equals [X, Y or Z] replace column A with value "T" I've found how to change values within the same column but not across, any help would be most appreciated. 回答1: You can try this: import pandas as pd df = pd.DataFrame({ 'A': [1, 2, 3, 4, 5], 'B': ['G', 'X', 'F', 'Z', 'I'] }) df.ix[df.B.isin(['X','Y','Z']), 'A'] = 'T' print df Output: A B 0 1 G 1 T X 2 3 F 3 T Z 4 5 I Remember to use ix or loc to avoid setting values on a copied

问题 Say I have this array: A, B 1, G 2, X 3, F 4, Z 5, I If column B equals [X, Y or Z] replace column A with value "T" I've found how to change values within the same column but not across, any help would be most appreciated. 回答1: You can try this: import pandas as pd df = pd.DataFrame({ 'A': [1, 2, 3, 4, 5], 'B': ['G', 'X', 'F', 'Z', 'I'] }) df.ix[df.B.isin(['X','Y','Z']), 'A'] = 'T' print df Output: A B 0 1 G 1 T X 2 3 F 3 T Z 4 5 I Remember to use ix or loc to avoid setting values on a copied

问题 I need to implement the following query SELECT * FROM friend WHERE ( friend.id1, friend.id2 ) NOT IN (SELECT id1, id2 FROM likes) but NOT IN can't be implemented on multiple columns. How do I write this query 回答1: I'm not sure whether you think about: select * from friend f where not exists ( select 1 from likes l where f.id1 = l.id and f.id2 = l.id2 ) it works only if id1 is related with id1 and id2 with id2 not both. 回答2: Another mysteriously unknown RDBMS. Your Syntax is perfectly fine in

问题 I'd like to create a MYSQL stored procedure that dynamically renames the column names of TABLE_EXAMPLE with content from TABLE_MASTER -> the expected result is shown on TABLE_RESULT . Here are the tables content: TABLE_EXAMPLE (THE HEADERS MIGHT CHANGE BUT THEY ARE MAPPED WITH A COLUMN IN TABLE_EXAMPLE): |header01 | header02|...|header n| |data01 ..| data02..|...|data 0n| |data11 ..| data12..|...|data 1n| ..........etc................. |data n1..|data n2..|...|data nn| TABLE_MASTER (STATIC

问题 In BASH I run the following one liner to get an individual column/field after splitting on a given character (one can use AWK as well if they want to split on more than one char i.e. on a word in any order, ok). #This will give me first column i.e. 'lori' i.e. first column/field/value after splitting the line / string on a character '-' here echo "lori-chuck-shenzi" | cut -d'-' -f1 # This will give me 'chuck' echo "lori-chuck-shenzi" | cut -d'-' -f2 # This will give me 'shenzi' echo "lori