model-view-controller

问题 I don't need any cosmetic work to do, Is there any better way to do this, I have some doubts while returning the View from controller to View with model.... I hope it will be in better way but I am not able to do this, Please guide me. This is the view. @model MVCwithWebAPI.Models.RootObject @{ ViewBag.Title = "Index"; Layout = "~/Views/Shared/_Layout.cshtml"; } <table> <tr> <td> <strong> <br /> @Model.cod </strong> </td> <td> <strong> <br /> @Model.wind.speed </strong> </td> <td> <strong>

问题 I have Ext.Net MVC form that post values to DirectAction. On server side, In DirectAction CoboBox selected value is always null. public ActionResult Save() { var cmbSender = this.GetCmp<ComboBox>("cmbSender"); var senderID = cmbSender.SelectedItem.Value; } I have checked Request["cmbSender"] but it does not work <form id="form12"> @( X.TabPanel() .Items( X.FormPanel() .Title("New Job") .ID("pnlNewJob") .Layout(LayoutType.Form) .MarginSpec("5 5 5 5") .Items( X.Panel() .Border(false)

问题 I have a User model that has all the queried fields with the existing data in the database. When I execute the following query- @user = User.find(4, :select => 'user_fname, user_lname') Rails throws the following error for the above line Couldn't find all Users with 'user_id': (4, {:select=>"user_fname, user_lname"}) (found 1 results, but was looking for 2) What's going wrong? 回答1: You can try this. I hope this will help. @user = User.where("id = ?", 4).select( "user_fname, user_lname") 回答2:

问题 I am new to Prestashop and I am trying to add a new "Sort by" field ( where by default you have: "Relevance" , "Name, A to Z" , "Name, Z to A", "Price, low to high", "Price, high to low" ) As you guys know, the functionality is located in the module called: "Ps_facetedsearch" , link here. I tried: Editing the module files, this works, but I can't upgrade the module anymore if I want to keep the functionality. Overriding, but can't seem to get it working, it still uses the same old module, not

问题 I am new to hibernate , I am doing project in Eclipse. When I log in to my application it displays to many log messages in console which I dont need, the log message is something like this, 97 [http-bio-8080-exec-9] INFO org.hibernate.annotations.common.Version - Hibernate Commons Annotations 3.2.0.Final 102 [http-bio-8080-exec-9] INFO org.hibernate.cfg.Environment - Hibernate 3.6.10.Final 103 [http-bio-8080-exec-9] INFO org.hibernate.cfg.Environment - hibernate.properties not found 105 [http

问题 I am trying to get an instance of my view within the controller. How can I accomplish this. The main reason I am trying to do this is that I have a grid in my view that I want to disable until a selection from a combobox is made so I need to have access to the instance of the view. Help? My controller: Ext.define('STK.controller.SiteSelectController', { extend: 'Ext.app.Controller', stores: ['Inventory', 'Stacker', 'Stackers'], models: ['Inventory', 'Stackers'], views: ['scheduler.Scheduler']

问题 This is the relationship i have between User,Gig(product),and Purchase table that records the purchase. class User < ActiveRecord::Base has_many :gigs has_many :purchases, foreign_key: 'buyer_id' has_many :sales, foreign_key: 'seller_id', class_name: 'Purchase' end class Gig < ActiveRecord::Base has_many :purchases has_many :buyers, through: :purchases has_many :sellers, through: :purchases end class Purchase < ActiveRecord::Base belongs_to :gig belongs_to :buyer, class_name: 'User' belongs

问题 I am having a problem with some custom pages that I am creating in Opencart for a big school project. More specifically, it seems that the model is not passing any query data to the controller and the view is unable to display the data. I read this post (How to create a custom admin page in opencart?) and started working from there. The idea is basically to create a portal where the admin can review all orders, all customers, all products and edit the products. Now, as I am quite new to

问题 I´m writing my own PHP MVC framework. So, the entry point for bootstrapping is at myapp/public/index.php . There I check the URL passed, as: $url = $_GET["url"]; And then I explode the code finding the necessary controller, action and parameters to navigate: $parts = explode("/", trim($url, "/")); if (sizeof($parts) > 0) { $controller = $parts[0]; if (sizeof($parts) >= 2) { $action = $parts[1]; $parameters = array_slice($parts, 2); } } From here the code loads and runs the controller and view

问题 I have an MVC razor form with a Kendo grid. The grid has an asynch image uploader. @(Html.Kendo().Grid<CraftStore.Models.Catalog>() .Name("CatalogGrid") .Columns(columns => { columns.Bound(p => p.CatalogName).Filterable(true).Width(240); columns.Bound(p => p.CatalogDescription).Filterable(true).Width(340); columns.Bound(p => p.ModelNumber).Filterable(true).Width(110); columns.Bound(p => p.SerialNumber).Filterable(true).Width(110); columns.Bound(p => p.InventoryCount).Filterable(true).Width