model-view-controller

JavaFX+MVC. How to hide/show multiple windows?

て烟熏妆下的殇ゞ 提交于 2020-01-06 02:00:07
问题 How to make that when i click on "Open second window" the main window be hide. And when i close second window, the main window be showed? I read this post, but i don't know how to implement it for my task. Thanks! I have next code: Main.java public class Main extends Application { @Override public void start(Stage primaryStage) { primaryStage.setTitle("First Stage"); try { primaryStage.setResizable(false); Parent root = FXMLLoader.load(getClass().getResource("MainView.fxml")); Scene scene =

MVC Model binding issue - list of objects

二次信任 提交于 2020-01-06 01:17:31
问题 The scenario is a shopping basket - the user will update a text box for the quantity and hit the update button. Currently, upon hitting the update button, the Action is hit but the model properties are all null. My first thoughts are that there is some issue with the binding because the ids of the controls are changed for each row. Are my thoughts correct? if so, how can I resolve this? EDIT: I also tried to use a for loop, rather than foreach but that didn't work either. All my code is below

JTable / TableModel MVC Implementation [Help]

Deadly 提交于 2020-01-05 23:31:31
问题 I'm trying to implement the MVC on a test example. How can i update the table when there is a change Class: Model class valueUpdater extends Thread { private String sValue; public valueUpdater() { this.start(); } public String getValue() { return this.sValue; } public void run() { try { for (int i = 0; i <= 100; i++) { this.sValue = String.valueOf(i); try { Thread.sleep(2000); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); } } } catch (Exception e)

How to convert Java Object to JSON string?

为君一笑 提交于 2020-01-05 23:12:45
问题 Hello i'm trying to convert my Java Object to a Json string to use in my view with javascript functions. I tried to use Google's gson lib: String myjson = ""; Gson gson = new Gson(); myjson = gson.toJson(myuser);//myuser is my java object However when i call myjson, it consists of ' " ' instead of the character ' " ' for this reason i can't able to use it in my view, it is creating me problems. How can I fix this, how can I create Json string properly? Edit : Is there a chance of making a

How to convert Java Object to JSON string?

非 Y 不嫁゛ 提交于 2020-01-05 23:10:52
问题 Hello i'm trying to convert my Java Object to a Json string to use in my view with javascript functions. I tried to use Google's gson lib: String myjson = ""; Gson gson = new Gson(); myjson = gson.toJson(myuser);//myuser is my java object However when i call myjson, it consists of ' " ' instead of the character ' " ' for this reason i can't able to use it in my view, it is creating me problems. How can I fix this, how can I create Json string properly? Edit : Is there a chance of making a

How to convert Java Object to JSON string?

自闭症网瘾萝莉.ら 提交于 2020-01-05 23:08:31
问题 Hello i'm trying to convert my Java Object to a Json string to use in my view with javascript functions. I tried to use Google's gson lib: String myjson = ""; Gson gson = new Gson(); myjson = gson.toJson(myuser);//myuser is my java object However when i call myjson, it consists of ' " ' instead of the character ' " ' for this reason i can't able to use it in my view, it is creating me problems. How can I fix this, how can I create Json string properly? Edit : Is there a chance of making a

How to convert Java Object to JSON string?

*爱你&永不变心* 提交于 2020-01-05 23:08:21
问题 Hello i'm trying to convert my Java Object to a Json string to use in my view with javascript functions. I tried to use Google's gson lib: String myjson = ""; Gson gson = new Gson(); myjson = gson.toJson(myuser);//myuser is my java object However when i call myjson, it consists of ' " ' instead of the character ' " ' for this reason i can't able to use it in my view, it is creating me problems. How can I fix this, how can I create Json string properly? Edit : Is there a chance of making a

PHP: Good solution for MVC routing function to parse requested views? [duplicate]

若如初见. 提交于 2020-01-05 13:51:12
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: CMS Routing in MVC I want to implement the MVC design structure and currently struggeling with an good solution to parse requested views. In my routing file, I have following code: public function parseRequestedView() { $this->ressource_requested = explode('/', trim($_GET['view'], '/')); // e.g.: http://www.foo.com/article/{id}/comments/show if (!empty($this->ressource_requested[3])) { // Format: [0] viewpoint

Load view codeigniter with plain text

孤者浪人 提交于 2020-01-05 10:32:32
问题 I am using codeigniter for my website and I was wondering if I could load a view in a view without using PHP. So like a Template Parser, is it possible to run this code: <div> <?php $this->load->view('widget'); ?> </div> with plain text like: <div> {loadview:widget} </div> Tnx 回答1: Sorry, but there's nothing built in to Codeigniter that does this. You'll have to look at using a third party template parser or write your own. Some suggestions: Twig: http://twig.sensiolabs.org/ (recommend)

Design Issue: MVC model with Java CardLayout application

你说的曾经没有我的故事 提交于 2020-01-05 08:34:05
问题 Sorry for the vague title, I am trying to layout an application i have unfortunately starting coding without following proper MVC architecture rules. I have an application that has the following structure. JFrame with a JPanel ("MainPanel") added as a component and the MainPanel has a CardLayout structure. The MainPanel then has several JPanel's that are flipped through using buttons, Jcombo Box and List selections. I want to implement the MVC model using this structure and i am having