min

I am doing a homework assignment for a class, and am looking for some helpful pointers, not full solutions. Basically, I have to write a Java program that reads in a text file and lists the information line by line, lists the line number, and finally, prints out the maximum and minimum value and the years that relates to each. The text file contains a year and the temperature for that year. So, it lists something like, "1900 50.9." I am not meant to use an array, or the scanner, this is part of the assignment. I've already been able to successfully get the program to print out each year and

I am having list of tuple from which I want the tuple with the minimum value at index 1 . For example, if my list is like: a =[('a', 2), ('ee', 3), ('mm', 4), ('x', 1)] I want the returned tuple to be ('x', 1) . Currently I am using sorted function to get this result like: min=sorted(a, key=lambda t: t[1])[0] Is there better ways to do it? Maybe with min function? Moinuddin Quadri You may use min() function with key parameter in order to find the tuple with minimum value in the list. There is no need to sort the list. Hence, your min call should be like: >>> min(a, key=lambda t: t[1]) ('x', 1)

I have a vector and a cell array (with repeating strings) with the same size. The cell array defines the groups. I want to find min/max values in the vector for each group. For example: value = randperm(5) %# just an example, non-unique in general value = 4 1 2 3 5 group = {'a','b','a','c','b'}; [grnum, grname] = grp2idx(group); I use ACCUMARRAY function for this: grvalue = accumarray(grnum,value,[],@max); So I have new cell array with unique group name ( grname ) and new vector ( grvalue ). grname = 'a' 'b' 'c' grvalue = 4 5 3 But I also need to find location index of values from old vector

Tracing back a ValueError: cannot convert float NaN to integer I found out that the line: max('a', 5) max(5, 'a') will return a instead of 5. In the above case I used the example string a but in my actual case the string is a NaN (the result of a fitting process that failed to converge). What is the rationale behind this behaviour? Why doesn't python recognize automatically that there's a string there and that it should return the number? Even more curious is that min() does work as expected since: min('a', 5) min(5, 'a') returns 5 . Martijn Pieters In Python 2, numeric values always sort

If a have a list like: l = [1,2,3,4,5] and I want to have at the end min = 1 max = 5 WITHOUT min(l) and max(l) . Mink The fastest approach I can think of would be to sort the original list and then pick the first and last elements. This avoids looping multiple times, but it does destroy the original structure of your list. This can be solved by simply copying the list and sorting only the copied list. I was curious if this was slower than just using max() and min() with this quick example script: import time l = [1,2,4,5,3] print "Run 1" t1 = time.time() print "Min =", min(l) print "Max =",