min

I am looking to find the lowest positive value in an array and its position in the list. If a value within the list is duplicated, only the FIRST instance is of interest. This is what I have which does what I want but includes 0. print "Position:", myArray.index(min(myArray)) print "Value:", min(myArray) for example, as it stands if, myArray = [4, 8, 0, 1, 5] then Position: 2, Value: 0 I want it to present position: 3, value: 1 You can use a generator expression with min . This will set m as the minimum value in a that is greater than 0. It then uses list.index to find the index of the first

So I have the following problem: There are n rotating dials each set to some number between 0-9 and they need to be matched with another series of n numbers(also between 0-9). One step of rotation is rotating any number of consecutive dials up or down by one step. The dials wrap around 9. i.e. rotating one step up from 9 gives 0 and vice versa. I need to find the minimum number of steps to match the initial configuration with the given configuration. Ex: Initial -> 154 Given -> 562 1. first move first 2 dials up by 1 154 -> 264 ->1 step 2. move 1st dial 3 up 264->564 ->3 steps 3. move 3rd dial

I need to generate random numbers with following properties. Min should be 200 Max should be 20000 Average(mean) is 500. Optional: 75th percentile to be 5000 Definitely it is not uniform distribution, nor gaussian. I need to give some left skewness. Java Random probably won't work because it only gives you normal(gaussian) distributions. What you're probably looking for is an f distribution (see below). You can probably use the distlib library here and choose the f distribution . You can use the random method to get your random number. Say X is your target variable, lets normalize the range by

I've got 2 integers. I need to know which one has minimum value and get this value. Is there any pretty way (one function?) to do it? Now i'm doing it this way: $foo = 5; $bar = 7; $min = min($foo, $bar); if($min == $foo) { ... } else { ... } Use min() if you need to work with the lower value. $min = min($foo, $bar); print "min: $min"; And use a regular if if you simply want to do the comparison if ($foo <= $bar) { // $foo is smaller/equal } else { // $bar is smaller } 来源： https://stackoverflow.com/questions/15881625/find-which-int-was-minimum-in-php

so we have the mysql MIN() function for getting the minimum in a table...but what if I want to get a MIN() based on a criteria so something like MIN(age) WHERE height < 170 in which the aim is to get the minimum age of ONLY people whose height is < 170...so say sam is the youngest of those with height < 170, but pam is younger than sam but have height > 170, then the query should return sam instead of pam... how would I compose such query? You say you want the "minimum age of ONLY people whose height is < 170" SELECT MIN(age) FROM YourTable WHERE height < 170 Will in fact work as you require

I am trying to find the MIN and MAX values for each row of a CSV file and append them to the next position in the list, positions 5 and 6. I have managed to calculate the average, append this to the forth position and output this in highest to lowest however, I am struggling to work out how to find the MAX and MIN values of each row so I can do the same - highest to lowest. The original CSV is formatted: Fred,56,78,99 with each user on a new line. Any help would be appreciate. import csv import operator sample = open("sampleData.txt", "r") csv1 = csv.reader(sample, delimiter = ',') sort =