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Python - run external script

穿精又带淫゛_ 提交于 2019-12-08 04:31:28
Does someone know if I have a script one.py which is written the following way: if __name__ == '__main__': # Do something And I want to call that main function from another script. How should I do that? I guess it would be something like (let's say this is launcher.py ) # 'one' stands for import from `one.py` module import one if __name__ == '__main__': one.main() The only problem is that I can't call main() this way. How should this be done? with file('a.py','rU') as f: co=compile(f.read(),'foobar','exec') exec co in {'__name__':'__main__'} Define your script like: def main(): # Do something

Java running main method of other class, when JButton is pressed

南笙酒味 提交于 2019-12-08 04:18:19
问题 I am trying to develop a JFrame which has two buttons that would let me to call the main method of other classes. The first try was to put it directly into the actionPerformed of each button, this will cause the JFrame of the other class to open but showing only the title of it and not showing any contents of the JPanel additionally freezing the program (can't even press close button, have to go into task manager or eclipse to kill it). The second try was adding a method call in

The initialization of non-local non-inline variables: does it take place strictly before the `main()` function call?

北战南征 提交于 2019-12-08 03:34:42
问题 Is the order in which digits will be printed in the following simple program implementation-defined? #include <iostream> struct Foo { Foo() { std::cout << "1" << std::endl; } }; Foo foo; int main() { std::cout << "2" << std::endl; } Some wordings from the standard ( Dynamic initialization of non-local variables [basic.start.dynamic]/4 ): It is implementation-defined whether the dynamic initialization of a non-local non-inline variable with static storage duration is sequenced before the first

How to fix “R.menu.main” in java when first developing an android app?

孤者浪人 提交于 2019-12-08 03:08:27
问题 So I downloaded everything that the Android app tutorial told me to, and I am and using Eclipse, but I keep getting an error message on main in R.menu.main : public boolean onCreateOptionsMenu(Menu menu) { // Inflate the menu; this adds items to the action bar if it is present. getMenuInflater().inflate(R.menu.main, menu); return true; I've imported android.R; and it didn't work; I deleted that line and I went to Project>Clean and it still didn't fix itself. Other people on this topic keep

Why does main() require braces?

烂漫一生 提交于 2019-12-08 01:22:58
问题 I tried several variations on main() return; or main() if(); and obtained different errors, the most peculiar of which was /usr/lib/gcc/i686-linux-gnu/4.4.5/../../../../lib/crt1.o: In function `_start': (.text+0x18): undefined reference to `main' collect2: ld returned 1 exit status While it's uncommon for a program to require only one statement, why does main() make it a requirement to have braces? Could someone explain why the error was so peculiar when compiling just int main();? 回答1:

Java: Passing combination of named and unnamed parameters to executable Jar/Main Method

和自甴很熟 提交于 2019-12-08 01:10:39
问题 I am looking for a way so that we can pass both named and unnamed arguments to the main method. Currently I am passing them as follows java -jar myJar param1 param2 param3 and handling them as public static void main( String[] args ) throws IOException { String param1 = args[0]; String param2=args[1]; ..... I must be able to send them and handle them as below in Java so that I can read the values based on their names and need not pass the arguments in the same order everytime I execute the

JavaFX : invoking ' Application.launch(args) ' from a method other than main [duplicate]

回眸只為那壹抹淺笑 提交于 2019-12-07 23:27:19
问题 This question already has answers here : Starting JavaFX from Main method of class which doesn't extend Application (3 answers) Closed 4 years ago . Question Can I call ' Application.launch(args); ' from a method other than main? If so could you provide an example keeping in mind the below context? Background I'm build a learning/teaching, command/text application, that teaches the user about arrays. At the end of the main class, after the major application content has ran, I call '

C++ - Restarting a game by calling the main() function

╄→гoц情女王★ 提交于 2019-12-07 13:53:24
问题 I'm building a small game. One of the input options is to restart the game. The only way I could think of doing this was to call the main function from within the main function int main(int argc, char argv[]) { ... if (input == "restart") { main(argc, argv); } Is this bad form? Will it even work? 回答1: You can't call main() recursively. That's actually undefined behavior. Use a loop instead: int main() { bool restart = false; do { // Do stuff ... // Set restart according some condition inside

QApplication app(argc, argv)

生来就可爱ヽ(ⅴ<●) 提交于 2019-12-07 12:46:39
问题 I noticed that the main.cpp in a Qt application has to contain the following line: QApplication app(argc, argv); I know that argc is the number of command-line arguments, and argv is that array list of command-line arguments. But, the question in my mind is: what are those arguments I'm passing to the constructor and at the same time cannot explicitly see? What is working behind the scences out there? Thanks. 回答1: There are no hidden arguments. You can explicitly see every argument- argc,

Does the main-function in Haskell always start with main = do?

北城余情 提交于 2019-12-07 06:42:32
问题 In java we always write: public static void main(String[] args){...} when we want to start writing a program. My question is, is it the same for Haskell, IE: can I always be sure to declare: main = do, when I want to write code for a program in Haskell? for example: main = do putStrLn "What's your name?" name <- getLine putStrLn ("Hello " ++ name) This program is going to ask the user "What's your name?" the user input will then be stored inside of the name-variable, and "Hello" ++ name will