Python - run external script

Question

Does someone know if I have a script one.py which is written the following way:

if __name__ == '__main__':
    # Do something

And I want to call that main function from another script. How should I do that?

I guess it would be something like (let's say this is launcher.py)

# 'one' stands for import from `one.py` module
import one

if __name__ == '__main__':
    one.main()

The only problem is that I can't call main() this way.

How should this be done?

Answer 1

with file('a.py','rU') as f:
  co=compile(f.read(),'foobar','exec')
  exec co in {'__name__':'__main__'}

Answer 2

Define your script like:

def main():
    # Do something

if __name__ == '__main__':
    # Processing of possible input parameters here and passing to main
    main()

Then you can do

# 'one' stands for import from `one.py` module
import one

if __name__ == '__main__':
    one.main()

Of course you can name the function however you want.