luhn

PL/SQL Check Digit, luhn using MOD 11

由 我只是一个虾纸丫 提交于 2019-12-12 01:39:36
问题 So here is the question: Write code to take in an id and determine if the check digit is correct UPDATED CODE: Set SERVEROUTPUT ON DECLARE val_num NUMBER := '&user_input'; holder NUMBER := 0; y NUMBER := 0; conv_string VARCHAR2(20); BEGIN conv_string := to_char(val_num*10); for x in 1..length(conv_string) loop y := to_number(substr(conv_string, -x, 1)); if mod(x,2) = 0 then y := y * 2; if y > 9 then y := y - 9; end if; end if; holder := holder + y; end loop; dbms_output.put_line ('Check is '|

Are there any valid credit numbers that are initial substrings of other valid credit card numbers?

由 独自空忆成欢 提交于 2019-12-10 18:34:01
问题 I'm trying to implement recognition of a valid credit card number so that I can transition to the next field. Given that credit card numbers come in various lengths, my question is whether I can count on the fact that if I confirm a valid credit card number (via regex and Luhn algorithm use), I won't be ruling out other valid credit card numbers (in terms of both regex/Luhn AND issuance) of greater length. 回答1: Consider Visa where valid PAN lengths are 16 to 19 digits, as the last digit is a

Generate IMEI in python

由 落花浮王杯 提交于 2019-12-06 04:01:29
问题 Hello I am trying to make a function in python to generate valid IMEI numbers so here is my function.The IMEI validation uses the Luhn algorithm so I am trying to implement it in my script. def getImei(): num = '' suma = 0 for i in range(0,13): digit = random.randrange(0,9) suma = suma + digit num = num + str(digit) suma = suma * 9 digit = suma % 10 num = num + str(digit) return num The function however fails to generate valid IMEI numbers. I found an article on wikipedia that tells me how to

Generating Luhn Checksums

由 隐身守侯 提交于 2019-12-03 18:54:59
问题 There are lots of implementations for validating Luhn checksums but very few for generating them. I've come across this one however in my tests it has revealed to be buggy and I don't understand the logic behind the delta variable. I've made this function that supposedly should generated Luhn checksums but for some reason that I haven't yet understood the generated checksums are invalid half of the time. function Luhn($number, $iterations = 1) { while ($iterations-- >= 1) { $stack = 0;

Implementation of Luhn algorithm

由 生来就可爱ヽ(ⅴ＜●) 提交于 2019-12-03 16:13:23
问题 I am trying to implement simple validation of credit card numbers. I read about the Luhn algorithm on Wikipedia: Counting from the check digit, which is the rightmost, and moving left, double the value of every second digit. Sum the digits of the products (e.g., 10: 1 + 0 = 1, 14: 1 + 4 = 5) together with the undoubled digits from the original number. If the total modulo 10 is equal to 0 (if the total ends in zero) then the number is valid according to the Luhn formula; else it is not valid.

Implementation of Luhn algorithm

由 你。 提交于 2019-12-03 05:40:24
I am trying to implement simple validation of credit card numbers. I read about the Luhn algorithm on Wikipedia : Counting from the check digit, which is the rightmost, and moving left, double the value of every second digit. Sum the digits of the products (e.g., 10: 1 + 0 = 1, 14: 1 + 4 = 5) together with the undoubled digits from the original number. If the total modulo 10 is equal to 0 (if the total ends in zero) then the number is valid according to the Luhn formula; else it is not valid. On Wikipedia, the description of the Luhn algorithm is very easily understood. However, I have also

Credit card number validator doesn't work correctly

由 我的梦境 提交于 2019-12-01 10:40:47
def checksum(card_without_check): card_without_check = card_without_check[-1::-1] def numbers(string): return [int(x) for x in string] print(card_without_check) odd_numbers = numbers(card_without_check[0::2]) even_numbers = numbers(card_without_check[1::2]) odd_numbers = [x * 2 for x in odd_numbers] odd_numbers = [x - 9 if x > 9 else x for x in odd_numbers] print(even_numbers) print(odd_numbers) return sum(odd_numbers) + sum(even_numbers) def check(checksum, check): return checksum % 10 == int(check) card_number = input("Enter card number:\n") print(checksum(card_number[:-1])) print("Card is",

Client-side validation of credit cards

由 自闭症网瘾萝莉.ら 提交于 2019-11-30 18:04:30
Does anyone have a library or JavaScript snippet to validate the check digit of credit cards before the user hits Submit? The jQuery Validation Plugin has a method for validating credit card numbers. There are other specific scripts: JavaScript Credit Card Validation Function Credit Card Validation Most of them use the Luhn algorithm . Probably OP doesn't even follow this thread anymore but this may be helpful for someone else: http://jquerycreditcardvalidator.com It checks the card type, validates its length and checks for mod 10 with Luhn algorithm. You can use this snippet to validate 16

Identify card type from card number [duplicate]

由 蹲街弑〆低调 提交于 2019-11-30 12:35:28
问题 This question already has answers here : How do you detect Credit card type based on number? (27 answers) Closed 5 years ago . i have an array of card types that looks something like this var cards = new Array(); cards [0] = {name: "VISA", length: "13,16", prefixes: "4", checkdigit: true}; cards [1] = {name: "VISA_DELTA/ELECTRON", length: "16", prefixes: "417500,4917,4913", checkdigit: true}; however id like to be able to find the card type depending on the card number entered. e.g if they

Identify card type from card number [duplicate]

由 柔情痞子 提交于 2019-11-30 03:15:07
This question already has an answer here: How do you detect Credit card type based on number? 26 answers i have an array of card types that looks something like this var cards = new Array(); cards [0] = {name: "VISA", length: "13,16", prefixes: "4", checkdigit: true}; cards [1] = {name: "VISA_DELTA/ELECTRON", length: "16", prefixes: "417500,4917,4913", checkdigit: true}; however id like to be able to find the card type depending on the card number entered. e.g if they select their card type from a drop down list i.e visa, then the credit card number should start with 4 otherwise when they
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