问题
So here is the question: Write code to take in an id and determine if the check digit is correct
UPDATED CODE:
Set SERVEROUTPUT ON
DECLARE
val_num NUMBER := '&user_input';
holder NUMBER := 0;
y NUMBER := 0;
conv_string VARCHAR2(20);
BEGIN
conv_string := to_char(val_num*10);
for x in 1..length(conv_string) loop
y := to_number(substr(conv_string, -x, 1));
if mod(x,2) = 0 then
y := y * 2;
if y > 9 then
y := y - 9;
end if;
end if;
holder := holder + y;
end loop;
dbms_output.put_line ('Check is '||(11-Mod(holder, 11)));
END luhn;
/
SET SERVEROUTPUT ON
The return is:
SQL> @ loop
Enter value for user_input: 036532
old 2: val_num NUMBER := '&user_input';
new 2: val_num NUMBER := '036532';
Check is 2
It should be 6
回答1:
Before actual execution
SET SERVEROUTPUT ON
to enable SQL*Plus to fetch database output buffer.
Here is solution: https://community.oracle.com/thread/837639?start=0&tstart=0
回答2:
There are lots of different variations of the luhn algorithm, so looking at these implementations and your (I think incomplete) description in the comments I think this may be fairly close to what you are looking for, and gives the correct checksum for 036532 as per your initial question.
Hope it is helpfull
Set SERVEROUTPUT ON
DECLARE
val_num number := '036532';
holder NUMBER := 0;
y NUMBER := 0;
conv_string VARCHAR2(20);
BEGIN
conv_string := to_char(val_num);
FOR X IN 1..LENGTH(CONV_STRING) LOOP
Y := TO_NUMBER(SUBSTR(CONV_STRING, -X, 1));
IF ((X+1) > 10) THEN
Y := Y * 10;
ELSE
Y := Y * (X + 1);
END IF;
IF (Y >= 10) THEN
HOLDER := HOLDER + TO_NUMBER(substr(TO_CHAR(Y), 1, 1)) + TO_NUMBER(substr(TO_CHAR(Y), 2, 1));
ELSE
HOLDER := HOLDER + Y;
END IF;
END LOOP;
HOLDER := MOD(HOLDER, 11);
Holder := 11 - mod(holder, 11);
dbms_output.put_line ('Check is '|| holder);
END luhn;
/
SET SERVEROUTPUT ON
来源:https://stackoverflow.com/questions/34170104/pl-sql-check-digit-luhn-using-mod-11