logical-operators

This question already has an answer here: Short circuit behavior of logical expressions in C in this example 1 answer Aren't the individual expressions in a composite logical AND/OR expression supposed to be evaluated first before the logical operators are applied to their result?Why is ++k untouched in the condition m = ++i && ++j || ++k for the following program : #include<stdio.h> int main() { int i=-3, j=2, k=0, m; m = ++i && ++j || ++k; printf("%d, %d, %d, %d\n", i, j, k, m); return 0; } Output : -2,3,0,1 But I expect the output -2,3,1,1 You should avoid coding such unreadable code. It is

Given this selector: body[class*="page-node-add-"][class~="page-node-edit"] {background:red;} It will match a body which has a class that contains a substring of page-node-add- AND a class which is exactly page-node-edit I would like to say match the first OR the second (but not both). Is it possible? The problem with using a comma: If I have a long selector like: body[class*="page-node-add-"] form.node-form > .field-type-field-collection > table > thead tr th, body[class~="page-node-edit"] form.node-form > .field-type-field-collection > table > thead tr th {...} That is a pain I would have

I happened to know the following code Here is the code, and very simple: var test = 0 || -1 ; console.log(test); then the output in the console is -1 and somehow i am really new into the javascript, all i think of is that the 0 stands for Boolean False in JS ,and so || operator seems to ignore the 0 and assign the value -1 to the variable so am i right ? i just want a confirm gdoron || — expr1 || expr2 (Logical OR) Returns expr1 if it can be converted to true; otherwise, returns expr2. Thus, when used with Boolean values, || returns true if either operand is true; if both are false, returns

I am trying to calculate the Greatest Common Denominator of two integers. C Code: #include <stdio.h> int gcd(int x, int y); int main() { int m,n,temp; printf("Enter two integers: \n"); scanf("%d%d",&m,&n); printf("GCD of %d & %d is = %d",m,n,gcd(m,n)); return 0; } int gcd(int x, int y) { int i,j,temp1,temp2; for(i =1; i <= (x<y ? x:y); i++) { temp1 = x%i; temp2 = y%i; if(temp1 ==0 and temp2 == 0) j = i; } return j; } In the if statement, note the logical operator. It is and not && (by mistake). The code works without any warning or error. Is there an and operator in C? I am using orwellDev-C++

I cannot understand the properties of logical (boolean) values TRUE , FALSE and NA when used with logical OR ( | ) and logical AND ( & ). Here are some examples: NA | TRUE # [1] TRUE NA | FALSE # [1] NA NA & TRUE # [1] NA NA & FALSE # [1] FALSE Can you explain these outputs? To quote from ?Logic : NA is a valid logical object. Where a component of x or y is NA, the result will be NA if the outcome is ambiguous. In other words NA & TRUE evaluates to NA, but NA & FALSE evaluates to FALSE. See the examples below. The key there is the word "ambiguous". NA represents something that is "unknown". So