logical-operators

Element-wise logical OR in Pandas

﹥>﹥吖頭↗ 提交于 2019-11-27 08:48:13
I would like the element-wise logical OR operator. I know "or" itself is not what I am looking for. I am aware that AND corresponds to & and NOT, ~ . But what about OR? deinonychusaur The corresponding operator is | : df[(df < 3) | (df == 5)] would elementwise check if value is less than 3 or equal to 5. If you need a function to do this, we have np.logical_or . For two conditions, you can use df[np.logical_or(df<3, df==5)] Or, for multiple conditions use the logical_or.reduce , df[np.logical_or.reduce([df<3, df==5])] Since the conditions are specified as individual arguments, parentheses

Is A==0 really better than ~A?

落花浮王杯 提交于 2019-11-27 08:15:52
Introduction to problem setup I was doing some benchmarks involving - ~A and A==0 for a double array with no NaNs , both of which convert A to a logical array where all zeros are converted to true values and rest are set as false values. For the benchmarking, I have used three sets of input data – Very small to small sized data - 15:5:100 Small to medium sized data - 50:40:1000 Medium to large sized data - 200:400:3800 The input is created with A = round(rand(N)*20) , where N is the parameter taken from the size array. Thus, N would vary from 15 to 100 with stepsize of 5 for the first set and

The logical && and || operators in JavaScript

旧街凉风 提交于 2019-11-27 08:14:28
问题 I wanted further clarification on something. Consider this: var a = 42; var b = "abc"; var c = null; a || b; // 42 a && b; // "abc" c || b; // "abc" c && b; // null I know that for the || operator, if the test on the first operand is true, the || expression results in the value of the first operand (a or c). If the test is false, the || expression results in the value of the second operand (b). Inversely, for the && operator, if the test is true, the && expression results in the value of the

Multiple conditions in if statement on both sides of the logical operator

无人久伴 提交于 2019-11-27 08:08:04
问题 I was experimenting with having multiple arguments in an if statement on both sides of the logical operator. I first started with the || operator, which worked as expected: var a = 'apple', b = 'banana', c = 'cherry'; if (a == 'banana' || a == 'apple' || b == 'banana' || b == 'apple') { console.log('example 1') // returns } if ((a || b) == 'banana' || (a || b) == 'apple') { console.log('example 2') // returns } if (a == ('apple' || 'banana') || b == ('apple' || 'banana')) { console.log(

The difference between & and && in R

浪子不回头ぞ 提交于 2019-11-27 07:53:53
问题 I have read http://stat.ethz.ch/R-manual/R-devel/library/base/html/Logic.html and the difference between & and && doesn't make sense. For example : > c(1, 2, 3) & c(1,2,3) [1] TRUE TRUE TRUE According to the link this is expected behavior. It is doing an element-wise comparison of the two vectors. So I test again... > c(1, 2, 3) && c(1,2,3) [1] TRUE This also returns what was expected. But then I change a value... > c(1, 2, 3) && c(1,3,3) [1] TRUE Still expected because it short circuits on

What does the exclamation mark mean in an Objective-C if statement?

拈花ヽ惹草 提交于 2019-11-27 07:14:59
问题 I am wondering what the exclamation mark in if(!anObject) means. 回答1: It is the boolean NOT operator also called negation. !true == false; !false == true; 回答2: That is the Logical NOT operator, i.e., if( thisThisIsNotTrue ) { doStuff } . 回答3: It's a C operator, simply meaning "not". So !YES == NO and !NO == YES are both true statements. if (![txtOperator.text isEqualToString: @"+"]) , for example, checks to see if txtOperator.text is NOT equal to @"+". 回答4: If it always adds, then your string

What is the difference between logical and conditional AND, OR in C#? [duplicate]

ぃ、小莉子 提交于 2019-11-27 06:52:38
Possible Duplicate: What is the diffference between the | and || or operators? Logical AND and OR: (x & y) (x | y) Conditional AND and OR: (x && y) (x || y) I've only known about conditional operands up to this point. I know what it does and how to apply it in if-statements. But what is the purpose of logical operands? I prefer to think of it as "bitwise vs. conditional" rather than "logical vs conditional" since the general concept of "logical" applies in both cases. x & y // bitwise AND, 0101 & 0011 = 0001 x | y // bitwise OR, 0101 | 0011 = 0111 x && y // true if both x and y are true x || y

How to solve && operands to logical scalar

佐手、 提交于 2019-11-27 06:52:07
问题 After I run the code in matlab, I encounter this error and unsure how to solve it. How can I solve this problem. Warning: Operands to the || and && operators must be convertible to logical scalar values. Jgray = double(rgb2gray(J)); % Calculate the Gradients [dIx, dIy] = gradient(Jgray); if max(dIx)<=103 && max(dIy)<=100 B = abs(dIy) - abs(dIx); else B = abs(dIx) - abs(dIy); end 回答1: If dIx and dIy are matrices (as opposed to 1-D vectors), max(dIx) and max(dIy) will return vectors. && and ||

Is there actually a reason why overloaded && and || don't short circuit?

廉价感情. 提交于 2019-11-27 06:21:28
The short circuiting behaviour of the operators && and || is an amazing tool for programmers. But why do they lose this behaviour when overloaded? I understand that operators are merely syntactic sugar for functions but the operators for bool have this behaviour, why should it be restricted to this single type? Is there any technical reasoning behind this? Eric Lippert All design processes result in compromises between mutually incompatible goals. Unfortunately, the design process for the overloaded && operator in C++ produced a confusing end result: that the very feature you want from && --

Why is there no logical xor in JavaScript?

限于喜欢 提交于 2019-11-27 06:08:00
Why is there no logical xor in JavaScript? JavaScript traces its ancestry back to C, and C does not have a logical XOR operator. Mainly because it's not useful. Bitwise XOR is extremely useful, but in all my years of programming I have never needed a logical XOR. If you have two boolean variables you can mimic XOR with: if (a != b) With two arbitrary variables you could use ! to coerce them to boolean values and then use the same trick: if (!a != !b) That's pretty obscure though and would certainly deserve a comment. Indeed, you could even use the bitwise XOR operator at this point, though