linked-list

Trying to make linkedlist in C

二次信任 提交于 2019-12-02 21:19:22
问题 I am trying to make a struct in C that is a linked list. I am not really sure what is going wrong though. My errors are: linked.c:6:2: error: unknown type name ‘linkedList’ linked.c: In function ‘makeList’: linked.c:30:2: error: ‘first’ undeclared (first use in this function) linked.c:30:2: note: each undeclared identifier is reported only once for each function it appears in linked.c: In function ‘addToList’: linked.c:36:9: error: used struct type value where scalar is required linked.c:43

Best way to store Country codes, names, and Continent in Java

北战南征 提交于 2019-12-02 21:10:28
I want to have a List or Array of some sort, storing this information about each country: 2 letter code Country name such as Brazil Continent/region of the world such as Eastern Europe, North America, etc. I will classify each country into the region/continent manually (but if there exists a way to do this automatically, do let me know). This question is about how to store and access the countries. For example, I want to be able to retrieve all the countries in North America. I don't want to use local text files or such because this project will be converted to javascript using Google Web

What are real world examples of when Linked Lists should be used?

北战南征 提交于 2019-12-02 20:48:24
Another programmer was mentioning that they haven't found a use case for using a linked list data structure in any professional software in his career. I couldn't think of any good examples off the top of my head. He is mostly a C# and Java developer Can anyone give some examples where this was the correct data structure to solve a particular real world problem? Related: What is a practical, real world example of the Linked List? A real-world example would be a FIFO queue. An simple array-based list is pretty bad for that because you need to add at one end and remove at the other end, and one

Linked list loop detection algorithm

两盒软妹~` 提交于 2019-12-02 20:01:46
I read some interview question online about how would you find if there's a loop in a linked list, and solution ( Floyd's cycle-finding algorithm ) is to have two pointers, one is 2x faster than the other, and check if they meet again. My question is: Why can't I just keep one pointer fixed, just move the other pointer forward by 1 step each time? Because the first (non-moving) pointer might not lie within the loop, so the pointers would never meet. (Remember that a loop may consist of only part of the list.) Because maybe not the complete linkedList is within the loop. For a linked list lasso

C program reversed linked list

旧城冷巷雨未停 提交于 2019-12-02 19:54:02
问题 Im trying to write a program in c that adds big numbers with linked list. I used reverse to add the numbers, but i cant get it to reverse again. It should be used several times(iow, looped to ask numbers until exit) #include <stdlib.h> #include <stdio.h> #include <string.h> #include "function.c" int main() { char n1[500]; int lenSum, len; printf("Welcome! \nThis program performs addition of big whole numbers that can contain upto a maximum of 500 digits."); printf("\nEnter first number: ");

singly linked chain printing c++

半世苍凉 提交于 2019-12-02 19:20:55
问题 I am trying to pick my chain in the format {1,2,3,4,etc}. You can find the header file below which will have the layout of the nodes. I am just confused on how I should go about cycling through my list to print out Item. Any guidance would be greatly appreciated! set.h using namespace std; #include <iostream> class Set { private: struct Node { int Item; // User data item Node * Succ; // Link to the node's successor }; unsigned Num; // Current count of items in the set Node * Head; // Link to

Why is mergesort space complexity O(log(n)) with linked lists?

試著忘記壹切 提交于 2019-12-02 19:17:21
Mergesort on an array has space complexity of O(n), while mergesort on a linked list has space complexity of O(log(n)), documented here I believe that I understand the array case, because we need auxiliary storage when merging the two sub-arrays. But wouldn't a linked list merge sort just merge the two sub-linked lists in place? I think this would have space complexity O(1) for creating a new head. In place merge (no auxiliary storage): public Node merge(Node a, Node b) { Node dummyHead, curr; dummyHead = new Node(); curr = dummyHead; while(a !=null && b!= null) { if(a.info <= b.info) { curr

How to implement an assignment operator in linked list class

假如想象 提交于 2019-12-02 18:52:15
问题 I am having difficulty figuring out how to implement the rule of 5 in my doubly linked list class. I get the concept of them, it's just lost with how to code it. I have attempted the destructor and copy operator, but at a stand still going forward with the rest. Any help/guidance is appreciated, thanks. destructor/copy: ~DList() { Node* current = front_; while (current != back_) { front_ = front_->next_; delete current; current = front_; } } // copy ctor DList(const DList& rhs) { const Node*

Why is a LinkedList Generally Slower than a List?

爱⌒轻易说出口 提交于 2019-12-02 18:46:27
I started using some LinkedList’s instead of Lists in some of my C# algorithms hoping to speed them up. However, I noticed that they just felt slower. Like any good developer, I figured that I should do due diligence and verify my feelings. So I decided to benchmark some simple loops. I thought that populating the collections with some random integers should be sufficient. I ran this code in Debug mode to avoid any compiler optimizations. Here is the code that I used: var rand = new Random(Environment.TickCount); var ll = new LinkedList<int>(); var list = new List<int>(); int count = 20000000;

print() function that prints the contents of each element of your list

China☆狼群 提交于 2019-12-02 18:41:15
问题 Basically i'm trying to write a print statement that will allow me to print the elements per line as a println as the output when i run the driver.java. And for the life of me i cannot figure out how to do it. Any help will be appreciated. here is the driver.java public class Driver { public static void main(String args[]){ LList<String> s_list = new LList<String>(); s_list.insert("New York, 8.4M"); s_list.insert("Los Angeles 3.8M"); s_list.insert("Chicago, 2.7M"); s_list.insert("Houston, 2