linked-list

I'm trying to write a method that merges a doubly linked list in an alternating fashion. So if we have two int lists (0,1,2,3) and (4,5,6), we'd just have one final list of (0,4,1,5,2,6,3). Each list has a head, a tail, a next, and a prev pointer. Its hurting my mind to try to figure out where to start or how this would work. I've tried to trace it on paper, but no progress. Can anyone guide me in the right direction? Whats a good way to 'picture' this or plan for it, as I dont even know where to start. Create a third, empty list (called the "result list"). Loop while there are still elements

I have a query in classic ASP like this: sql_test="select * from Openquery(it_test, 'select * from IT_DB.HOST') the problem is that I want to test the connection to the linked server before executing it and getting an error on the page. If the connection to the linked server doesn't work (ex: db down) I can execute a query on the local SQL server 2000 db avoiding getting an error on the page. I tend to use this code... 'GetDataSet error columns... const C_ERROR = "ERROR" 'Used when an error is generated - to be fed to the comsuming routine const C_NO_DATA = "NO_DATA" 'Used when no data is

So I am creating a linked list in a separate function, and when I print out the linked list within the function, it seems everything is fine. However; when I go to main and try to access the linked list with printf I get a segmentation fault and am confused exactly why. void createLL(struct node* head, struct node* curr, char ch, int number){ //lowest digit is the head while (((scanf(" %c",&ch)) >= 0)){ curr = (struct node*)malloc(sizeof(struct node*)); //allocate space number = ch - '0' ; //convert char to number curr->data = number; curr->next = head; head = curr; } curr = head; /

Here's the problem. Write a function for merging multiple (sorted) linked lists into one sorted linked list. This function should access the elements through Iterator interface (do not access elements through the linked list directly). The arguments to the merge procedure are an array of Iterators and the size of the array. The return value should be another Iterator with an underlying List implementation. Steps: (1) Implement linked list with iterator interface. Define the Element in the list as below: typedef struct { int idno; char name[25]; float marks; } Element; (a) List createList(); (b

I have implemented a simple linked list in C language, but can it be implemented without using double-pointer(**).I want to implement same program by using only single pointers. #include <stdio.h> #include <stdlib.h> struct node { int data; struct node *next; }; void push(struct node** head_ref, int new_data) { struct node* new_node = (struct node*) malloc(sizeof(struct node)); new_node->data = new_data; new_node->next = (*head_ref); (*head_ref) = new_node; } void append(struct node** head_ref, int new_data) { struct node* new_node = (struct node*) malloc(sizeof(struct node)); struct node

I want to create a linked list using Cypher over REST. If I create the head of the list using the following query: MERGE (headNode:HEAD {list:"mylist"}) WITH headNode MERGE headNode-[:LINK]->(headNode) RETURN headNode And then do the insert using this query: MERGE (headNode:HEAD {list:"mylist"})-[old:LINK]->after DELETE old CREATE headNode-[:LINK]->(newNode:LINKNODE { number : {nodeNumber} })-[:LINK]->after Then everything is fine as long as I don't run multiple insert queries in parallel. But when I do I start to get consequences that are bad. I either get (depending on the timing) an error

Can you suggest an algorithm that find all pairs of nodes in a link list that add up to 10. I came up with the following. Algorithm: Compare each node, starting with the second node, with each node starting from the head node till the previous node (previous to the current node being compared) and report all such pairs. I think this algorithm should work however its certainly not the most efficient one having a complexity of O(n2). Can anyone hint at a solution which is more efficient (perhaps takes linear time). Additional or temporary nodes can be used by such a solution. If their range is