lead

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 4 years ago . Improve this question im trying to update table temp(F4) result from bottom to top. Is it while-loop every row and update can be order by? Thanks! 回答1: Assuming ROW is a positive integer then you can use (demo) WITH T1 AS ( SELECT *, MIN(CASE WHEN F4 <> 0 THEN CONCAT(FORMAT([ROW],'D10'),[F4]) END)

问题 I am having a very hard time leading or lagging an entire dataframe. What I am able to do is shifting individual columns with the following attempts but not the whole thing: require('DataCombine') df_l <- slide(df, Var = var1, slideBy = -1) using colnames(x_ret_mon) as Var does not work, I am told the variable names are not found in the dataframe. This attempt shifts the columns right but not down: df_l<- dplyr::lag(df) This only creates new variables for the lagged variables but then I do

问题 I am having a very hard time leading or lagging an entire dataframe. What I am able to do is shifting individual columns with the following attempts but not the whole thing: require('DataCombine') df_l <- slide(df, Var = var1, slideBy = -1) using colnames(x_ret_mon) as Var does not work, I am told the variable names are not found in the dataframe. This attempt shifts the columns right but not down: df_l<- dplyr::lag(df) This only creates new variables for the lagged variables but then I do

问题 How do I add a Zoho CRM Lead with the Zoho CRM v2 API, using simple curl connections? The docs are not very clear on not only how to add a lead, but how to even get the proper oAuth token to create the lead. 回答1: The docs are not very clear on this process. So, I'll simplify this. The biggest hurdle are the steps to get the refresh token. Once you have that, you can generate countless access tokens that are used to make the actual API calls. How To Get Your Refresh Token Login to your Zoho

问题 data=data.frame("Student"=c(1,1,1,2,2,2,3,3,3,4,4,4,5,5,5), "Grade"=c(5,6,7,3,4,5,4,5,6,8,9,10,2,3,4), "Pass"=c(NA,0,1,0,1,1,0,1,0,0,NA,NA,0,0,0), "NEWPass"=c(0,0,1,0,1,1,0,1,1,0,0,0,0,0,0), "GradeNEWPass"=c(7,7,7,4,4,4,5,5,5,10,10,10,4,4,4), "GradeBeforeNEWPass"=c(6,6,6,3,3,3,4,4,4,10,10,10,4,4,4)) I have a data.frame called data. It has column names Student, Grade and Pass. I wish to do this: NEWPass: Take Pass and for every Student fill in NA values with the previous value. If the first

问题 I'm trying to replicate the following formula in R: Xt = Xt-1 * b + Zt * (1-b) I'm using the following code t %>% mutate(x= ifelse(week == 1, z, NaN)) %>% # Initial value for the first lag mutate(x= ifelse(week != 1, lag(x,1 ,default = 0) * b + z, z) But I get all NaN except from the second element. z b x (dbl) (dbl) (dbl) 1 168.895 0.9 168.8950 2 20.304 0.9 131.7472 3 14.943 0.9 NA 4 11.028 0.9 NA 5 8.295 0.9 NA 6 8.024 0.9 NA 7 6.872 0.9 NA 8 7.035 0.9 NA 9 4.399 0.9 NA 10 4.158 0.9 NA This

问题 I'm trying to replicate the following formula in R: Xt = Xt-1 * b + Zt * (1-b) I'm using the following code t %>% mutate(x= ifelse(week == 1, z, NaN)) %>% # Initial value for the first lag mutate(x= ifelse(week != 1, lag(x,1 ,default = 0) * b + z, z) But I get all NaN except from the second element. z b x (dbl) (dbl) (dbl) 1 168.895 0.9 168.8950 2 20.304 0.9 131.7472 3 14.943 0.9 NA 4 11.028 0.9 NA 5 8.295 0.9 NA 6 8.024 0.9 NA 7 6.872 0.9 NA 8 7.035 0.9 NA 9 4.399 0.9 NA 10 4.158 0.9 NA This

问题 I have a table that is used to log events. Two types specifically : ON and OFF. There are sometimes overlapping log entries as there can be 2 simultaneous devices logging. This is not crucial, as the end report should give a [mostly] correct overview of ON -> OFF periods. Below is a sample, with the 3rd column just for illustration: It does not exist. ActionTaken ID ID_of_next_OFF Switched ON 1 3 Switched ON 2 6 Switched OFF 3 Switched ON 4 7 Switched ON 5 8 Switched OFF 6 Switched OFF 7

问题 I have to create lead and lag variables like below in R Suppose i have a dataframe which has details about a customer's visit to any store... CustomerID Dateofvisit 1 1/2/2013 1 1/3/2013 1 1/7/2013 2 1/9/2013 2 1/14/2013 2 2/14/2013 3 1/4/2013 3 1/5/2013 As we can see, there are 3 customers with different visit dates.. When i apply a lag function on the above...(i created my own function,)..it becomes like below: CustomerID Dateofvisit Laggeddate 1 1/2/2013 - 1 1/3/2013 1/2/2013 1 1/7/2013 1