laravel-4

问题 I'm a beginner with Composer, so I know little about it and have little experience with web application development. I was reading the Nettuts+ Tutorial, and have a basic question about Composer. { "require": { "laravel/framework": "4.0.*", "way/generators": "dev-master", "twitter/bootstrap": "dev-master", "conarwelsh/mustache-l4": "dev-master" }, "require-dev": { "phpunit/phpunit": "3.7.*", "mockery/mockery": "0.7.*" }, "autoload": { "classmap": [ "app/commands", "app/controllers", "app

问题 I am trying to export a database table using Laravel as a csv file. I would like the user to be able to select the Export as CSV button and download the table as a csv file. Currently I've gotten this code but It is not working: my button: <a href="/all-tweets-csv" class="btn btn-primary">Export as CSV</a> my route: Route::get('/all-tweets-csv', function(){ $table = Tweet::all(); $filename = "tweets.csv"; $handle = fopen($filename, 'w+'); fputcsv($handle, array('tweet text', 'screen name',

问题 I've been reading about this feature: http://laravel.com/docs/html#form-model-binding And it looks really neat, but there are couple of things that I'm not certain about. Do I need to put any code in the controller action to process this form? What does that look like? The model (User) I want to bind in my form has a separate table for addresses. So I want to be able to fill out the User model's fields, but also the fields for the related Address model. Can I do that with form-model-binding,

问题 I have the following table: group_pages in mysql database with page name route name : id name route -------------------- 0 About about 1 Contact contact 2 Blog blog what I am trying to do is to create dynamic routes in my : routes.php ? Where if I go to for example: /about it will go to AboutController.php ( which will be created dynamically) is that possible? is it possible to create a dynamic controller file? I am trying to create dynamic pages routes that links to a controller example i

问题 I'm stuck on a simple task. I just need to order results coming from this call $results = Project::all(); Where Project is a model. I've tried this $results = Project::all()->orderBy("name"); But it didn't work. Which is the better way to obtain all data from a table and get them ordered? 回答1: You can actually do this within the query. $results = Project::orderBy('name')->get(); This will return all results with the proper order. 回答2: You could still use sortBy (at the collection level)

问题 Laravel 3 had a File::mime() method which made it easy to get a file's mime type from its extension: $extension = File::extension($path); $mime = File::mime($extension); On upgrading to Laravel 4 I get an error: Call to undefined method Illuminate\Filesystem\Filesystem::mime() I also can't see any mention of mime types in the Filesystem API docs. What's the recommended way to get a file's mime type in Laravel 4 (please note this is not a user-uploaded file)? 回答1: One solution I've found is to

问题 I want to get all the rows from a table through an expression: table.date <= 2014-07-10 But if the column contains a datetime let's say: 2014-07-10 12:00:00 But if I do: where('date', '<=', $date) it won't get the row. I guess this is because $date = 2014-07-10 which makes MySQL assume that it is 2014-07-10 00:00:00. In regular MySQL I would just do where DATE(date) <= $date What would be the equivalent using Laravel's Eloquent? 回答1: Laravel 4+ offers you these methods: whereDay() ,

问题 How can I create a Mediumblob within the Laravel schema builder ? In the docs it says : $table->binary('data'); // BLOB equivalent to the table But I need a MediumBlob otherwise the images get truncated at 64K; we are running MySQL. I know that Laravel's schema builder is DB agnostic, but is there a way to avoid the "native way" and if not how can i create a Mediumblob column ? 回答1: You can't. This issue suggests using raw queries to create such columns, so you should do something like this

问题 I have recently started working with Laravel and Eloquent, and was wondering about the lack of a find or create option for models. You could always write, for example: $user = User::find($id); if (!$user) { $user = new User; } However, is there not a better way to find or create? It seems trivial in the example, but for more complex situations it would be really helpfully to either get an existing record and update it or create a new one. 回答1: Below is the original accepted answer for:

问题 Is there a way to generate stored MYSQL procedures in a Laravel 4 migration? For example, here's a simple procedure generation query stored as a string (via a Heredoc) $query = <<<SQL DELIMITER $$ DROP PROCEDURE IF EXISTS test$$ CREATE PROCEDURE test() BEGIN INSERT INTO `test_table`(`name`) VALUES('test'); END$$ DELIMITER ; SQL; DB:statement(DB::RAW($query)); When Running this in a migration's up() function I get this error: 回答1: There are two major problems with your code DELIMITER is not a