keys

To ignore duplicate keys during 'copy from' in postgresql

匿名 (未验证) 提交于 2019-12-03 01:05:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have to dump large amount of data from file to a table PostgreSQL. I know it does not support 'Ignore' 'replace' etc as done in MySql. Almost all posts regarding this in the web suggested the same thing like dumping the data to a temp table and then do a 'insert ... select ... where not exists...'. This will not help in one case, where the file data itself contained duplicate primary keys. Any body have an idea on how to handle this in PostgreSQL? P.S. I am doing this from a java program, if it helps 回答1: Use the same approach as you

find Key for value in python when key associated with multiple values

匿名 (未验证) 提交于 2019-12-03 01:05:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: For a dictionary of the type { 'key1' : [ 'v1' , 'v2' , 'v3' , ...], 'key2' : [ 'v2' , 'v4' , ...], ... } How do I Find any key associated with a value v Print that k:[value set] pair to a new dictionary 回答1: # answer to 1st question keys_with_value = [ k for k , v in old_dict . iteritems () if "whatever_value" in v ] # answer to 2nd question new_dict = {} for k in keys_with_value : new_dict [ k ] = old_dict [ k ] Example: >>> old_dict = { 'key1' :[ 'v1' , 'v2' , 'v3' ], 'key2' :[ 'v2' , 'v4' ]} >>> keys_with_value = [ k for k , v

PHP replace a random word of a string

匿名 (未验证) 提交于 2019-12-03 01:01:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I want to replace one random word of which are several in a string. So let's say the string is $str = 'I like blue, blue is my favorite colour because blue is very nice and blue is pretty' ; And let's say I want to replace the word blue with red but only 2 times at random positions. So after a function is done the output could be like I like red , blue is my favorite colour because red is very nice and blue is pretty Another one could be I like blue , red is my favorite colour because blue is very nice and red is pretty So I want

GTK3 function keys; which are consumed (and unusable from my GTK app)?

匿名 (未验证) 提交于 2019-12-03 01:00:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: FWIW, the exact program motivating this question is (on Linux/Debian/Sid/x86-64) my bismon on github, commit d43a75fb9f8e13 . GTK3 is 3.22.24. If you need to try it, build it with make and run ./bismon . It is in alpha stage, and still not interesting to others than me. It is some kind of DSL interpreter with a GTK interface and a persistent heap. If you want something to appear, click to focus on the middle widget, type the_system there followed by Ctrl Return , but that is not relevant for this question. I am successfully able, with

ORA-02298 Parent Keys Not Found?

匿名 (未验证) 提交于 2019-12-03 01:00:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I've been stuck on this for ages as every time I try it - it comes up with the following error: Cannot Validate - parent keys not found. Here's the code ( http://i.imgur.com/6JBzTiM.jpg ): I can create the Primary Key in the Employees table and assign it to EmployeeId. But when trying to add that as a foreign key in the WorkPackages table (using the code below) ALTER TABLE WORKPACKAGES ADD FOREIGN KEY (EMPLOYEEID) REFERENCES EMPLOYEES (EMPLOYEEID); it keeps on coming up with the validation error. What am I doing wrong? 回答1: ALTER TABLE

Using unused primary keys [duplicate]

匿名 (未验证) 提交于 2019-12-03 01:00:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Possible Duplicate: How to reuse auto_increment values? I have a table which has an auto-increment ID -column as it's primary key , but am running into the 'problem' that whenever a key is deleted, that creates a gap. This is of course not a problem as such, but it doesn't look very neat. Is there an easy way to get MySQL to use the first available unused ID -number, instead of the ' next ' number in the sequence ? I hope my question makes sense. 回答1: What you want to accomplish, IMHO, is not a very good idea. Take this into account; there

List All Redis Databases

匿名 (未验证) 提交于 2019-12-03 00:59:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I ran this command to access my redis server. telnet 127.0.0.1 6379 Now, I want to show all of my databases. Please tell me this command. Thanks. 回答1: There is no command to do it (like you would do it with MySQL for instance). The number of Redis databases is fixed, and set in the configuration file. By default, you have 16 databases. Each database is identified by a number (not a name). You can use the following command to know the number of databases: CONFIG GET databases 1) "databases" 2) "16" You can use the following command to list

TypeError: 'dict_keys' object does not support indexing

匿名 (未验证) 提交于 2019-12-03 00:59:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: def shuffle ( self , x , random = None , int = int ): """x, random=random.random -> shuffle list x in place; return None. Optional arg random is a 0-argument function returning a random float in [0.0, 1.0); by default, the standard random.random. """ randbelow = self . _randbelow for i in reversed ( range ( 1 , len ( x ))): # pick an element in x[:i+1] with which to exchange x[i] j = randbelow ( i + 1 ) if random is None else int ( random () * ( i + 1 )) x [ i ], x [ j ] = x [ j ], x [ i ] When I run the shuffle function it raises

jQuery CouchDB - filter keys for view

匿名 (未验证) 提交于 2019-12-03 00:57:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am using the javascript library which comes bundled with couchdb to query the database. On a side note here is a good overview of the functionality it provides, with a lot of good examples. It is possible to filter the results from a view by specifying the key values to return. This is easily done with a query string ( documentation ) but how do I do it with the javascript API? This is how I am doing it with a query string (please note that the JSON portion of the key-value-pair would need to be HTML encoded): http://localhost:5984

Python selenium send_keys emoji support

匿名 (未验证) 提交于 2019-12-03 00:57:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am trying to use selenium's send_keys to send emoji characters to a text box with the following python code. browser = webdriver.Chrome(chrome_options=options) browser.get("https://www.google.co.in") time.sleep(5) working = browser.find_element_by_id('lst-ib') text = u'Python is ?' working.send_keys(text) I am getting the following error. Traceback (most recent call last): File "smiley.py", line 30, in <module> working.send_keys(text) File "C:\Python27\lib\site-packages\selenium\webdriver\remote\webelement.py", line 347, in send_keys self.