keyerror

Creating variables from list and accessing globally

倖福魔咒の 提交于 2021-02-17 05:22:05
问题 I’m writing a program that pulls a list of departments from a database. I want to avoid hardcoding this since the list may change. I want to create a variable for each department to populate questions into a GUI. The problem I have is that I can create variables from the database list using the vars() function. I’m then storing the list of variable names so I can reference them elsewhere in my program. As long as I do everything in the same def, there is no problem. But I don’t know how to

KeyError('pandas._libs.interval') when opening a dataframe in Spyder

旧时模样 提交于 2021-02-11 12:46:11
问题 When I try to click on data frames in the Variable Explorer in Spyder, I get the following error: This happens with all data frames (I tried making my own). As a side note, functions like numpy.sum and .describe() don't output anything, but I'm unsure if this is related to the KeyError. Thank you! 回答1: Add pandas to the packages option in setup.py module. Here is the code snippet for setup.py from setuptools import setup APP = ['automating_finances0.py'] DATA_FILES = [] OPTIONS = {'packages':

KeyError when formatting locals

本小妞迷上赌 提交于 2021-02-08 11:55:52
问题 I'm facing a KeyError I can't explain or understand. I have a notebook, in which I define a variable PREFIX in a cell: PREFIX = "/home/mavax/Documents/info/notebook/log_study" which is simply a path to a folder containing logs, so people using the notebook just need to change the path if they want to execute the code below. Then, later (quite a bunch of cells beneath), I use it, without any problem: for basename in ["log_converted_full.txt", "log_converted_trimmed.txt"]: entries = load_log

Python dict.get('key') versus dict['key'] [duplicate]

半腔热情 提交于 2021-02-07 04:56:24
问题 This question already has answers here : Why dict.get(key) instead of dict[key]? (10 answers) Closed 4 years ago . Why does this throw a KeyError: d = dict() d['xyz'] But this does not? d = dict() d.get('xyz') I'm also curious if descriptors play a role here. 回答1: This is simply how the get() method is defined. From the Python docs: Return the value for key if key is in the dictionary, else default. If default is not given, it defaults to None, so that this method never raises a KeyError. The

KeyError on relation field in Django-REST

 ̄綄美尐妖づ 提交于 2021-01-28 18:18:11
问题 I have the following models: class ProductColor(models.Model): color_title = models.CharField(max_length=50) class BasicProduct(models.Model): product_title = models.CharField(max_length=150) product_desc = models.TextField() product_price = models.FloatField(default=10.0) # Describes what colors are available for this product product_colors = models.ManyToManyField(ProductColor) class BasicCartItem(models.Model): cart_product = models.ForeignKey(BasicProduct) cart_color = models.ForeignKey

getting raise KeyError(key) KeyError: 'SECRET_KEY' with django on production settings

那年仲夏 提交于 2020-12-29 09:48:14
问题 I've 2 separate settings files for production and development and a common base.py settings file base.py SECRET_KEY = r"!@#$%^&123456" prod.py from .base import * SECRET_KEY = os.environ['SECRET_KEY'] manage.py #!/usr/bin/env python import os import sys if __name__ == "__main__": os.environ.setdefault("DJANGO_SETTINGS_MODULE", "project.settings.dev") from django.core.management import execute_from_command_line execute_from_command_line(sys.argv) When I enter this in terminal: python manage.py

getting raise KeyError(key) KeyError: 'SECRET_KEY' with django on production settings

◇◆丶佛笑我妖孽 提交于 2020-12-29 09:47:05
问题 I've 2 separate settings files for production and development and a common base.py settings file base.py SECRET_KEY = r"!@#$%^&123456" prod.py from .base import * SECRET_KEY = os.environ['SECRET_KEY'] manage.py #!/usr/bin/env python import os import sys if __name__ == "__main__": os.environ.setdefault("DJANGO_SETTINGS_MODULE", "project.settings.dev") from django.core.management import execute_from_command_line execute_from_command_line(sys.argv) When I enter this in terminal: python manage.py