jetty

有哪些方法 实现服务启动之后,马上执行相关操作? 方式一 :@PostConstruct 对类的要求 无,普通的java bean即可 例如: /*** * 执行完构造方法之后就会执行该方法 */ @PostConstruct public void init() { System.out.println("初始化字典"); refresh2(); } 执行时机 类实例化之后 方式二: 实现org.springframework.context.ApplicationListener 的onApplicationEvent方法 对类的要求 必须使用SpringMVC的注解@Configuration , 实现org.springframework.context.ApplicationListener 的onApplicationEvent方法 示例 例如: /*** * Spring容器加载完成触发,可用于初始化环境，准备测试数据、加载一些数据到内存 * @param contextRefreshedEvent */ @Override public void onApplicationEvent(ContextRefreshedEvent contextRefreshedEvent) { configType=getProperty("ConfigType");

I have a servlet filter which I want to map to http://127.0.0.1:8888/ in Jetty. I have put a servlet filter mapping with url pattern /* . However, the filter is not called. I also tried with / mapping. It does not work either. How is this caused and how can I solve it? If you name your war root.war it will be deployed to the root / context. http://wiki.eclipse.org/Jetty/Howto/Deploy_Web_Applications You can redirect requests from "/" to "/urlToRedirect" and handle "/urlToRedirect" by special servlet. Like in example: public static void main(String[] args) throws Exception { Servlet frontend =

How can i force Jetty to open all deployed webapps starting from specific virtual host like test.localhost:8080/myapp instead of localhost:8181/myapp ? Here's snippet from jetty.xml: <Call name="addConnector"> <Arg> <New class="org.eclipse.jetty.server.nio.SelectChannelConnector"> <Set name="host"> <Property name="jetty.host"/> </Set> <Set name="port"> <Property name="jetty.port" default="8181"/> </Set> ... ... i tried to play with jetty.host value but still no success. :( How to? To LISTEN on a specific network interface, you specify that interface either via its IP address (IPv4 or IPv6) or