interpolation

问题 I created in a playground a uibezierpath added manually values and it works fine. The results is : Now my goal is to smooth the curve and remove these "sharp" corners. I'm thinking on a interpolation function but not sure. Below my actual code : //: Playground - noun: a place where people can play import Foundation import UIKit import CoreGraphics import QuartzCore class DemoView: UIView { override func draw(_ rect: CGRect) { let origin = CGPoint(x: frame.size.width / 2, y: frame.size.height

问题 Is there an 'easy way' to grab two rows of data from a table, and add rows with values 'in-between'? I want to grab a latitude, a longitude and a timestamp from each row. Compare the timestamp to the one from the previous row, and interpolate new rows if the timestamp is bigger than my minimum...grab two rows 1 minute apart and add rows for every 10 seconds... Is using a stored procedure the best way to go about this? Easiest? Currently using mySql and PHP... 回答1: I would just grab the data

问题 I have 3d data produced from mesh points. The structure that was meshed is complex enough that interpolation using griddata is lacking. Specifically, there are regions without data points which are being given values by griddata that are not the fill_value. I need these hollow regions to have the value of 0.0, which I set fill_value to. A simplified version of this is illustrated below: The area occupied by the cylinder has no data points but the rest of the cube volume does. There will be

问题 I have an input data set of 32 points. Now I want to convert these 32 points to 240 points by averaging the data over the points. I thought of plotting the 32 sample points which I have and then by approximately plotting the curve and taking data at a higher sampling frequency so as to obtain 240 points. I am not able to understand how to do this in MATLAB. I took help from some sources, but I was not able to come up with any solution. How can this be done? In short, I want to convert 'x'

问题 I try to do a thing that should be nothing more than a two-dimensional, linear interpolation but currently I fail finding the correct approach. To describe the problem a bit simplified: there is a drawing area with a size of 3000x3000 pixels where I have to draw e.g. a horizontal line. To do that I'm drawing dots or short lines from every pixel position to the next pixel position which then forms a line. Now a correction has to be applied to the whole thing where correction information can be

问题 Basically I have a large (could get as large as 100,000-150,000 values) data set of 4-byte inputs and their corresponding 4-byte outputs. The inputs aren't guaranteed to be unique (which isn't really a problem because I figure I can generate pseudo-random numbers to add or xor the inputs with so that they do become unique), but the outputs aren't guaranteed to be unique either (so two different sets of inputs might have the same output). I'm trying to create a function that effectively models

问题 I need to have a custom interpolator for the Gallery widget. I checked the documentation and source codes but couldn't find anywhere to specify/override the default animation behavior. Maybe some of you might know? Thanks! UPDATE: i ended up just extend Gallary widget and implemented my own animation 回答1: Solution: i ended up just extend Gallary widget and implemented my own animation 来源： https://stackoverflow.com/questions/6489744/is-there-a-way-to-override-android-gallery-widget-default

问题 I have two data points on a 2-D image grid and the value of some quantity of interest at these two points is known. For example: Let us consider the point being x=(2,2) . Then considering a 4-grid neighborhood we have points x_1=(1,2), x_2=(2,3), x_3=(3,2), x_4=(2,1) as neighbours of x . Suppose the value of some quantity of interest at these points be y=5, y_1=7, y_2=8, y_3= 10, y_4 = 3 . Through interpolation, I want to find y at a sub-pixel value, say at (2.7, 2.3) . The above problem can

问题 I have a question about the interp1 function in MATLAB. Let x be in the range [1, 1024]. However, the following: yi = interp1(x, y, 1024); returns NaN . I've checked my program several times and nothing seems wrong but the result is still weird to me. I'd be thankful if anyone could help. 回答1: I'm pretty sure that you're not getting to 1024 but rather some value just less like 1023.999999999945435 Try out this very contrived example: x = 1:10; y = 1:10; interp1(x, y, 10) %This works, returns

问题 EDIT: Code edited to produce results consistent with Matlab. See below. I am converting Matlab scripts to Python and the linear interpolation results are different in certain cases. I wonder why and if there is any way to fix this? Here is the code example in both Matlab and Python and the resulting output (Note that t just so happens to be equal to tin in this case): MATLAB: t= [ 736696., 736696.00208333, 736696.00416667, 736696.00625, 736696.00833333, 736696.01041667, 736696.0125]; tin =[