int64

来源： https://stackoverflow.com/questions/38297160/bit-field-larger-than-64-shifts-in-swift

来源： https://stackoverflow.com/questions/63468445/i-can-i-manually-specify-bson-type-in-mongodbs-nodejs-driver-i-am-getting-erro

问题 Hey guys I want to get some memory from a process that I already know with CheatEngine. I defined a region that I want to scan (0x190D186FF->0x190D1870A) but the address is too big to be stored in a simple int. That's why I use an __int64 but with that modification ReadProcessMemory doesn't seems to handle the address anymore. When I compile I got 3 warnings for VirtualProtectEx and ReadProcessMemory: cast to pointer from integer of different size How can I read really big address from the

问题 The problem with the following code: var x uint64 = 18446744073709551615 var y int64 = int64(x) is that y is -1 . Without loss of information, is the only way to convert between these two number types to use an encoder and decoder? buff bytes.Buffer Encoder(buff).encode(x) Decoder(buff).decode(y) Note, I am not attempting a straight numeric conversion in your typical case. I am more concerned with maintaining the statistical properties of a random number generator. 回答1: Seeing -1 would be

问题 I have an open-source codebase that is written in both C and C++. I'm looking for an integer type that is guaranteed to be at least 64 bits wide, which can be reliably compiled on most OS X (Intel, 64-bit) and Linux boxes with open-source C and C++ compilers, without too much extra work on the end user's part. Windows and 32-bit client support are not important at this time. I did some testing on OS X, and the latest GCC that ships with the developer tools does not support C+11 mode (and

问题 I'm trying to parse a json stream in Go. I've created a simplified example: package main import ( "encoding/json" "fmt" ) var d = []byte(`{ "world":[{"data": 2251799813685312}, {"data": null}]}`) type jsonobj struct{ World []World } type World struct{ Data int64 } func main() { var data jsonobj jerr := json.Unmarshal(d, &data) fmt.Println(jerr) } this will give me go run testmin.go json: cannot unmarshal null into Go value of type int64 I've found a nullable int64 in the sql package, but json

问题 Can someone explain to me (in detail) how to multiply two __int64 objs and check if the result will fit in __int64. Note: Do not use any compiler or processor dependent routines. 回答1: not assuming a and b are positive: __int64 a,b; //... __int64 tmp_result = abs(a) * abs(b) ; if ( ( a && b ) && ( ( tmp_result < abs(a) || tmp_result < abs(b) ) || ( tmp_result / abs(a) != abs(b)) || ( a == TYPE_MIN && b != 1) || ( b == TYPE_MIN && a != 1) ) ) std::cout << "overflow"; __int64 result = a * b;

问题 How do I convert 64-bit hexadecimal strings in R? > library(int64) > as.int64("7f2d36a2a000") [1] NA Warning message: In as.int64("7f2d36a2a000") : NAs introduced > as.int64("0x7f2d36a2a000") [1] NA Warning message: In as.int64("0x7f2d36a2a000") : NAs introduced 回答1: For a number that large, you'll need to load a package that supports representations of arbitrarily large numbers. Rmpfr is one example: library(Rmpfr) ## Check that it works as expected on smaller numbers: strtoi("ff", base=16)

问题 I tried: test_image = tf.convert_to_tensor(img, dtype=tf.float32) Then following error appears: ValueError: Tensor conversion requested dtype float32 for Tensor with dtype int64: 'Tensor("test/ArgMax:0", shape=TensorShape([Dimension(None)]), dtype=int64)' 回答1: You can cast generally using: tf.cast(my_tensor, tf.float32) Replace tf.float32 with your desired type. Edit : It seems at the moment at least, that tf.cast won't cast to an unsigned dtype (e.g. tf.uint8 ). To work around this, you can

问题 How to convert __int64 to long in Windows (MSVC8 & MSVC6)? Will a normal typecasting work? Also, how about converting long to __int64? If the long is a negative value, will it work? Note - I am talking of a scenario in which the __int64 variable will always contain a value which will not be more than 32 bits long. 回答1: 1. Convert long to __int64 Acorrding to MSDN on the __int64 keyword: The _ _int64 keyword declares a new type, a 64-bit (8-byte) integer. As with the int, short, and long types