inputstream

问题 According to changes for kitakt 4.4 there were some problems with playing shoutcast streams (those returning "ICY" instead of "HTTP/1.x" response). So solution for kitkat was to reregister "icy" protocol prefix in JVM once before we opened a stream by this: try { java.net.URL.setURLStreamHandlerFactory( new java.net.URLStreamHandlerFactory(){ public java.net.URLStreamHandler createURLStreamHandler( String protocol ) { Log.d( LOG, "Asking for stream handler for protocol: '" + protocol + "'" );

问题 This question already has answers here : How to read a large text file line by line using Java? (21 answers) Closed 4 months ago . I use InputStream to read some data, so I want to read characters until new line or '\n'. 回答1: You should use BufferedReader with FileInputStreamReader if your read from a file BufferedReader reader = new BufferedReader(new FileInputStreamReader(pathToFile)); or with InputStreamReader if you read from any other InputStream BufferedReader reader = new

问题 Looking through the documentation and source code I don't see a clear way to do this. Curious if I'm missing something. Say I receive an InputStream from a server response. I create a JsonParser from this InputStream. It is expected that the server response is text containing valid JSON, such as: {"iamValidJson":"yay"} However, if the response ends up being invalid JSON or not JSON at all such as: Some text that is not JSON the JsonParser will eventually throw an exception. In this case, I

问题 I need to convert numerical values into byte arrays. For example, to convert a long to a byte array, I have this method: public static byte[] longToBytes(long l) { ByteBuffer buff = ByteBuffer.allocate(8); buff.order(ByteOrder.BIG_ENDIAN); buff.putLong(l); return buff.array(); } It's pretty straightforward - take a long, allocate an array that can hold it, and throw it in there. Regardless of what the value of l is, I will get an 8 byte array back that I can then process and use as intended.

问题 Should be pretty simple: I have an InputStream where I want to peek at (not read) the first two bytes, i.e. I want the "current position" of the InputStream to stil be at 0 after my peeking. What is the best and safest way to do this? Answer - As I had suspected, the solution was to wrap it in a BufferedInputStream which offers markability. Thanks Rasmus. 回答1: For a general InputStream, I would wrap it in a BufferedInputStream and do something like this: BufferedInputStream bis = new

问题 I got stuck at a special problem (I think). For a study project I have to make an Android application that can connect to a Laser Distance Measurer (Bosch GLM 50 C Distometer). So far I went through countless tutorials and hints here at Stackoverflow and other sources. I'm new to Android and am sligthly overwhelmed. The task is to create an app, that reads the measured distance on the Bosch device and display/save it on the smartphone via Bluetooth. Now my concrete question is: Is it possible

问题 I got stuck at a special problem (I think). For a study project I have to make an Android application that can connect to a Laser Distance Measurer (Bosch GLM 50 C Distometer). So far I went through countless tutorials and hints here at Stackoverflow and other sources. I'm new to Android and am sligthly overwhelmed. The task is to create an app, that reads the measured distance on the Bosch device and display/save it on the smartphone via Bluetooth. Now my concrete question is: Is it possible

问题 There is a way to convert inputStream to a String, and encode it to base64, right? In my function, I get InputStream param, and need to insert it into the BLOB field in my Oracle database table. Is there a way to do that? (my database object contains string field to save the image, but I don't find any way to convert the inputStream to string in base64 format) Thank you! 回答1: You can try something like this using the Base64 API. InputStream finput = new FileInputStream(file); byte[]

问题 I am using following way to write InputStream to File : private void writeToFile(InputStream stream) throws IOException { String filePath = "C:\\Test.jpg"; FileChannel outChannel = new FileOutputStream(filePath).getChannel(); ReadableByteChannel inChannel = Channels.newChannel(stream); ByteBuffer buffer = ByteBuffer.allocate(1024); while(true) { if(inChannel.read(buffer) == -1) { break; } buffer.flip(); outChannel.write(buffer); buffer.clear(); } inChannel.close(); outChannel.close(); } I was

问题 I have a problem, I need to compare two inputstreams fast. Today I have a function like this: private boolean isEqual(InputStream i1, InputStream i2) throws IOException { try { // do the compare while (true) { int fr = i1.read(); int tr = i2.read(); if (fr != tr) return false; if (fr == -1) return true; } } finally { if (i1 != null) i1.close(); if (i2 != null) i2.close(); } } But it's really slow. I want to use buffered reads but have not come up with a good way of doing it. Some extra stuff