inout

Swift 5 : Escaping closure captures 'inout' parameter

痞子三分冷 提交于 2021-02-08 07:24:50
问题 I already have the response data that I received from the server. This response data have some bakers data. Now I want to calculate the distance of the user and bakery and then store it in the same modal class. I have created a function for it. And as this function need to be used in 4,5 view controllers, my plan is to create as an extension of UIViewController func getDistanceUserBakery(bakeryData : inout [BakeryRecord], completion : @escaping (Int?) -> () ) { for index in 0...(bakeryData

Swift inout how to not copy back property when not changed, to not trigger objects setters

一个人想着一个人 提交于 2020-04-16 04:25:32
问题 according to the docs You write an in-out parameter by placing the inout keyword at the start of its parameter definition. An in-out parameter has a value that is passed in to the function, is modified by the function, and is passed back out of the function to replace the original value. But how to not copy back the result if it was not changed at all I have a database parser which assigns the attr only when it's value changes, however, with the behavior of inout, the attr that is passed in

Is that an in or in/out parameter? Doxygen, C++

好久不见. 提交于 2020-04-11 07:37:06
问题 If a pointer is passed to a function for read only, then this pointer is an IN parameter. If a pointer is passed to a function for read only, but this function makes a copy of the pointer to have access to it in module related functions for read only operations, this pointer is still IN. If the function still uses the pointer as read only, but the other module related functions use the pointer for write operations, what does that make the pointer? An IN parameter, but without const? An in/out

Swift Generics vs Any

♀尐吖头ヾ 提交于 2020-01-21 07:31:45
问题 I read swift documentation in apple site. There is a function swapTwoValues, which swaps two any given values func swapTwoValues1<T>(_ a: inout T, _ b: inout T) { let temporaryA = a a = b b = temporaryA } Now I want to write similar function but instead of using T generic type I want to use Any func swapTwoValues2(_ a: inout Any, _ b: inout Any) { let temporaryA = a a = b b = temporaryA } to call this functions I write var a = 5 var b = 9 swapTwoValues1(&a, &b) swapTwoValues2(&a, &b) I have

How to update a value in a nested dictionary given path fragment in Swift?

那年仲夏 提交于 2019-12-20 03:25:55
问题 I have a nested dictionary and an array containing path fragment. I need to update the value at that location. I am possibly looking for a recursive function instead of extensions to Dictionary types and such. I am not able to do this recursively because I making a copy of the inout param. var dict: [String: Any] = ["channel": ["item": ["title": 1111]]] var pathFrag = ["channel", "item", "title"] var val = 123 func addAt(pathFrag: inout [String], val: Int, data: inout [String: Any]) { if let

Using inout keyword: is the parameter passed-by-reference or by copy-in copy-out (/call by value result)

牧云@^-^@ 提交于 2019-12-20 01:05:39
问题 Question: Based on the information and discussion below: Are inout parameters passed-by-reference or by copy-in copy-out ? Based on the following SO threads, function parameters marked by the inout keyword is passed by reference : Does inout/var parameter make any difference with reference type? Is Swift Pass By Value or Pass By Reference Why doesn't inout pass by reference? We note that the two top-most threads are pre-Swift 2.0; I haven't been able to find any newer discussion on the

Using inout keyword: is the parameter passed-by-reference or by copy-in copy-out (/call by value result)

﹥>﹥吖頭↗ 提交于 2019-12-20 01:04:30
问题 Question: Based on the information and discussion below: Are inout parameters passed-by-reference or by copy-in copy-out ? Based on the following SO threads, function parameters marked by the inout keyword is passed by reference : Does inout/var parameter make any difference with reference type? Is Swift Pass By Value or Pass By Reference Why doesn't inout pass by reference? We note that the two top-most threads are pre-Swift 2.0; I haven't been able to find any newer discussion on the

inout with reg type in verilog

蹲街弑〆低调 提交于 2019-12-13 08:29:55
问题 I have used inout with c but for c to be on the LHS of procedural assignment, it needs to be a reg type variable. Can anyone help me out with this code? module multiedgeclk(input clk ,[7:0] a,b,d, inout [7:0] c, output reg [7:0]f); always @(posedge clk) c <= a + b; always @(negedge clk) f = c & d; endmodule 回答1: In verilog inout is the direction of the port. wire or reg is the type of the signal. If you want to drive a bi-directional port, it should be declare as inout wire or inout and drive