infinite-loop

Validate the type of input in a do-while loop C

大城市里の小女人 提交于 2019-12-17 07:53:26
问题 Basically, I need to ensure that input is an integer , like so: do { printf("Enter > "); scanf("%d", &integer); } while (/* user entered a char instead of an int */); I have tried various methods, but it always end up with run-time error or infinite loop when I tried to enter a char . I have knew that fflush(stdin) is an undefined behavior, which is better not to involve it in my code in order to prevent any error plus it no longer works in VS2015 due to some reasons. The codes below are the

Is there an expression for an infinite generator?

守給你的承諾、 提交于 2019-12-17 03:27:13
问题 Is there a straight-forward generator expression that can yield infinite elements? This is a purely theoretical question. No need for a "practical" answer here :) For example, it is easy to make a finite generator: my_gen = (0 for i in xrange(42)) However, to make an infinite one I need to "pollute" my namespace with a bogus function: def _my_gen(): while True: yield 0 my_gen = _my_gen() Doing things in a separate file and import -ing later doesn't count. I also know that itertools.repeat

Infinite loop with cin when typing string while a number is expected

老子叫甜甜 提交于 2019-12-16 19:09:45
问题 In the following loop, if we type characters as the cin input instead of numbers which are expected, then it goes into infinite loop. Could anyone please explain to me why this occurs? When we use cin , if the input is not a number, then are there ways to detect this to avoid abovementioned problems? unsigned long ul_x1, ul_x2; while (1) { cin >> ul_x1 >> ul_x2; cout << "ux_x1 is " << ul_x1 << endl << "ul_x2 is " << ul_x2 << endl; } 回答1: Well you always will have an infinite loop, but I know

cout not working in the case of an infinite loop

雨燕双飞 提交于 2019-12-14 03:57:14
问题 int main(int argc, char* argv[]) { while(1) { cout<<"123"; } return 0; } I wrote this small program which would print "123" and then go in an infinite loop. But it does not print anything on the screen. What is the reason for this? 回答1: There can be two reasons. Firstly, the output is most probably buffered. That is, the text sent to cout is not printed immediately, but kept in a buffer and printed only on flushing the buffer (which happens by cout.flush() or by printing endl ). Secondly, I

Can I accidentally harm system files or personal files with Visual Studio 2012

感情迁移 提交于 2019-12-14 03:26:50
问题 I do apologize for the lack of knowledge in this matter but it is very important for me, so at least I'll give it a try. I am using Visual Studio 2012 express on Windows 7 ultimate, I have written some very basic a silly program to practice structures in the C language. Unfortunately, one of the methods that I've written had a wrong condition to stop and it goes to an infinite loop and the worse part it exceeds the given array boundaries. I will add the code below BUT THE CODE IS NOT my main

Infinite loop on login redirect

无人久伴 提交于 2019-12-14 00:27:29
问题 I have a login script which generally works for me, but occasionally goes into an infinite loop on redirecting after checking the cookie stored for login. The browser will report something like the following: "Firefox has detected that the server is redirecting the request for this address in a way that will never complete." Others have reported this issue too. Below are the key elements of the login process. I wonder if someone can see what the issue is with this process/script. Thanks, Nick

A way to run an infinite loop without the stackoverflowexception on ironpython?

安稳与你 提交于 2019-12-13 18:46:04
问题 I'm having a little problem when trying to run an infinite loop in ironpython 2.7 Here is my script: import urllib import urllib2 import json a=0 info = '' def getInfo(): url = 'https://api.bitfinex.com/v1/pubticker/btcusd' values = {} data = urllib.urlencode(values) req = urllib2.Request(url) response = urllib2.urlopen(req) the_page = response.read() page_info = json.loads(the_page) return(page_info) while 1: try: info = getInfo() a=a+1 print("--"+str(a)+"--") if info != '': print(str(info[

Can compilers detect infinite looping condition? [duplicate]

别来无恙 提交于 2019-12-13 18:41:23
问题 This question already has answers here : When have you come upon the halting problem in the field? [closed] (13 answers) Closed 6 years ago . I'm building a compiler for a custom language. Is it possible for the compiler to detect any infinite looping condition without running the program? If so how can I implement it? 回答1: You may be able to detect some infinite loops, but in general you can't detect all possible infinite loops (unless your custom language is specifically designed to

atoi() method, char * cout

我与影子孤独终老i 提交于 2019-12-13 17:13:39
问题 This is an atoi() I am trying to understand. In order to compile with the non-existing library, I called it m() . There are several lines of codes I am confused about, mainly char * issues. My questions are listed after the code : #include "stdafx.h" #include <iostream> using namespace std; int m( char* pStr ) { int iRetVal = 0; int iTens = 1; cout << "* pStr: " << * pStr << endl; // line 1 if ( pStr ) { char* pCur = pStr; cout << "* pCur: " << * pCur << endl; while (*pCur) { //cout << "*

When test hanging in an infinite loop

时光总嘲笑我的痴心妄想 提交于 2019-12-13 12:32:28
问题 I'm tokenising a string with XSLT 1.0 and trying to prevent empty strings from being recognised as tokens. Here's the entire function, based on XSLT Cookbook: <xsl:template name="tokenize"> <xsl:param name="string" select="''" /> <xsl:param name="delimiters" select="';#'" /> <xsl:param name="tokensplitter" select="','" /> <xsl:choose> <!-- Nothing to do if empty string --> <xsl:when test="not($string)" /> <!-- No delimiters signals character level tokenization --> <xsl:when test="not(