infinite-loop

问题 Is it possible to get an infinite loop in for loop? My guess is that there can be an infinite for loop in Python. I'd like to know this for future references. 回答1: The quintessential example of an infinite loop in Python is: while True: pass To apply this to a for loop, use a generator (simplest form): def infinity(): while True: yield This can be used as follows: for _ in infinity(): pass 回答2: To answer your question using a for loop as requested, this would loop forever as 1 will never be

问题 I am trying to run a loop until the user chooses to break out of it. Whether the user wants to run the function all night or for just a few seconds the loop should repeat until the user decides to stop it. In researching solutions I came across using two threads to achieve this. The first thread would run the infinite loop while the second thread waited for user input. Upon receiving that input the second thread would terminate the first and then return. How do I use the second thread to

问题 I've seen two ways to create an infinite loop in Python: while 1: do_something() while True: do_something() Is there any difference between these? Is one more pythonic than the other? 回答1: Fundamentally it doesn't matter, such minutiae doesn't really affect whether something is 'pythonic' or not. If you're interested in trivia however, there are some differences. The builtin boolean type didn't exist till Python 2.3 so code that was intended to run on ancient versions tends to use the while 1

问题 I have the following loop: for (byte i = 0 ; i < 128; i++) { System.out.println(i + 1 + " " + name); } When I execute my programm it prints all numbers from -128 to 127 in an infinite loop. Why does this happen? 回答1: byte is a 1-byte type so can vary between -128...127, so condition i < 128 is always true. When you add 1 to 127 it overflows and becomes -128 and so on in a (infinite) loop... 回答2: After 127, when it increments, it will become -128, so your condition won't match . byte : The

问题 I would like to map my servlet to /* , but it failed with an infinite loop. <servlet> <servlet-name>helloServlet</servlet-name> <servlet-class>my.HelloServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>helloServlet</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping> The java code is: public class HelloServlet extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response){ request

问题 This causes infinite loop: std::regex_replace("the string", std::regex(".*"), "whatevs"); This DOES NOT cause infinite loop: std::regex_replace("the string", std::regex("^.*$"), "whatevs"); What is wrong with Mac regex implementation? using Mac OS X El Capitan Xcode 7.1 this question is related to: C++ Mac OS infinite loop in regex_replace if given blank regex expression 回答1: The .* matches the whole string first, and then the empty string at the end because * means " match 0 or more

问题 I would like to know if there is anyway I can add a trigger on two tables that will replicate the data to the other. For example: I have a two users tables, users_V1 and users_V2, When a user is updated with one of the V1 app, it activate a trigger updating it in users_V2 as well. If I want to add the same trigger on the V2 table in order to update the data in V1 when a user is updated in V2, will it go into an infinite loop? Is there any way to avoid that. 回答1: I don't recommend explicitly

问题 I had a simple bit of code that was supposed to be an endless loop since x will always be growing and will always remain larger than j . int x = 5; int y = 9; for (int j = 0; j < x; j++) { x = x + y; } System.out.println(y); but as is, it prints y and does not loop endlessly. I cannot figure out why. However, when I adjust the code in the following manner: int x = 5; int y = 9; for (int j = 0; j < x; j++) { x = x + y; System.out.println(y); } System.out.println(y); It becomes an endless loop

问题 I have an EditText field with a Customer Text Watcher on it. In a piece of code I need to change the value in the EditText which I do using .setText("whatever") . The problem is as soon as I make that change the afterTextChanged method gets called which created an infinite loop. How can I change the text without it triggering afterTextChanged? I need the text in the afterTextChanged method so don't suggest removing the TextWatcher . 回答1: You could unregister the watcher, and then re-register

问题 I have an EditText field with a Customer Text Watcher on it. In a piece of code I need to change the value in the EditText which I do using .setText("whatever") . The problem is as soon as I make that change the afterTextChanged method gets called which created an infinite loop. How can I change the text without it triggering afterTextChanged? I need the text in the afterTextChanged method so don't suggest removing the TextWatcher . 回答1: You could unregister the watcher, and then re-register