MIC IJVM simple sum of 2 digits
问题 just a simple question regarding calculations in IJVM as I couldn't find the solution in their documentation. Suppose we need to perform the following calculation: BIPUSH 0x32 // PUSH 2 BIPUSH 0x33 // PUSH 3 IADD // PUSH sum(2,3) OUT // output: "e" IADD ----> Pop two words from stack; push their sum I know the solution is likely straight forward, but for the life of me I can't recall on how to convert the addition/output to the actual digits. How to make it output "5" instead of this stupid