identifier

Are dollar-signs allowed in identifiers in C++03?

白昼怎懂夜的黑 提交于 2019-11-26 18:25:50
问题 What does the C++ standard say about using dollar signs in identifiers, such as Hello$World ? Are they legal? 回答1: A c++ identifier can be composed of any of the following: _ (underscore), the digits 0-9, the letters a-z (both upper and lower case) and cannot start with a number. There are a number of exceptions as C99 allows extensions to the standard (e.g. visual studio). 回答2: They are illegal. The only legal characters in identifiers are letters, numbers, and _. Identifiers also cannot

What characters are valid in an SQL Server database name?

空扰寡人 提交于 2019-11-26 16:04:06
问题 We're going to provide our clients with a tool that (among other things) creates a new SQL Server database, and I want to be able to do basic validation on the database name they provide. SQL Server's documentation explains what characters are valid in a database name. However, the documentation is apparently incorrect, because I can successfully create databases whose names violate the documented rules. According to SQL Server's documentation for CREATE DATABASE, database names must comply

$ in variable name?

☆樱花仙子☆ 提交于 2019-11-26 15:27:36
I stumbled on some C++ code like this: int $T$S; First I thought that it was some sort of PHP code or something wrongly pasted in there but it compiles and runs nicely (on MSVC 2008). What kind of characters are valid for variables in C++ and are there any other weird characters you can use? The only legal characters according to the standard are alphanumerics and the underscore. The standard does require that just about anything Unicode considers alphabetic is acceptable (but only as single code-point characters). In practice, implementations offer extensions (i.e. some do accept a $) and

Using number as “index” (JSON)

偶尔善良 提交于 2019-11-26 15:27:26
Recently started digging in to JSON, and I'm currently trying to use a number as "identifier", which doesn't work out too well. foo:"bar" works fine, while 0:"bar" doesn't. var Game = { status: [ { 0:"val", 1:"val", 2:"val" }, { 0:"val", 1:"val", 2:"val" } ] } alert(Game.status[0].0); Is there any way to do it the following way? Something like Game.status[0].0 Would make my life way easier. Of course there's other ways around it, but this way is preferred. JSON only allows key names to be strings. Those strings can consist of numerical values. You aren't using JSON though. You have a

identify groups of linked episodes which chain together

橙三吉。 提交于 2019-11-26 14:47:52
Take this simple data frame of linked ids: test <- data.frame(id1=c(10,10,1,1,24,8),id2=c(1,36,24,45,300,11)) > test id1 id2 1 10 1 2 10 36 3 1 24 4 1 45 5 24 300 6 8 11 I now want to group together all the ids which link. By 'link', I mean follow through the chain of links so that all ids in one group are labelled together. A kind of branching structure. i.e: Group 1 10 --> 1, 1 --> (24,45) 24 --> 300 300 --> NULL 45 --> NULL 10 --> 36, 36 --> NULL, Final group members: 10,1,24,36,45,300 Group 2 8 --> 11 11 --> NULL Final group members: 8,11 Now I roughly know the logic I would want, but don

Apostrophe in identifiers in Haskell

给你一囗甜甜゛ 提交于 2019-11-26 14:21:49
问题 I found this code snipped on the internet: digits 0 = [0] digits n = digits' n [] where digits' 0 ds = ds digits' n ds = let (q,r) = quotRem n 10 in digits' q (r:ds) sumOfDigits = sum . digits Can someone quickly explain what the " ' " sign ( digits n = digits' n [] ) after the recursive function call is for? I've seen some other code examples in Haskell (tutorials), but im not understandig this one. A quick explanation is appreciated. 回答1: The apostrophe is just part of the name. It is a

What are “connecting characters” in Java identifiers?

拈花ヽ惹草 提交于 2019-11-26 14:03:09
I am reading for SCJP and I have a question regarding this line: Identifiers must start with a letter, a currency character ($), or a connecting character such as the underscore ( _ ). Identifiers cannot start with a number! It states that a valid identifier name can start with a connecting character such as underscore. I thought underscores were the only valid option? What other connecting characters are there? Peter Lawrey Here is a list of connecting characters. These are characters used to connect words. http://www.fileformat.info/info/unicode/category/Pc/list.htm U+005F _ LOW LINE U+203F

Using keywords as identifiers in F#

拜拜、爱过 提交于 2019-11-26 12:45:55
问题 In C#, I can do the following: int @private = 15; And in VB.NET, I can do the following: Dim [Private] As Integer = 15 I am wondering if there is a way in F# to use reserved keywords as identifiers, like there is in VB.NET and C#? 回答1: Given section 3.4 of the F# 2.0 spec: Identifiers follow the specification below. Any sequence of characters that is enclosed in double-backtick marks (`` ``), excluding newlines, tabs, and double-backtick pairs themselves, is treated as an identifier. I

NSInvalidArgumentException - receiver has no segue with identifier

三世轮回 提交于 2019-11-26 12:28:10
问题 I have been trying everything for hours, and nothing\'s worked. I am trying to segue between two view controllers, from one tableViewController to another tableViewController. The segue is hooked up to the top level view, not the tableviewcell. The identifier that was set in Xcode is identical to the one used in the code (copy and pasted). It was working fine last night, but now i can\'t seem to get it to segue without crashing. here are the methods in which the segue is called - (void

What is the bundle identifier of apple&#39;s default applications in iOS?

◇◆丶佛笑我妖孽 提交于 2019-11-26 12:05:41
问题 I need to know the bundle identifiers for apple applications, such as mail, contacts, safari, photos, game center, settings, calendar, iPod, App store, camera, ... After searching for quite a while I found out they may be com.apple.{somethingelse} 回答1: These are from iPhone 4S iOS 5.0.1 Camera: com.apple.camera AppStore: com.apple.AppStore Contacts: com.apple.MobileAddressBook Mail: com.apple.mobilemail GameCenter: com.apple.gamecenter MobileSafari: com.apple.mobilesafari Preferences: com