graph

How to increase label spacing to avoid label overlap in networkx graph

邮差的信 提交于 2021-02-11 13:10:34
问题 I want to plot a graph, where one node for each document exists and then other nodes for each word in it. This way I want to visualize words, that are occuring in multiple documents. Unfortunately the labels for the nodes overlap, so that they aren't very readable oftentimes. I have tried to increase and decrease the k variable, but it is not really helping. I noticed that the graph changes if its plotted again, and sometimes the labels are more readable, but its not very helpful because I

How to increase label spacing to avoid label overlap in networkx graph

旧街凉风 提交于 2021-02-11 13:04:52
问题 I want to plot a graph, where one node for each document exists and then other nodes for each word in it. This way I want to visualize words, that are occuring in multiple documents. Unfortunately the labels for the nodes overlap, so that they aren't very readable oftentimes. I have tried to increase and decrease the k variable, but it is not really helping. I noticed that the graph changes if its plotted again, and sometimes the labels are more readable, but its not very helpful because I

Algorithm for locating the closest destination(s) to source(s) and resolving conflicts in case a single destination is mapped to multiple sources

跟風遠走 提交于 2021-02-11 08:22:06
问题 Problem Statement: Given a matrix of people(denoted by small alphabets) and bikes(denoted by capital alphabets), find the nearest bike for a given person. How will you change your solution if you have to find bikes for a set of people? (assuming multiple bikes can be at the same distance from 1 person)? I know Dijkstra's algorithm and Bellman Ford's algorithm, but curious about the implementation here. Or can it be solved by BFS(Breadth First Search)? 回答1: To assign a single bike to a single

Algorithm for locating the closest destination(s) to source(s) and resolving conflicts in case a single destination is mapped to multiple sources

大兔子大兔子 提交于 2021-02-11 08:16:56
问题 Problem Statement: Given a matrix of people(denoted by small alphabets) and bikes(denoted by capital alphabets), find the nearest bike for a given person. How will you change your solution if you have to find bikes for a set of people? (assuming multiple bikes can be at the same distance from 1 person)? I know Dijkstra's algorithm and Bellman Ford's algorithm, but curious about the implementation here. Or can it be solved by BFS(Breadth First Search)? 回答1: To assign a single bike to a single

Changing lower limit of graph y-axis when x is a discrete variable without cutting off bottom of bars

本秂侑毒 提交于 2021-02-11 06:52:08
问题 I am trying to adjust the y-axis of this graph so that it starts at 1 instead of 0. What's the best way to do this? The solution offered here cuts off the bottom of the graph. I would like for the bars to look pretty much identical to the graph below, but with the lower y-limit at 1 and each bar moved down 1 unit to match. I would like to preserve the small amount of gray space below each bar. Code: groups %>% ungroup() %>% mutate(message = fct_relevel(message, "Personal", "General"),

How to add vertical lines to graph with HighStocks or HighCharts?

笑着哭i 提交于 2021-02-10 19:59:15
问题 I have successfully created a chart with HighChart's HighStock. I'm trying to add vertical lines to the chart. I've searched everywhere in HighStock's docs, Stackoverflow and Google on how to do this, but to no avail. I tried HighStock's "flags" but can't create vertical lines with them. I basically want to turn this chart... ... into something like this: Is this even possible? If yes, how? Thanks! 回答1: Yes, These are called plotLines and are easily added like: xAxis: { plotLines: [{ value:

Graph bars only appear when lower limit of y axis set to 0 in ggplot

China☆狼群 提交于 2021-02-10 18:10:42
问题 I am trying to create a bar graph. When I set the limits as (0,7), the bars appear. However, I would like the lower limit to be 1, not 0. When I set the lower limit to 1, the bars do not appear. I get the following error message: Removed 8 rows containing missing values (geom_bar). It doesn't matter how I set the limits. I have used both of the following options: ylim(1, 7) scale_y_continuous(limits = c(1, 7)) Does anyone know how I can fix this? I'd like a graph that looks like this, but

Graph bars only appear when lower limit of y axis set to 0 in ggplot

半腔热情 提交于 2021-02-10 17:55:55
问题 I am trying to create a bar graph. When I set the limits as (0,7), the bars appear. However, I would like the lower limit to be 1, not 0. When I set the lower limit to 1, the bars do not appear. I get the following error message: Removed 8 rows containing missing values (geom_bar). It doesn't matter how I set the limits. I have used both of the following options: ylim(1, 7) scale_y_continuous(limits = c(1, 7)) Does anyone know how I can fix this? I'd like a graph that looks like this, but

How to fix graphics being cut off when drawing NetworkX graphs with Matplotlib?

廉价感情. 提交于 2021-02-10 12:57:39
问题 I am using NetworkX and Matplotlib to draw nodes, but the nodes are sometimes being cut off at the edge of the graphic. Is there a setting to increase the margins or prevent them from being cut off? Image: Nodes being cut off at the edge of the graphic Example program: import networkx as nx import matplotlib.pyplot as plt import numpy as np adjacency_matrix = np.array([[1,0,0,0,0,0,1,0],[0,1,1,1,1,0,0,0],[0,1,1,0,0,0,0,0],[0,1,0,1,0,0,0,0], [0,1,0,0,1,1,0,0],[0,0,0,0,1,1,1,1],[1,0,0,0,0,1,1,0

How to fix graphics being cut off when drawing NetworkX graphs with Matplotlib?

≯℡__Kan透↙ 提交于 2021-02-10 12:57:20
问题 I am using NetworkX and Matplotlib to draw nodes, but the nodes are sometimes being cut off at the edge of the graphic. Is there a setting to increase the margins or prevent them from being cut off? Image: Nodes being cut off at the edge of the graphic Example program: import networkx as nx import matplotlib.pyplot as plt import numpy as np adjacency_matrix = np.array([[1,0,0,0,0,0,1,0],[0,1,1,1,1,0,0,0],[0,1,1,0,0,0,0,0],[0,1,0,1,0,0,0,0], [0,1,0,0,1,1,0,0],[0,0,0,0,1,1,1,1],[1,0,0,0,0,1,1,0