format

I would like to convert double into String . I want it to have as few digits as possible and maximally 6. So I found String.format("%.6f", d) which converts my 100.0 into 100.000000 . Max precision works correctly, but I would like it to be converted to 100 (minimum precision). Have you got any idea what method is working like that? Thomas Use DecimalFormat : new DecimalFormat("#.0#####").format(d) . This will produce numbers with 1 to 6 decimal digits. Since DecimalFormat will use the symbols of the default locale, you might want to provide which symbols to use: //Format using english symbols

I want to get year-month-day hour:minute:second.fraction(2 digits), if I use "%Y-%m-%d %H:%M:%S.%f", I got almost what I want exception for the fraction( last part ) of seconds, it's showing 6 digits on my Windows XP, I don't know how to get 2 digits only, any idea? Boaz Yaniv Boost.DateTime (upon which Boost.Log relies) doesn't seem to support specialized fractional seconds formatting, so the only way to do that would be to write your own custom attribute formatter, or (the easier, but less nice way) to slightly modify your formatting code. Instead of something like this: backend->set

When I run this the first one is correctly created into a date. The second one fails, returning a boolean and so I cannot format. Is the time out of range? //works correctly $startDate = "2015-05-06 10:49:20.637133"; $start = DateTime::createFromFormat('Y-m-d h:m:s.u',$startDate); echo $start->format('m/d/y'); //doesn't work correctly $startDate = "2015-05-12 15:49:06.821289"; $start = DateTime::createFromFormat('Y-m-d h:m:s.u',$startDate); echo $start->format('m/d/y'); Code to reproduce the error Change the h to a big H , since the small one is 12-hours format and the big one is 24-hours

I just started learning Rust, and I'm making some small tools to help me understand the language. I have a problem formatting a String using the format! macro. As format! takes a literal, I am not able pass my string to it. I want to do this to dynamically add strings into the current string for use in a view engine. I'm open for suggestions if there might be a better way to do it. let test = String::from("Test: {}"); let test2 = String::from("Not working!"); println!(test, test2); What I actually want to achieve is the below example, where main.html contains {content} . use std::io::prelude::

Below is a sample robots.txt file to Allow multiple user agents with multiple crawl delays for each user agent. The Crawl-delay values are for illustration purposes and will be different in a real robots.txt file. I have searched all over the web for proper answers but could not find one. There are too many mixed suggestions and I do not know which is the correct / proper method. Questions: (1) Can each user agent have it's own crawl-delay? (I assume yes) (2) Where do you put the crawl-delay line for each user agent, before or after the Allow / Dissallow line? (3) Does there have to be a blank

QUESTION: Implement the following pseudocode to draw a checkered flag to the screen. 1. Ask the user for the size of the checkered flag (n). 2. Draw an n x n grid to the screen. 3. For i = 0,2,4,...,62: 4. row = i // n 5. offset = row % 2 6. col = (i % n) + offset Please copy and paste the link see the ouput: http://www.awesomescreenshot.com/image/45977/12eaef67de44c2b291ecd47fe8d10135 I implemented the pseudocode, but I need some help. I am keep getting this error: row, col = findGrid(x) TypeError: 'int' object is not iterable My program: from turtle import* def size(): size = eval(input(

I want to define a date format that takes the following format : 12JAN2010 I tried using this code : /* partie B question 2*/ data projet.Ophtalmo_new; set projet.Ophtalmo_new (RENAME=(date_diagnostic=date_dia)) (RENAME= (date_examen=date_exa)); date_diagnostic = input (date_dia, DDMMYY10.); date_examen = input (date_exa, DDMMYY10.); format date_diagnostic date_examen date9.; run; But it sends me the following syntax error : ERROR 22-322: Syntax error, expecting one of the following: un nom, une chaîne entre guillemets, ;, CUROBS, END, INDSNAME, KEY, KEYRESET, KEYS, NOBS, OPEN, POINT, _DATA_,

I'd like to read a file of about 5MB in memory ... the file has this format (it is a text file) ID 3: 0 itemId.1 0 itemId.2 0 itemId.5 1 itemId.7 ........................ 20 itemId.500 ID 50: 0 itemId.31 0 itemId.2 0 itemId.4 2 itemId.70 ........................ 20 itemId.2120 ..... how can I do this efficiently in c++? Martin York Reading a file line by line: ifstream fin ("file.txt"); string myStr; while(getline(fin, myStr)) // Always put the read in the while condition. { // Then you only enter the loop if there is data to //use myStr data // processes. Otherwise you need to read and then }