format

I have to create Excel spreadsheet with nice format from Python. I thought of doing it by: I start in Excel as it is very easy to format: I write in Excel the model I want, with the good format I read this from Python I create from Python an Excel spreadsheet with the same format In the end, the purpose is to create from Python Excel spreadsheets, but formatting with xlwt takes a lot of time, so I thought of formatting first in Excel to help. I have researched for easy ways to doing this but haven't found any. I can stick to my current working solution, using xlwt in Python to create formatted

I have a huge file to read whose structure is: [...] (0,0,0,0,0): 5.00634e-33, 5.59393e-33, 6.24691e-33, 7.29338e-33, (0,0,0,0,4): 7.77607e-33, 8.95879e-33, 9.65316e-33, 1.07434e-32, (0,0,0,0,8): 1.20824e-32, 1.34983e-32, 1.49877e-32, 1.73061e-32, (0,0,0,0,12): 1.919e-32, 2.15391e-32, 2.3996e-32, 2.67899e-32, [...] I'm interested in reading the value after ":", which format should I use in the read statement if I use Fortran90? I've tried with read(1,'("(",I6,",",I6,",",I6,",",I6,",",I6,"):",F10.4,F10.4,F10.4,F10.4)')idx1,idx2,idx3,idx4,idx5,dummy1,dummy2,dummy3,dummy4 But I got a forrtl:

I am trying to get the following output. All rows and columns are text wrapped except the header though: import pandas as pd import pandas.io.formats.style import os from pandas import ExcelWriter import numpy as np from xlsxwriter.utility import xl_rowcol_to_cell writer = pd.ExcelWriter('test1.xlsx',engine='xlsxwriter',options={'strings_to_numbers': True},date_format='mmmm dd yyyy') df = pd.read_csv("D:\\Users\\u700216\\Desktop\\Reports\\CD_Counts.csv") df.to_excel(writer,sheet_name='Sheet1',startrow=1 , startcol=1, header=True, index=False, encoding='utf8') workbook = writer.book worksheet =

Is there any way to format Date object to made fixed length of Day and Month in order to have good alignment in a column? For example: 15 May 2010 10 January 2010 Instead of 15 May 2010 10 January 2010 Thanks! Have a look at the java.util.Formatter class whose format method is the same as String.format(...) and similar to System.out.printf. For example: import java.util.Calendar; import java.util.Date; import java.util.GregorianCalendar; public class FormatDateCalendar { public static final String FORMAT_STRING = "%1$-3td %1$-9tB %1$tY"; public static void main(String[] args) { Calendar c1 =

Following on this SO question what would be the best way to use the formatting operator to apply it to a numpy array where the array is of the format given below corresponding to RGB values Note RGB values have been scaled 0 to 1 so multiple by 255 to rescale array([[ 0.40929448, 0.47071505, 0.27701891], [ 0.59383913, 0.60611158, 0.55329837], [ 0.4393785 , 0.4276561 , 0.34999225], [ 0.4159481 , 0.4516056 , 0.3026519 ], [ 0.54449997, 0.36963636, 0.4001209 ], [ 0.36970012, 0.3145826 , 0.315974 ]]) and you want a hex triplet value for each row You can use the rgb2hex from matplotlib. from

If a date format is $scope.timestamp = '2016-12-16 07:02:15 am' I want to format to 16/12/2016 07:02:15 am I have tried this below code and it's working good $scope.originalStamp = $filter('date') (new Date($scope.timestamp.replace("-","/")),'dd-MM-yyyy HH:mm:ss a'); But my question is why new Date($scope.timestamp) is always return null if am not use replace the char from (-) to (/)? see the below code is not working if am without using replace(). $scope.originalStamp = $filter('date') (new Date($scope.timestamp),'dd-MM-yyyy HH:mm:ss a'); Why the new Date() does not accept if the date format

I try to format the current time in 2 locations: Chicago and Tokyo LocalDateTime now = LocalDateTime.now(); ZonedDateTime chicago = now.atZone(ZoneId.of("America/New_York")); System.out.println("chicago: " + chicago); System.out.println("Chicago formated: " + chicago.format(DateTimeFormatter.ofLocalizedTime(FormatStyle.FULL))); ZonedDateTime tokyo = now.atZone(ZoneId.of("Asia/Tokyo")); System.out.println("Tokyo: " + tokyo); System.out.println("Tokyo formated: " + tokyo.format(DateTimeFormatter.ofLocalizedTime(FormatStyle.FULL))); The print out: chicago: 2017-11-05T18:19:01.441-05:00[America

user6@das0 hadoop-0.20.203.0]$ bin/hadoop namenode -format 12/02/20 14:05:17 INFO namenode.NameNode: STARTUP_MSG: Re-format filesystem in /data0/hadoop-name ? (Y or N) y Format aborted in /data0/hadoop-name 12/02/20 14:05:20 INFO namenode.NameNode: SHUTDOWN_MSG: 随后启动hadoop, 发现http://das0:5007无法显示。 将/data0/hadoop-name文件夹整个删除。然后再格，成功！！！ [zhangpeng6@das0 hadoop-0.20.203.0]$ bin/hadoop namenode -format 12/02/20 14:09:57 INFO namenode.NameNode: STARTUP_MSG: 12/02/20 14:09:57 INFO util.GSet: VM type = 64-bit 12/02/20 14:09:57 INFO util.GSet: 2% max memory = 177.77875 MB 12/02/20 14:09:57 INFO util

I wish to format a variable to a price format where if it is for example $90 then leave out the decimal which it already does anyway. But if the value is $44.5 then I want to format it as $44.50. I can do it in php not javascript. PHP example: number_format($price, !($price == (int)$price) * 2); The code I want to format: $(showdiv+' .calc_price span').html(sum_price); var price = 44.5; var dplaces = price == parseInt(price, 10) ? 0 : 2; price = '$' + price.toFixed(dplaces); AlienWebguy PHPJS has that code for you: http://phpjs.org/functions/money_format:876 Also provided by @Daok How can I