fork

Redis 中的数据持久化策略(RDB)

删除回忆录丶 提交于 2020-01-07 08:52:35
Redis 是一个内存数据库,所有的数据都直接保存在内存中,那么,一旦 Redis 进程异常退出,或服务器本身异常宕机,我们存储在 Redis 中的数据就凭空消失,再也找不到了。 Redis 作为一个优秀的数据中间件,必定是拥有自己的持久化数据备份机制的,redis 中主要有两种持久化策略,用于将存储在内存中的数据备份到磁盘上,并且在服务器重启时进行备份文件重载。 RDB 和 AOF 是 Redis 内部的两种数据持久化策略,这是两种不同的持久化策略,一种是基于内存快照,一种是基于操作日志,那么本篇就先来讲讲 RDB 这种基于内存快照的持久化策略。 一、什么是 RDB 持久化策略 RDB(redis database),快照持久化策略。RDB 是 redis 默认的持久化策略,你可以打开 redis.conf,默认会看到这三条配置。 save 900 1 900秒内执行一次set操作 则持久化1次 save 300 10 300秒内执行10次set操作,则持久化1次 save 60 10000 60秒内执行10000次set操作,则持久化1次 RDB 又分为两种,一种是同步的,调用 save 命令即可触发 redis 进行 RDB 文件生成备份,但是这是一个同步命令,在备份完成之前,redis 服务器不响应客户端任何请求。另一种是异步的,调用 bgsave 命令,redis 服务器

fork function process graph, valid and invalid outputs

北慕城南 提交于 2020-01-07 08:12:09
问题 printf("L1 \n"); if (fork() != 0) { printf("L2 \n"); if (fork() != 0) { printf("L3 \n"); fork(); } } printf("End \n"); I am having a hard time understanding this code. Could someone explain/ display what the process graph would look like? Also, a valid and invalid sequence. My thought of the process graph was something like this: L1 will hold two L2 processes then each L2 processes will hold 2 L3 processes and each L3 processes will hold an end processes. Is this correct? A valid sequence for

多进程下的文件描述符

风流意气都作罢 提交于 2020-01-07 07:52:30
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 多进程下的文件描述符 我们都知道fork之后, 子进程继承了父进程的文件描述符. 但是这是什么意思? 如果父子进程或多个子进程同时操作这个文件描述符会如何? 奇怪的表现 脚本的基本逻辑是父进程读取要处理的文件是计算行数, 然后根据配置的子进程个数fork子进程,子进程处理某一范围的数据,比如子进程1处理1到10行, 子进程2处理11到20. 因为对这个文件的处理是只读操作, 所以没有进行文件拆分,而是直接使用继承的文件描述符, 各子进程移动到自己处理的范围进行处理. 但是在测试的时候, 发现有些子进程总是无法读到数据, strace 调试发现read(2)返回0. 但是增加fseek之后,又正常了, 见当时代码注释: //开发时发现如果没有这个fseek, 会导致$proc_idx=0的那个子进程fgets读不到数据,strace显示read返回0 //原因不明 fseek($order_file, ftell($order_file)); while(($line_no <= $stop) && $line = fgets($order_file, 4096)) { .... } 可以看到这个fseek到ftell完全是没有用的,但加了这句这后就就正常了. 真是匪夷所思. 开发时, 一开始是正常的,

Wait for children to complete if parent intercepts SIGINT

北慕城南 提交于 2020-01-07 03:04:28
问题 I have a perl script with multiple child processes (created using fork()). Each child sleeps then does some processing (several system() calls). Under windows when I hit Ctrl+C I see that the signal was caught , then the script waits for the children to complete and after this exits. I want to replicate this behaviour in linux (catch sigint , let the children complete and exit the main script/process ). How do I wait for all children to complete before killing the parent ? Is it possible to

Wait for children to complete if parent intercepts SIGINT

最后都变了- 提交于 2020-01-07 03:04:06
问题 I have a perl script with multiple child processes (created using fork()). Each child sleeps then does some processing (several system() calls). Under windows when I hit Ctrl+C I see that the signal was caught , then the script waits for the children to complete and after this exits. I want to replicate this behaviour in linux (catch sigint , let the children complete and exit the main script/process ). How do I wait for all children to complete before killing the parent ? Is it possible to

PHP pcntl

青春壹個敷衍的年華 提交于 2020-01-06 18:34:19
来源: https://www.jianshu.com/p/de0b74f58f50 pcntl 是一个可以利用操作系统的 fork 系统调用在PHP中实现多线程的进程控制扩展,当使用 fork 系统调用后执行的代码将会是并行的。 pcntl 仅适用于Linux平台的CLI模式下使用。 PHP官方没有提供多线程的扩展,在 pecl 中有一个 pthread 扩展提供了多线程的特性,此版本仅在线程安全版本中可用。 创建子进程 pcntl_fork int pcntl_fork(void) 当 pcntl_fork 函数执行时会在当前进程下创建一个子进程,子进程与父进程在PID和PPID上会不同。 子进程会复制父进程中所有的数据、代码、状态等信息。当使用 pcntl_fork 成功创建子进程后,子进程会复制父进程的代码和数据。此时父进程和子进程拥有相同的代码和数据。子进程也会复制父进程的状态。 当使用 pcntl_fork 创建子进程,如果成功则会在父进程中将会返回0,在子进程中会返回自身的进程编号 PID 。如果创建失败则返回 -1 。 使用 pcntl_fork 创建的进程只是一个分支节点,相当于一个标记,父进程完成后子进程会从标记处继续执行,也就是说在 pcntl_fork 之后的代码分别会被父进程和子进程执行两遍,而两个进程在执行过程中得到的返回值却是不同的

Command Line Arguments not getting executed in C

六眼飞鱼酱① 提交于 2020-01-06 06:33:06
问题 I am trying to pass arguments to execl() function for ls command. But when I pass /bin/ls -l -a as arguments to my program, the execl() function doesn't recognise the last two arguments. Why is that?Here is the code: #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int i,childpid; if(argc!=4) { printf("you didn't provide any commandline arguments!\n"); return 0; } childpid=fork(); if(childpid<0) { printf("fork() failed\n"); return 0; } else if(childpid==0) { printf(

Garbage collector in Ruby 2.2 provokes unexpected CoW

那年仲夏 提交于 2020-01-06 03:10:08
问题 How do I prevent the GC from provoking copy-on-write, when I fork my process ? I have recently been analyzing the garbage collector's behavior in Ruby, due to some memory issues that I encountered in my program (I run out of memory on my 60core 0.5Tb machine even for fairly small tasks). For me this really limits the usefulness of ruby for running programs on multicore servers. I would like to present my experiments and results here. The issue arises when the garbage collector runs during

Can I call chdir or setenv after fork on Mac OS X?

余生长醉 提交于 2020-01-06 01:59:34
问题 On OS X, the man page for fork says this: There are limits to what you can do in the child process. To be totally safe you should restrict yourself to only executing async-signal safe operations until such time as one of the exec functions is called. All APIs, including global data symbols, in any framework or library should be assumed to be unsafe after a fork() unless explicitly documented to be safe or async-signal safe. If you need to use these frameworks in the child process, you must

what else '\n' do except printing newline?

自作多情 提交于 2020-01-05 13:03:19
问题 After commenting Line 2 "Hello" is printed nine times but commenting Line 1 outputs "Hello" more than nine times. My question is what's the role of '\n' in this? #include<stdio.h> #include<stdlib.h> int main() { int tmp[10], i, n=0; for(i=0;i<9;i++) { tmp[i]=fork(); if(tmp[i]>0) break; else { printf("Hello\n"); // ---- Line 1 printf("Hello "); // ---- Line 2 } } } 回答1: \n also flushes the standard output buffer. If it is not present, it is possible that you have previously entered data in it.