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BMW ICOM A2+B+C is upgrade of BMW ICOM, ICOM A2 is Second generation of BMW ISTA Diagnose and programming system. Support both new and old BMW vehicles. BMW ICOM A2 : Software Version : 2016.07 ISTA/D (ISID /DiagnosticISTA-D 3.55.31 ISTA-P 3.59.0.600 VIN: 2016.06.15 BMW ICOM : 1. Support Multi-language: American English, British English, German, Spanish, French, Italian, Polish, Portuguese, Turkish, Czech, Swedish, Dutch, Indian, Greek, Russian, Japanese, Korean, Thai, Simplified Chinese and Traditional Chinese 2. Hardware Version: ICOM Application-01.40.05 3. Support Vehicles: BMW Cars, BMW

除了走到哪里，还要加状态表示当前节点和已经匹配的串 #include<iostream> #include<cstdio> #include<string> #include<cstring> #include<algorithm> #include<cmath> #include<vector> #include <set> #include <queue> #define ll long long #define ld long double #define lson l,m,rt<<1 #define pi acos(-1) #define rson m+1,r,rt<<1|1 #define fo(i,l,r) for(int i = l;i <= r;i++) #define fd(i,l,r) for(int i = r;i >= l;i--) #define mem(x) memset(x,0,sizeof(x)) #define eps 1e-8 using namespace std; const int maxn = 250,maxs = 5; const ll inf = 1e9; const ll mod = 1000000007; ll read() { ll x=0,f=1; char ch=getchar(); while(!(ch>='0'&&ch<

注意标记一个点后，fail树上的子节点都会被标记 跑spfa，dp也可以 #include<iostream> #include<cstdio> #include<string> #include<cstring> #include<algorithm> #include<cmath> #include<vector> #include <set> #include <queue> #define ll long long #define ld long double #define lson l,m,rt<<1 #define pi acos(-1) #define rson m+1,r,rt<<1|1 #define fo(i,l,r) for(int i = l;i <= r;i++) #define fd(i,l,r) for(int i = r;i >= l;i--) #define mem(x) memset(x,0,sizeof(x)) #define eps 1e-8 using namespace std; const int maxn = 50050; const ll inf = 1e9; const ll mod = 998244353; ll read() { ll x=0,f=1; char ch=getchar(); while(!(ch>='0'&

https://zoj.pintia.cn/contests/91827364639/problems C 要把这两个二进制串变为相同，需要先看哪些位置不同，设为数组c，某位为1则两位不同。 分1形成两段、四段或者更多段来考虑。 #include <iostream> #include <cstdio> #include <string> #include <cstring> #include <algorithm> #include <cmath> #include <stack> #include <vector> #include <set> #include <cmath> #include <queue> #include <map> #define ll long long #define ld double #define lson rt << 1, l, m #define pi acos(-1) #define rson rt << 1 | 1, m + 1, r #define fo(i, l, r) for (long long i = l; i <= r; i++) #define fd(i, l, r) for (long long i = r; i >= l; i--) #define mem(x) memset(x, 0, sizeof(x))

目录 do...while循环 for循环 break与continue 除了while循环外，C语言中还提供了do...while及for循环另外两种循环语句 do...while循环 do...while循环的语法为： do { 循环体语句; }while(条件表达式); 使用do...while打印0到9： #include <stdio.h> int main(int argc, char* argv[]) { int i = 0; do { printf("%d\r\n", i); i++; } while (i < 10); return 0; } for循环 for循环的基本语法结构： for(语句1;语句2;语句3) { 循环体语句 } 其中 语句1为for循环开始前会执行的初始化语句 语句2为每次循环开始前，用作判断循环是否继续的条件表达式 语句3为每次循环结束后（下一次循环是否执行判断前）要执行的语句，一般用于步进 使用for循环打印0到9： #include <stdio.h> int main(int argc, char* argv[]) { int i = 0; for (i = 0; i < 10; i++) { printf("%d\r\n", i); } return 0; } for循环中的语句1-3并不要求一定存在

BMW ICOM A2+B+C is upgrade of BMW ICOM, ICOM A2 is Second generation of BMW ISTA Diagnose and programming system. Support both new and old BMW vehicles. BMW ICOM A2 : Software Version : 2016.07 ISTA/D (ISID /DiagnosticISTA-D 3.55.31 ISTA-P 3.59.0.600 VIN: 2016.06.15 BMW ICOM : 1. Support Multi-language: American English, British English, German, Spanish, French, Italian, Polish, Portuguese, Turkish, Czech, Swedish, Dutch, Indian, Greek, Russian, Japanese, Korean, Thai, Simplified Chinese and Traditional Chinese 2. Hardware Version: ICOM Application-01.40.05 3. Support Vehicles: BMW Cars, BMW

BMW ICOM A2+B+C is upgrade of BMW ICOM, ICOM A2 is Second generation of BMW ISTA Diagnose and programming system. Support both new and old BMW vehicles. BMW ICOM A2 : Software Version : 2016.07 ISTA/D (ISID /DiagnosticISTA-D 3.55.31 ISTA-P 3.59.0.600 VIN: 2016.06.15 BMW ICOM : 1. Support Multi-language: American English, British English, German, Spanish, French, Italian, Polish, Portuguese, Turkish, Czech, Swedish, Dutch, Indian, Greek, Russian, Japanese, Korean, Thai, Simplified Chinese and Traditional Chinese 2. Hardware Version: ICOM Application-01.40.05 3. Support Vehicles: BMW Cars, BMW

错误消息： 2019-10-08 14:48:16.703 WARN o.s.s.o.p.c.JdbcClientDetailsService : Could not decode JSON for additional information: BaseClientDetails [clientId=clientIdPassword, clientSecret=$2a$11$jOA21o3tg9FO.nUVIsurbO3JzMj/yr8kw9p741siUNzEkRtuq9DyG, scope=[read, write, trust], resourceIds=[], authorizedGrantTypes=[password, authorization_code, refresh_token], registeredRedirectUris=[http://www.baidu.com/], authorities=[ROLE_USER], accessTokenValiditySeconds=7200, refreshTokenValiditySeconds=5184000, additionalInformation={}] java.io.EOFException: No content to map to Object due to end of input at

上2篇给了详细API 设计，下面我们来模拟测试下： Quinella： self.bet_type = "Quinella" self.nraces = 1 self.horse_ids.append([1,2,4,5,6,8,9]) self.user_odds.append([2.0,4.2,4.2,5.5,5.9,"-",11.0]) self.tab_odds.append([3.9,7.2,4.2,5.5,5.9,"-",11.0]) # Strategy self.scale_tab = 0 self.scale_user = 0 self.user_div_range = (1,20) #self.tab_div_range = (5,1000000) self.overlay = False self.overlay_var = 100 self.percent_by_number = 100 self.stake=0.5 self.outlay_amount=50. self.flat_stakes=False self.takeout = 200. self.rounding="Nearest" self.tabodds1 = (1,5.) self.tabodds2 = (1,10.) Here is the output: 2 42.5 (1, 2) 15

A 矩阵树定理可以用于最小生成树计数，最直观的做法就是求个mst，再用矩阵树定理求最小生成树个数，但是n<=1e5，显然不是o(n^3)可以做出来的。 考虑随机数据生成器，固定1e5的边，但是边权在unsigned long long的范围内随机指定，由样例看出，即使是点数很少的情况下，最多也只有一个生成树 于是，我们猜测，只需要做一遍最小生成树，并假定不会有更多的生成树就可以了。 #include<bits/stdc++.h> #define ull unsigned long long using namespace std; const int maxn = 100050; const ull mod = 1000000007; int f[maxn]; int findf(int x){ return f[x] == x ? x : f[x] = findf(f[x]); } int n,m; ull k1,k2; struct edge{ int u; int v; ull w; friend bool operator < (edge a,edge b){ return a.w < b.w; } }e[maxn]; ull xorS(){ ull k3 = k1,k4 = k2; k1 = k4; k3 ^= k3 << 23; k2 = k3 ^ k4 ^ (k3 >