firebug

Random Blocking with Javascript-File?

两盒软妹~` 提交于 2019-12-06 07:49:35
There is an example of javascript blocking from Steve Souders from his Book 'High Performance Web Sites': http://stevesouders.com/hpws/js-blocking.php Javascripts don't block Downloads anymore, but still do block rendering. .. but there is a strange download activity: There are 5 parallel downloads (max 6 are possible in Firefox 3 or IE 8 from the same server/host) 4 Images (2 from host1, 2 from host2) 1 Javascript in between there is also a 5th image in the page, but the loading of this fifth image does not occure in parallel, but only after Javascript has finished loading. so why does that

Why would javascript eval work in chrome, safari, but in firefox only when firebug on?

怎甘沉沦 提交于 2019-12-06 07:25:08
Thanks to this answer I was able to get javascript to execute when being loaded via an ExtJS AJAX call. However, the following code does not work the same in all browsers (on mac): chrome: works, alert pops up safari: works, alert pops up firefox: works, but only when Firebug is enabled , when Firebug is not enabled, the script is ignored How can I get javascript to execute via AJAX call in Firefox without having Firebug installed? Ext.onReady(function(){ var menuItemStart = new Ext.Panel({ id: 'panelStart', title: 'Start', html: 'This is the start menu item.', cls:'menuItem' }); var

Install Firebug Extension Manually

北战南征 提交于 2019-12-06 05:54:12
I want to install Firebug manually and update configuration settings on my own. I followed below steps: Downloaded firebug-2.0b1.xpi file (3 MB) Extracted the content by using winRAR. put this extracted folder "firebug-2.0b1" inside " C:\Program Files\Mozilla Firefox\extensions " Now, I run Firefox, but It seems firebug is not installed. This doens't work because some configurations are not done or Profile is not updated. I could like to know if any changes I need to do in folder. I am doing this because, I couldn't install by drag & drop .xpi file on firefox or install through browser itself.

Using FireBug for a website with frames

て烟熏妆下的殇ゞ 提交于 2019-12-06 04:11:24
I downloaded Firebug and attempted to use it to debug JS for a site that uses frames. My understanding is when I go to the Script tab in Firebug, I would see the JS functions on the aspx and the JS in any files that are included and I would be able to set breakpoints. However, all I see on this site is: </head> <frameset> <frame src="../company/HostPage.aspx name="mainFrame"> <noframes></noframes> </frameset> </html> Am I understanding Firebug correctly? There are two menu strips in Firebug. When you select the "Script" tab, above that is a menu strip that contains the name of the current file

firefox view source code

南笙酒味 提交于 2019-12-06 03:22:20
I noticed that the source code shown in Firefox appears to be incomplete. I have the latest version. When using the Firebug plugin to look at a webpage, I am able to find elements which are simply not recognized by Firefox. This is for a automated script I am working on. I am wondering several things: Why is a firefox plugin able to recognize elements Firefox is not? Is there a way to pass the source from Firebug engine to Firefox, or any other viable workaround which would enable Firefox to recognize all of the elements on the page? My guess is that these "hidden" elements have been created

Prevent logging of AJAX calls in console tab of Firebug like Twitter

£可爱£侵袭症+ 提交于 2019-12-06 02:52:13
问题 Need to know how i can prevent logging my AJAX calls in Firebug's Console tab, the way Twitter does. When you search in Twitter you get a live update feed saying "5 tweets since you searched". Twitter sends periodic AJAX calls for the live updates, however these AJAX calls do not get logged in Firebug's console tab, you will be able to see them if you switch to the Net tab of Firebug. Can someone tell me how does twitter achieve this because in my web application all the AJAX calls get logged

What's the RESTful way to check whether the client can access a resource?

浪尽此生 提交于 2019-12-06 01:42:00
问题 I'm trying to determine the best practice in a REST API for determining whether the client can access a particular resource. Two quick example scenarios: A phone directory lookup service. Client looks up a phone number by accessing eg. GET http://host/directoryEntries/numbers/12345 ... where 12345 is the phone number to try and find in the directory. If it exists, it would return information like the name and address of the person whose phone number it is. A video format shifting service.

js修改img的src属性刷新图片时的图片缓存问题

旧巷老猫 提交于 2019-12-06 00:13:01
问题:上传一张图片,通过js更新src属性刷新图片使其即时显示时, 当img的src当前的url与上次地址无变化时(只更改图片,名称不变,不同图片名称相同)图片不变化(仍显示原来的图片) 但通过firebug看图片已经变化,因为当src的地址不变时浏览器不会重新加载图片仍从缓存里面读取 方法:只需每次刷新图片时,改变一下src的地址内容就行了, (1)通过前台变化,让js每次生成一个随机数作参数放在url后边,但该参数没有实际意义 (2)每次请求到该图片页面时,从后台传一个随机数,前台获得该随机变量并放在url后边,该随机数也没有什么实际意义 原理: 由于在img的src中增加了随机数参数,多次访问图片时,浏览器认为是访问了不同的图片路径(或者说是访问了不同的图片), 浏览器会每次重新访问服务器读取图片, 而不再读取缓存中的图片。 Example: $("#empImgContent").attr('src', src=“**/uploads/empimgs/" + empObj.empPic+"?t=" + Math.random()); //显示图片 来源: oschina 链接: https://my.oschina.net/u/2519523/blog/1833940

Javascript infinite prototype chain

余生颓废 提交于 2019-12-05 20:33:31
问题 I am using the following test code: function Test() { } Test.prototype.MyMethod = { a: function() { }, b: function() { } } And to run it I'm simply doing: var test = new Test(); console.debug(test); In the firebug console, I expand the object that was printed and look inside of __proto__ : In there find a seemingly unending chain of constructor -> prototype: +MyMethod -constructor -prototype +MyMethod -constructor -prototype +MyMethod -constructor and so on. Did I do something wrong here? Why

How to dock Firebug in browser window?

本秂侑毒 提交于 2019-12-05 20:08:24
问题 How to dock Firebug in browser window after I opened in a new window? With Firefox 3.0.8 and Firebug 1.3 on Mac OS X 10.5 I can't get it docked in the browser window back. :( 回答1: How to fix the problem Background: firefox 10.0.10 Steps: Close Firebug if you have it open -> Go to Firefox menu -> select the "Web developer" option -> select "Firebug" from all the options listed -> Select "Firebug UI location" from all the options -> Choose Top, Button, Left or Right depending on your preference