facebook-like

Main Question: When I sent a GET request to retrieve data of someID/POSTS, like https://graph.facebook.com/microsoft/posts?fields=comments,likes&limit=1&access_token= , cannot get the "count" in "likes" and "comments" fields using the access token generated by my own facebook registered app, but can get the expected data if using the access token from Facebook Sample apps, e.g. " HelloFacebookSample ". This issue occurs on both Android and FB Graph API Exploer. Also in oder to troubleshoot the possible causes, I used the exactly same codes as FB sample under my registered app_id, but the same

We are having a problem with our facebook like/send button, if you open: http://apps.facebook.com/bymii-test/products.php?pageid=216605071714962&prd_id=35&prd_name=Coalesce : - click facebook send, the box is behind the facebook sidebar. Is there any way to: change the z-index - or to make the window pop up on the left? I FINALLY FOUND THE ANSWER!! 1 1/2 Hours searching later.. just enter this code into your CSS file: .fb_edge_widget_with_comment span.fb_edge_comment_widget { top: 15px !important; left: -250px !important;} Hope this is what you were looking for, because it was exactly what I

Hi friends I have an one issue, how to likes a page in Facebook from my application?? I am able to retrieve all the information of Facebook page using page id, also i am able to comment to the page wall, my requirement is that would be able to likes a page in Facebook which i am unable to do..??.I have gone through graph API but unable to find solution..?? I tried this code dialog = ProgressDialog.show(MyApp.this, "", "please wait..", true, true); Bundle params = new Bundle(); mAsyncRunner.request("PAGE_ID/likes",params,"POST",new UploadListener(), null); public class UploadListener implements

I have applied the Facebook like button on a page where I am displaying all the post from my WordPress admin. I applied the Facebook like button code, and it is working fine here, but when user clicks on the post, that post is getting open in FancyBox where I am applying the Facebook like button , but the Facebook like button is not getting created there. How can I do this? This is the code I am using to create the Facebook like button at both places: <div id="fb-root"></div> <script> (function(d, s, id) { var js, fjs = d.getElementsByTagName(s)[0]; if (d.getElementById(id)) return; js = d

Is it possible that a user using android application can like that application page created in Facebook from application itself? Yes. Just create a Layout with a WebView Like <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical"> <WebView android:id="@+id/webview" android:layout_width="fill_parent" android:layout_height="fill_parent" /> </LinearLayout> Create a activity Like.class WebView webview; Then add the following at the end of

window.fbAsyncInit = function() { FB.init({ appId : '********', // App ID channelUrl : document.location.protocol + '//connect.facebook.net/en_US/all.js', // Channel File status : true, // check login status cookie : true, // enable cookies to allow the server to access the session xfbml : true // parse XFBML }); var fql_query = "SELECT uid FROM page_fan WHERE page_id = "+page_id+"and uid="+user_id; FB.Data.query(fql_query).wait(function(rows) { if (rows.length == 1 && rows[0].uid == user_id) { console.log("LIKE"); $('#container_like').show(); } else { console.log("NO LIKEY"); $('#container

How is this done? I've seen some iframe content which was either hidden - in which case a graphic pointing up and saying something to the effect of "like us..." - or an offer - for example a discount available to the viewer if the page is "liked". I've dug around for this, but haven't had any luck. It's been done, but I didn't have the foresight to note which FB pages were doing it.... argh! You will need a Facebook application in order to achieve this. Once you have set that up, create your page and when the page loads, the user will need to authorise your application so that you can get