expression

Build Lambda Expressions with Contains

馋奶兔 提交于 2020-08-26 00:04:51
问题 I have a problem converting simple linq query to Lambda Expression. My queries look like this: int[] array = List<int> array2 = sql.OfType<Table1>().Select(x=>x.ID).Take(10).ToList(); var result = sql.OfType<Table1>().Where(x => array.Contains(x.ID)).Take(10).ToList(); and the final result should be: static void DynamicSQLQuery<T>(IQueryable<T> sql, string fieldName) { List<int> array = sql.OfType<T>().Select(SelectExpression<T>(fieldName)).Take(10).ToList(); var result = sql.OfType<T>()

how can i store and reuse pieces of my lambda expressions

自古美人都是妖i 提交于 2020-08-22 09:36:30
问题 I have a block of code where a piece of the lambda expression is used again and again. How can store this logic so that i can reuse this expression piece? Eg: lets take the example of the code given below Session.Query<DimensionGroup>()(dimgroup=>(dimgroup.Users.Where(map => ((map.User.Key == _users.PublicUser.Key || map.User.Key == _users.CurrentUser.Key) && map.AccessLevel.ToAccessLevel() == AccessLevel.Write)).Count() > 0)); (map.User.Key == _users.PublicUser.Key || map.User.Key == _users

Spring cron expression for every after 30 minutes

眉间皱痕 提交于 2020-07-31 06:24:54
问题 I have following Spring job to run after every 30 minutes. Please check my cron expression, is that correct? "0 0 0 * * 30" Here is a full cron job definition from the related Spring configuration file: <bean id="autoWeblogPingTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean"> <property name="jobDetail" ref="jobDetailForWeblogPing"/> <!-- run every 35 minutes --> <property name="cronExpression" value="0 0 0 * * 30" /> </bean> 回答1: According to the Quartz-Scheduler

Spring cron expression for every after 30 minutes

时光毁灭记忆、已成空白 提交于 2020-07-31 06:24:20
问题 I have following Spring job to run after every 30 minutes. Please check my cron expression, is that correct? "0 0 0 * * 30" Here is a full cron job definition from the related Spring configuration file: <bean id="autoWeblogPingTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean"> <property name="jobDetail" ref="jobDetailForWeblogPing"/> <!-- run every 35 minutes --> <property name="cronExpression" value="0 0 0 * * 30" /> </bean> 回答1: According to the Quartz-Scheduler

How to assign values for a list of some objects defined as variable with Spring Expression Language(Or the other expression languages you aware of)

喜你入骨 提交于 2020-07-23 02:41:40
问题 In Spel, it is easy to assign some values for a List property. For example having object foo with a property defined as List, I usually do: SpelParserConfiguration config = new SpelParserConfiguration(true,true); ExpressionParser parser = new SpelExpressionParser(config); Foo foo = new Foo(); EvaluationContext context = new StandardEvaluationContext(foo); parser.parseExpression("barList[1].test='11111111'") .getValue(context); But what do you do for the case you want to assign values for a