dynamic-programming

Property file not reflecting the modified changes using Apache Commons Configuration

末鹿安然 提交于 2019-12-10 11:42:28
问题 I am trying to explore Apache commons configuration to dynamically load the property file and do modification in the file and save it. I wrote a demo code for the same. Code Snippet package ABC; import org.apache.commons.configuration.ConfigurationException; import org.apache.commons.configuration.PropertiesConfiguration; import org.apache.commons.configuration.reloading.FileChangedReloadingStrategy; public class Prop { public static void main(String[] args) { try { URL propertiesURL = Prop

javascript making change algorithm

别说谁变了你拦得住时间么 提交于 2019-12-10 11:38:59
问题 I'm solving this problem "Making change" in javascript: Question: Given an amount of money, an array of coin denominations, compute the number of ways to make the amount of money with coins of the available denominations. Example: For amount=4 (4¢) and denominations=[1,2,3] (1¢, 2¢ and 3¢), your program would output 4—the number of ways to make 4¢ with those denominations: 1¢, 1¢, 1¢, 1¢ 1¢, 1¢, 2¢ 1¢, 3¢ 2¢, 2¢ I found a solution: var makeChange = function(total){ var count = 0; var coins =

A dance with an aglorithm's complexity

烈酒焚心 提交于 2019-12-10 11:36:20
问题 I am about to take part in a dance contest and tomorrow is the big day! I know apriori the list with the n songs of the contest and their order. After much scouting, I was able to determine the judges and my skills so good that I can accurately predict my result if I dance the i-th song of the list, i.e. score(i) . However, after the i-th song, I need time to rest, namely I cannot dance the next rest(i) songs, i.e. songs i + 1, ..., i + rest(i). No other constraint exists for the number of

Coin Change (Dynamic Programming)

跟風遠走 提交于 2019-12-10 11:33:54
问题 We usually the following recurrence relation for the coin change problem: ( P is the total money for which we need change and d_i is the coin available) But can't we make it like this: ( V is the given sorted set of coins available, i and j are its subscripts with Vj being the highest value coin given) C[p,Vi,j] = C[p,Vi,j-1] if Vj > p = C[p-Vj,Vi,j] + 1 if Vj <=p Is there anything wrong with what I wrote? Though the solution is not dynamic but isn't it more efficient? 回答1: Consider P = 6, V

Can I avoid Python loop overhead on dynamic programming with numpy?

风流意气都作罢 提交于 2019-12-10 10:56:56
问题 I need help with the Pythonic looping overhead of the following problem: I'm writing a function that calculates a pixel flow algorithm that's a classic dynamic programming algorithm on a 2D Numpy array. It requires: 1) visiting all the elements of the array at least once like this: for x in range(xsize): for y in range(ysize): updateDistance(x,y) 2) potentially following a path of elements based on the values of the neighbors of an element which looks like this while len(workingList) > 0: x,y

Algorithm for Filling bag maximally (this is not the knapsack 0/1)

久未见 提交于 2019-12-10 10:34:29
问题 I am working on some task which requires from me to solve the following algorithmic problem: - You Have collection of items (their weights): [w1, w2, ..., wn] - And You have a bag which weight is: W - It is Needed to fill the bag maximally (fill as much as possible) with the subset of given items. So this is not "Knapsack 0/1" problem, as we deal only with weights (we have only one parameter for item). Therefore I assume that it might have a solution (Knapsack is NP-complete) or some kind of

What's time complexity of this Algorithm for breaking words? (Dynamic Programming)

萝らか妹 提交于 2019-12-10 10:32:33
问题 Word Break (with Dynamic Programming: Top->Down) Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example , given s = "catsanddog", dict = ["cat", "cats", "and", "sand", "dog"]. A solution is ["cats and dog", "cat sand dog"]. Question: Time complexity ? Space complexity ? Personally I think, Time complexity = O(n!), without Dynamic Programming, n is the length of the

Is there any algorithm to address the longest common subsequent problem with different weights for each character?

荒凉一梦 提交于 2019-12-10 10:29:26
问题 I'm looking for an algorithm that addresses the LCS problem for two strings with the following conditions: Each string consists of English characters and each character has a weight. For example: sequence 1 (S1): "ABBCD" with weights [1, 2, 4, 1, 3] sequence 2 (S2): "TBDC" with weights [7, 5, 1, 2] Suppose that MW(s, S) is defined as the maximum weight of the sub-sequence s in string S with respect to the associated weights. The heaviest common sub-sequence (HCS) is defined as: HCS = argmin

formulation of general dynamic programming problem

一世执手 提交于 2019-12-10 10:16:23
问题 I wonder if the objective function of a general dynamic programming problem can always be formulated as in dynamic programming on wiki, where the objective function is a sum of items for action and state at every stage? Or that is just a specical case and what is the general formulation? EDIT: By "dynamic programming problem", I mean a problem that can be solved by dynamic programming technique. Such kind of problems possess the property of optimal problem and optimal structure. But at lease

Largest Empty Rectangle Within a Rectangle

青春壹個敷衍的年華 提交于 2019-12-10 10:09:27
问题 I'm not really good in maths, so I'm having really hard times converting formulas into code, and I can't find anything ready-made googling around. I have a big rectangle containing a lot of small rectangles... and all what I need to do is to calculate the largest empty rectangle. Anyonne can help me? Here is what I came up with... nothing to say, it's a big fail. Rect result = new Rect(); for (Double l = 0; l < bigRect.Width; ++l) { for (Double t = 0; t < bigRect.Height; ++t) { Double h = 0;