division

问题 If I have a 64 bit number in the EDX-EAX , and I divide it with a relatively small number, the quotient may become a number bigger than 32 bits . So at that point the div operator only sets the carry flag ? My problem is, that I would like to process a number in the EDX-EAX and write it out digit per digit , so in this case I would have to divide the number in EDX-EAX by 10 to get the last digit. 回答1: No. DIV in 64b/32b has maximum quotient 2 32 -1. Overflow is indicated with the #DE (divide

问题 I try to divide 32 bit number in 16 bit number. For example 10000000h divide by 2000h.According the desgin I try to do I divide 4 right digits with the divisor and then the 4 left digit by the divisor. This is my code : .DATA num dd 10000000h divisor dw 2000h result dd ? remainder dw ? .CODE main: mov ax,@DATA mov ds,ax xor dx,dx mov cx ,word ptr divisor mov bx,offset num mov ax,[bx] div cx mov bx,offset result mov [bx],ax mov bx,offset num mov ax,[bx+2] mov ax,[bx+2] div cx mov bx,offset

问题 As stated in the title, why does the ARM instruction set distinguish between signed and unsigned only on division? SDIV and UDIV are available but that's not the case with ADD, SUB and MUL. 回答1: addition and subtraction of signed and unsigned numbers of the same size produce exactly the same bit patterns in two's complement math (which ARM uses), so there is no neeed for separate instructions. for example if we take byte-sized values: 0xFC +4 signed: -4+4 = 0 unsigned: 252 +4 = 256 = 0x100 =

问题 I have two numbers I want to divide: 5262167 / 162333331 When verified using windows calculator (calc.exe) the result is 0.0324158136076195 but when used simple select with CAST function in SQL Server 2008R2 I don't have same result. Here is what I'm running in SQL editor: select CAST((5262167 / 162333331) as decimal(18,8)) and the result is 0.00000000 回答1: You're doing integer division, which will truncate any remainders. 5262167 < 162333331, so your result is 0. Cast your input before

问题 In one of my assignments I came across a weird implementation, and I was curious if it's a bug or the designed behavior. In Python 3, division by / returns a floating point number, and // means integer division and should return an integer. I've discovered though that if either of the values is a float when doing integer division, it will return a float. Example: # These all work as expected 10 / 2 -> 5.0 11 / 2 -> 5.5 10 // 2 -> 5 11 // 2 -> 5 # Here things start to get weird 10.0 // 2 -> 5

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 5 years ago . I understand that in Java, if i divide two integers together, if the result isn't an integer, the fractional part is truncated and I get an integer result from the division. This never made sense to me! I'm wondering if i could get some insight into why Java is designed to do

问题 This question already has answers here : python 3.1.2 gives wrong output when dividing two large numbers? (3 answers) Closed 6 months ago . In my program, I'm using division to test if the result is an integer, I'm testing divisibility. However, I'm getting wrong answers. Here is an example: print(int(724815896270884803/61)) gives 11882227807719424. print(724815896270884803//61) gives the correct result of 11882227807719423. Why is the floating point result wrong, and how can I test whether

问题 I am unsure of what the cbw command actually does. I have a snippet of code: mov ax,0FF0h cbw idiv ah How does the value of ax change after cbw? 回答1: The cbw instruction sign-extends a byte into a word. In this case, it'll take the sign bit of AL (which happens to be 1) and copy it into every bit of AH . This means that the two's-complement value of AX will be the same, but the binary representation will be different. The value of AX after the cbw instruction will be FFF0h (a 16-bit -16 value

问题 I've run into an odd problem with this code: legibIndex = 206.385 - 84.6 * (countSylb / countWord) - 1.015 * (countWord / countSent); This is the calculation for the legibility index of a given text file. Since this is a homework assignment, we were told what the Index should be (80, or exactly 80.3) My syllable count, word count, and sentence count are all correct (they match up with the given numbers for the sample textfiles. Even if I hardcode the numbers in, I do not get 80, even though I

问题 I want to divide a bigdecimal value with an integer.i have rounded the bigdecimal value(if it is 133.333 then rounded value is 133).given below is my code snippet. v1 = v1.setScale(0, RoundingMode.HALF_UP); int temp = BigDecimal.valueOf(v1.longValue()).divide(constant1); value of constant is 12. It is showing an error message that The method divide(BigDecimal) in the type BigDecimal is not applicable for the arguments (int) Can anyone help me to do the division? 回答1: Change .divide(constant1)