division of bigdecimal by integer

问题

I want to divide a bigdecimal value with an integer.i have rounded the bigdecimal value(if it is 133.333 then rounded value is 133).given below is my code snippet.

v1 = v1.setScale(0, RoundingMode.HALF_UP);
int temp = BigDecimal.valueOf(v1.longValue()).divide(constant1);

value of constant is 12. It is showing an error message that

The method divide(BigDecimal) in the type BigDecimal is not applicable for the arguments (int)

Can anyone help me to do the division?

回答1:

Change

.divide(constant1);

to

.divide(new BigDecimal(constant1));

---

Btw, why don't you just do something like

int temp = (int) (Math.round(v1.doubleValue()) / constant1);

??

回答2:

You should write the code as follows:

int temp = BigDecimal.valueOf(v1.longValue())
        .divide(BigDecimal.valueOf(constant1)).intValue();

The thing about BigDecimal and BigInteger is that they mostly operate with instances of these classes and not with primitive types. Results of operations are also new instances of these classes.

One other remark: I advise to use valueOf static method instead of a constructor, because by doing this you may have a possibility to avoid creation of new objects. Using a constructor makes creation of a new object explicit, which is not necessary in this case at all.

来源：https://stackoverflow.com/questions/7819553/division-of-bigdecimal-by-integer