division

问题 Assume the following code: mov eax, 0 sub eax, 2 xor edx, edx idiv base where base equals to 8 (defined as const int base = 8 ). As a result, I expect to get 0 in eax and 2 (or −2) in edx . However, the result of the division is a big long number. Most likely, it is caused by overflow in eax registry, when I subtract 2 from it. I think eax is interpreted by idiv operation as unsigned int . How do I perform this division properly? I code in Visual Studio 2013 on x64 system. 回答1: The usual

问题 This question already has answers here : Is floating point math broken? (31 answers) Closed 6 years ago . I am dividing a number( may be in amount format of XX.XX) by a integer. But when i do 6.6 / 6 or 3.3/3 , it gives 1.099999... , instead of 1.1. What i am doing is, I am dividing the amount equally among the number of people and if any remainder amount exists, I am adding that extra amount to one person among them. May be something of this kind, 104/6 will be divided as 17.85, 17.83, 17.83

问题 I am using this struct to represent 128bit integers: typedef struct { uint64_t low, high; } uint128; (Unless you can point me to a fast 128bit integer library I can not change that) Now I want to print such a value in base 10, using printf . I probably need division by 10 to do that, but no division is implemented yet. How can I do this? The solution does not have to be super efficient, as long as it works. EDIT: I like all solutions you came up with. You are awesome. 回答1: void printu128

问题 I am doing a calculation with an array which is drawn from mysql and the problem is "division by zero" warning I am running a loop over this statment $v = (($v - $valuei)/($valuei) * 100); Here $v is is changing (let's say from 100 to 150 e.g 100, 101, 102, 103,...,150) and $valuei is the intial value of $v (i.e 100) So, when the calculation will start first output should be zero and I want that zero then why it gives a warning "Division By Zero " and also makes all the "$v" values equal to

问题 I've just started with pandas some weeks ago and now I am trying to perform an element-wise division on rows, but couldn't figure out the proper way to achieve it. Here is my case and data date type id ... 1096 1097 1098 0 2014-06-13 cal 1 ... 17.949524 16.247619 15.465079 1 2014-06-13 cow 32 ... 0.523429 -0.854286 -1.520952 2 2014-06-13 cow 47 ... 7.676000 6.521714 5.892381 3 2014-06-13 cow 107 ... 4.161714 3.048571 2.419048 4 2014-06-13 cow 137 ... 3.781143 2.557143 1.931429 5 2014-06-13

问题 I wrote a program to divide large numbers using strings in C++. That is a string is used to store each digit of the number. I used continuous subtraction to get the remainder and quotient. For ex: 16/5 Subtract 16-5=11 11-5=6 6-5=1 1 is less than 5 so stop quotient = 3 and remainder = 1 But the problem is this method is extremely slow for very large numbers. What other possible method is there to make it fast? 回答1: One approach to get fast bignum computation is to use high values for the base

问题 I'm trying to divide 859091 by 11 to obtain the quotient and the remainder, but I'm getting Floating Point Exception on line: div bx This is my code for SASM : %include "io.inc" section .data dividend dd 859091 divisor dw 11 section .text global CMAIN CMAIN: push ebp mov ebp, esp xor eax, eax xor ebx, ebx xor edx, edx mov ax, word [dividend] mov dx, word [dividend + 2] mov bx, word [divisor] test bx, bx jz exit div bx exit: leave ret 回答1: You're getting divide overflow because the quotient

问题 How can I find whether the input is even or odd in MIPS? I am trying to find out using integer registers, but my program is not working. Here is the code: li $s1,2 div $s0,$s1 mfhi $t0 xor $t1,$t0,$0 beq $t1,0,Even j Odd But this program shows even odd numbers as even this is because the result is in decimal like 0.3 . How can I solve this issue? 回答1: You need to and the number which you want to check with 0x01 . This is how you use and in mips: and $d, $s, $t If the value in target register

问题 Im currently working on the cs50 "cash" problem: estimating the amount of coins needed to pay some change. ex: $0.41 owed = 1 quarters, 1 dime, 1 nickel, 1 penny. however, when estimating the amount of coins needed i end up being off with the pennies i believe is due to error on my part as it always seems to be off by one or 2 coins (pennies). I have included multiple printf statement to try and track what i could be doing but i can't seem to figure out why the division isn't working.

问题 I'm learning Haskell and stuck trying to understand the type system. I'm trying to write a function which returns the length of the series 'Half or Three Plus One' for an input. Here's my attempt at the function, using a recursive approach (the function is valid for integral inputs only): hotpo :: (Integral a) => a->a hotpo n = hotpoHelper n 1 hotpoHelper:: (Integral a) => a->a->a hotpoHelper 1 n = n hotpoHelper num count | even num = hotpoHelper (truncate (num/2)) (count+1) | otherwise =