division

问题 Why when I do: select CAST(1 AS DECIMAL(38, 28))/CAST(1625625 AS DECIMAL(38, 28)) Do I get 0, but when I do select CAST(1 AS DECIMAL(20, 10))/CAST(1625625 AS DECIMAL(20, 10)) I get a value? I would have expected the higher precision division to return a higher precision result, why is this not the case? 回答1: This happens because for math operations the resulting precision and scale is calculated with the rules found in http://msdn.microsoft.com/en-us/library/ms190476.aspx#division operation

问题 I have a number, for instance 10 . I want to split this number in 5 integers using something like this: foo <- function(x, n) rep(x/n, n) foo(10, 5) [1] 2 2 2 2 2 This works until x is not a mutliple of n : foo(10, 3) [1] 3.333333 3.333333 3.333333 In this case I woud like an output like. [1] 3 4 3 # the order doesn't matter. The difference between each integer have to be minimal. So this result is not allowed: [1] 2 5 3 So far I'm using this function, but not sure whether this is always

问题 I'd like division to return 0. for 0./0. instead of NaN or an error in a tensorflow application. I know how I can do this in numpy [1], [2], but I'm new to tensorflow. How can this be achieved? 来源： https://stackoverflow.com/questions/45466142/tensorflow-divide-with-0-0-0

问题 How can i check number is divisible by particular number or not both numbers are decimal. with decimal point value of two digits. i had tried with below (((dn / size) % 1) == 0) but in some cases it not provide proper out put. how can i resolve it. here i put some example values like double dn = 369.35,369.55.370.55 and size may be 0.05,0.10,0.5 etc... if(((dn / size) % 1) == 0) { Log.d(TAG,"OK"); } else { Log.d(TAG,"OK"); } please help me to short out it. 回答1: (dn / size) % 1 == 0 whilst

问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: Python float - str - float weirdness Python float division does not appear to have accurate results. Can someone explain why? >>>3.0/5 0.59999999999999998 回答1: Short answer: Floats use finite-precision binary encoding to represent numbers, so various operations lose some precision. The Wikipedia page has a lot of information (maybe too much). See also: How do I use accurate float arithmetic in Python? 回答2:

问题 This one is really puzzling me. I am writing a damage algorithm with some random variation. When I calculate the variation this is what it looks like. Random random = new Random(); Double variation = random.Next(85, 115) / 100; Double damage = restOfAlgorithm * variation; When I do that, variation always outputs 0. However, if I do like below, it will output the expected result. Random random = new Random(); Double variation = random.Next(85, 115); Double damage = restOfAlgorithm * (variation

问题 Say i got two big numbers (defined below), and i want to implement division on them by falling back to x86 avaliable arithmetic 0008768376 - 1653656387 - 0437673667 - 0123767614 - 1039873878 - 2231712290 / 0038768167 - 3276287672 - 1665265628 C=A/B Those numbers are stored as vectors of 32 bit unsigned ints. First one, A, is 6-unsigned-int vector, B is 3-unsigned-int long vector [each of this field i name generalised 'digit' or 'field' on my own] The resulting C will be some 3-unsigned-int

问题 I am unable to understand why C++ division behaves the way it does. I have a simple program which divides 1 by 10 (using VS 2003) double dResult = 0.0; dResult = 1.0/10.0; I expect dResult to be 0.1, However i get 0.10000000000000001 Why do i get this value, whats the problem with internal representation of double/float How can i get the correct value? Thanks. 回答1: Because all most modern processors use binary floating-point, which cannot exactly represent 0.1 (there is no way to represent 0

问题 I've got two inputs in a div that I want to divide one by the other. <div> <input type="number" id="a"> / <input type="number" id="b"> <input type="submit"> <p class="result">RESULT HERE</p> </div> How can the maths of this be done with jquery? 回答1: It really depends when you want the calculation to take place, but the maths itself is incredibly simple. Just use the standard division operator, / : var num1 = $("input[label='a']").val(), num2 = $("input[label='b']").val(), result = parseInt

问题 The concept of binary division in MIPS has been explained in the Pattern's computer organization book. However, when I comes to the improved division algorithm, things are not very clear. Consider the following diagram. While it is talking about 32-bit integers, I want to know what are the register sizes for 1001010÷1000 ? Here is my understanding: Dividend: 1001010 which should be 8-bit 0100,1010 Divisor: 1000 which should be 8-bit 0000,1000 Now what about the registers in the diagram?