division

问题 An integer division caused by the elements of an array returns 0, I'm supposed to store the % in the same array.... array[6][i]=array[5][i]/total; This stores a 0... I thought it had something to do with the array being an integer array... so I did a cast... array[6][i]=(int)(array[5][i]/total); Still stored 0... I read I had to convert them to floating points but the casting doesn't work... I tried this array[6][i]=(int)((float)array[5][i]/(float)total); the array declaration int arreglo[7]

问题 As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references, or expertise, but this question will likely solicit debate, arguments, polling, or extended discussion. If you feel that this question can be improved and possibly reopened, visit the help center for guidance. Closed 6 years ago . i have the program written however I have two problems and need assistance to correct. the problems are 1) i do not want the counter i

问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: How to resolve a Java Rounding Double issue Please Help, I programm some calculator in Java. I use double type. Double has 15 digits after the decimal point. I have problem with the following: 1/3 * 3 = 0.9999999999999999 I need 1/3 * 3 = 1 How can I solve this problem? I keep result in Double. The same problem I have with other mathematical operations, for example sqrt(6) = 2.449489742783, and next I square the

问题 I want to order ascending a MySQL query by this rule: x-y/x x = price y = price2 price and price2 are the columns from the MySQL table. I have this query but unfortunately doesn`t work. SELECT * FROM albums WHERE price2 > 1 ORDER BY price - price2 / price ASC Thanks for attention. 回答1: try this out: $SQLquery = "SELECT * FROM albums WHERE price2 > 1 ORDER BY (price-price2)/price ASC"; or $SQLquery = "SELECT * FROM albums WHERE price2 > 1 ORDER BY ((price-price2)/price) ASC"; 回答2: You should

问题 #include<iostream> #include<iomanip> #include <math.h> using namespace std; int doIt(int a){ a=a/1000; return a; } void main(){ int myfav= 23412; cout<<"test: "+doIt(myfav); cin.get(); } just wondering why i am not getting a print out for this. Thanks in advance. 回答1: Using C++ streams, you should cout << "test: " << doIt(myfav) , rather than trying to + them together. I'm not sure off the top of my head whether << or + takes precedence, but regardless of whether you're adding to a stream or

问题 I am calculating the average of sixteen 64 bit numbers added together and I think that I have done all the addition correctly, but now I need to figure out how to divide a 64 bit number by 16 and I am stuck! Any help would be great thank you so much. Here is my code so far. tableSize EQU 16 sum EQU 0x40000000 average EQU 0x40000008 MOV r8, #14 ADR r0, table LDR r9, =sum LDR r10,=average LDR r1, [r0], #1 ;hi #1 LDR r2, [r0], #1 ;lo #1 SUM SUB r8, r8, #1 LDR r3, [r0], #1 ;hi #2 LDR r4, [r0], #1

问题 This question already has answers here : C program to convert Fahrenheit to Celsius always prints zero (8 answers) Closed 3 years ago . Im not getting correct answer with the following code below. Can anyone debug this code? When I input radius = 5, the answer I get is 500.000000 whereas the original answer should be 523.80952. Can anyone please explain what's wrong here? Sphere volume formula =4/3(π x r^3) #include <stdio.h> int main() { float radius = 0; float volume; float pie = 0; printf(

问题 So, for a very silly project in C++, we are making our own long integer class, called VLI (Very Long Int). The way it works (they backboned it, blame them for stupidity) is this: User inputs up to 50 digits, which are input as string. String is stored in pre-made Sequence class, which stores the string in an array, in reverse order. That means, when "1234" is input, it gets stored as [4|3|2|1]. So, my question is this: How can I go about doing division using only these arrays of chars? If the

问题 If this was previously talked about, I'm sorry, I had a hard time searching on this. I am calculating a depreciation rate. One portion of our calculation is 1/life in months. My table stores this data in a decimal field. I tried test = 1 / estimatedLife; but the result of the calculation of test (which is defined as a decimal ) is 0. Say the estimated life is 36 months. So 1/36 should equal 0.02777778. Any thoughts of what I am doing wrong? BTW, I changed the test to a double and had the same

问题 I'm trying to do some crosstabs in SQL Server 2008 R2. That part is alright, however, if I try to get percentages for each cell, I run into a problem. Here is a distilled use case: A survey where people give their favorite color and their favorite fruit. I'd like to know how many like a given fruit AND a given color: with survey as ( select 'banana' fav_fruit, 'yellow' fav_color union select 'banana', 'red' union select 'apple', 'yellow' union select 'grape', 'red' union select 'apple', 'blue