divide-by-zero

问题 Creating a lambda function to calculate weighted average and sending that to a dictionary. wm = lambda x: np.average(x, weights=df.loc[x.index, 'WEIGHTS']) # Define a dictionary with the functions to apply for a given column: f = {'DRESS_AMT': 'max', 'FACE_AMT': 'sum', 'Other_AMT': {'weighted_mean' : wm}} # Groupby and aggregate with dictionary: df2=df.groupby(['ID','COL1'], as_index=False).agg(f) This code works but the weighted average lambda function fails if the weights add up to 0

问题 Creating a lambda function to calculate weighted average and sending that to a dictionary. wm = lambda x: np.average(x, weights=df.loc[x.index, 'WEIGHTS']) # Define a dictionary with the functions to apply for a given column: f = {'DRESS_AMT': 'max', 'FACE_AMT': 'sum', 'Other_AMT': {'weighted_mean' : wm}} # Groupby and aggregate with dictionary: df2=df.groupby(['ID','COL1'], as_index=False).agg(f) This code works but the weighted average lambda function fails if the weights add up to 0

问题 In order to better understand Rusts panic/exception mechanisms, I wrote the following piece of code: #![feature(libc)] extern crate libc; fn main() { let mut x: i32; unsafe { x = libc::getchar(); } let y = x - 65; println!("{}", x); let z = 1 / y; println!("{}", z); } I wanted to check how Rust deals with division by zero cases. Originally I assumed it was either taking an unhandled SIGFPE to the face and dying or it implemented a handler and rerouted it to a panic (which can be dealt with

问题 I have the following data: a = pd.Series([1, 2, 3]) b = pd.Series([0, 0, 0]) If there is a division by zero I want to in some cases set the result to one of the series set the result to a specific value But the following give "unexpected" results: a.div(b, fill_value = 0) 0 inf 1 inf 2 inf a.div(b).fillna(0) 0 inf 1 inf 2 inf a.div(b).combine_first(a) 0 inf 1 inf 2 inf I want to arrive at: case 1 : set the data to a specific value 0 0 1 0 2 0 case 2 : set the value to a specific series 0 1 1

来源： https://stackoverflow.com/questions/64033464/how-to-produce-codes-that-always-trigger-signal-sigfpediv-by-zero

来源： https://stackoverflow.com/questions/64033464/how-to-produce-codes-that-always-trigger-signal-sigfpediv-by-zero

问题 Initially I declared variables x and y as type int: #include<stdio.h> int main(){ int x, y = 0 ; x = 1 / y; printf("%d", x); return 0; } Program crashed (for obvious reasons). Now I declared variables x and y as double: #include<stdio.h> int main(){ double x, y = 0 ; x = 1 / y; printf("%d", x); return 0; } But Output: 0. (why?) Then I changed %d to %f in printf: #include<stdio.h> int main(){ double x, y = 0 ; x = 1 / y; printf("%f", x); return 0; } Output: 1.#INF00 I don't understand what is

问题 Initially I declared variables x and y as type int: #include<stdio.h> int main(){ int x, y = 0 ; x = 1 / y; printf("%d", x); return 0; } Program crashed (for obvious reasons). Now I declared variables x and y as double: #include<stdio.h> int main(){ double x, y = 0 ; x = 1 / y; printf("%d", x); return 0; } But Output: 0. (why?) Then I changed %d to %f in printf: #include<stdio.h> int main(){ double x, y = 0 ; x = 1 / y; printf("%f", x); return 0; } Output: 1.#INF00 I don't understand what is

问题 This question already has answers here : Why does this method return double.PositiveInfinity not DivideByZeroException? (4 answers) Closed 2 years ago . Just threw together a simple test, not for any particular reason other than I like to try to have tests for all my methods even though this one is quite straightforward, or so I thought. [TestMethod] public void Test_GetToolRating() { var rating = GetToolRating(45.5, 0); Assert.IsNotNull(rating); } private static ToolRating GetToolRating

问题 According to C++ Standard (5/5) dividing by zero is undefined behavior. Now consider this code (lots of useless statements are there to prevent the compiler from optimizing code out): int main() { char buffer[1] = {}; int len = strlen( buffer ); if( len / 0 ) { rand(); } } Visual C++ compiles the if -statement like this: sub eax,edx cdq xor ecx,ecx idiv eax,ecx test eax,eax je wmain+2Ah (40102Ah) call rand Clearly the compiler sees that the code is to divide by zero - it uses xor x,x pattern