digits

问题 I've been using this site quite a lot but I've never really wrote anything. Today, I've stumbled upon a problem which solution I can't seem to find. The problem is that, I have an int variable with an unknown number of digits. It is asked of me to sum all of those digits and then have it printed/shown_as_a_message with all those digit separated. For example, the user enters the number "12345678" and in the end I need to have a message saying "The numbers 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36". I

问题 I am conducting a Bayesian analysis in R thorough "R2Winbugs" package. In the R output, teh estimated parameters are rounded. My question is how can I control this? Here is my command: bugs(data, inits=inits, model.file = "C:/Users/Gunal/Desktop/dummy/dummyw.txt", parameters, digits=5, n.chains = 3, n.iter = 1000, codaPkg = FALSE, bugs.directory = "D:/PROGRAMLAR/WinBUGS14/") and here is some part of my output mean sd 2.5% 25% 50% 75% 97.5% Rhat n.eff beta1 0.3 0.1 0.0 0.2 0.3 0.4 0.5 1.7 5

问题 Suppose I have the following input: 1234 How can I get the following output? 3412 This is obtained by circularly shifting (or rotating) the digits of the input twice. I have tried the following code: number = 1234 bin(number >> 1) but it is not producing the results I was expecting. 回答1: The >> operator does a binary bitshift. It moves the binary representation of 1234 on place to the right, discarding the rightmost (least significant) bit. Therefore you code does not result in 3412 . You

问题 I am new to Python. I am trying to adjust the format of a list which looks like below: data=[1,10,313,4000,51234,123456] and I would like to convert them to a list of strings with leading zeros: result=['000001','000010','000313','004000','051234','123456'] each of the element has 6 digits. I know for a single number X, I can do: str(X).zfill(6) but I am not sure how to apply this to a list. I would like to solve this problem without using a for loop. Anyone could help? Thanks. 回答1: Apply the

问题 I am new to Python. I am trying to adjust the format of a list which looks like below: data=[1,10,313,4000,51234,123456] and I would like to convert them to a list of strings with leading zeros: result=['000001','000010','000313','004000','051234','123456'] each of the element has 6 digits. I know for a single number X, I can do: str(X).zfill(6) but I am not sure how to apply this to a list. I would like to solve this problem without using a for loop. Anyone could help? Thanks. 回答1: Apply the

问题 I just started tinkering with Ruby earlier this week and I've run into something that I don't quite know how to code. I'm converting a scanner that was written in Java into Ruby for a class assignment, and I've gotten down to this section: if (Character.isLetter(lookAhead)) { return id(); } if (Character.isDigit(lookAhead)) { return number(); } lookAhead is a single character picked out of the string (moving by one space each time it loops through) and these two methods determine if it is a

问题 I am trying to count the number of digits of an input. However, whenever I input 10 or 11 or any two digit number, the output is 325 . Why doesn't it work? inputnumber = int(input()) countnumber = inputnumber digitcount = 0 while countnumber > 0: digitcount += 1 countnumber = countnumber/10 print(digitcount) # result is 325 when input is 10 or 11 回答1: Your error mainly happened here: countnumber=countnumber/10 Note that you are intending to do integer division. Single-slash division in Python

问题 I have been banging my head on this one all day. The C++ project I am currently working on has a requirement to display an editable value. The currently selected digit displays the incremented value above and decremented value below for said digit. It is useful to be able to reference the editable value as both a number and collection of digits. What would be awesome is if there was some indexable form of a floating point number, but I have been unable to find such a solution. I am throwing

问题 I am newbie. I want to make small app which will calculate the sum of all the digits of a number. For example, if I have the number 2568, the app will calculate 2+5+6+8 which is equal with 21. Finally, it will calculate the sum of 21's digits and the final result will be 3 . Please help me 回答1: Basically you have two methods to get the sum of all parts of an integer number. With numerical operations Take the number and build the remainder of ten and add that. Then take the integer part of the

问题 I am newbie. I want to make small app which will calculate the sum of all the digits of a number. For example, if I have the number 2568, the app will calculate 2+5+6+8 which is equal with 21. Finally, it will calculate the sum of 21's digits and the final result will be 3 . Please help me 回答1: Basically you have two methods to get the sum of all parts of an integer number. With numerical operations Take the number and build the remainder of ten and add that. Then take the integer part of the